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	/*
	* Copyright (c) 1997, 2021, Oracle and/or its affiliates. All rights reserved.
	* DO NOT ALTER OR REMOVE COPYRIGHT NOTICES OR THIS FILE HEADER.
	*
	* This code is free software; you can redistribute it and/or modify it
	* under the terms of the GNU General Public License version 2 only, as
	* published by the Free Software Foundation. Oracle designates this
	* particular file as subject to the "Classpath" exception as provided
	* by Oracle in the LICENSE file that accompanied this code.
	*
	* This code is distributed in the hope that it will be useful, but WITHOUT
	* ANY WARRANTY; without even the implied warranty of MERCHANTABILITY or
	* FITNESS FOR A PARTICULAR PURPOSE. See the GNU General Public License
	* version 2 for more details (a copy is included in the LICENSE file that
	* accompanied this code).
	*
	* You should have received a copy of the GNU General Public License version
	* 2 along with this work; if not, write to the Free Software Foundation,
	* Inc., 51 Franklin St, Fifth Floor, Boston, MA 02110-1301 USA.
	*
	* Please contact Oracle, 500 Oracle Parkway, Redwood Shores, CA 94065 USA
	* or visit www.oracle.com if you need additional information or have any
	* questions.
	*/

	package java.util;

	import jdk.internal.util.ArraysSupport;
	import jdk.internal.vm.annotation.IntrinsicCandidate;

	import java.io.Serializable;
	import java.lang.reflect.Array;
	import java.util.concurrent.ForkJoinPool;
	import java.util.function.BinaryOperator;
	import java.util.function.Consumer;
	import java.util.function.DoubleBinaryOperator;
	import java.util.function.IntBinaryOperator;
	import java.util.function.IntFunction;
	import java.util.function.IntToDoubleFunction;
	import java.util.function.IntToLongFunction;
	import java.util.function.IntUnaryOperator;
	import java.util.function.LongBinaryOperator;
	import java.util.function.UnaryOperator;
	import java.util.stream.DoubleStream;
	import java.util.stream.IntStream;
	import java.util.stream.LongStream;
	import java.util.stream.Stream;
	import java.util.stream.StreamSupport;

	/**
	* This class contains various methods for manipulating arrays (such as
	* sorting and searching). This class also contains a static factory
	* that allows arrays to be viewed as lists.
	*
	* <p>The methods in this class all throw a {@code NullPointerException},
	* if the specified array reference is null, except where noted.
	*
	* <p>The documentation for the methods contained in this class includes
	* brief descriptions of the <i>implementations</i>. Such descriptions should
	* be regarded as <i>implementation notes</i>, rather than parts of the
	* <i>specification</i>. Implementors should feel free to substitute other
	* algorithms, so long as the specification itself is adhered to. (For
	* example, the algorithm used by {@code sort(Object[])} does not have to be
	* a MergeSort, but it does have to be <i>stable</i>.)
	*
	* <p>This class is a member of the
	* <a href="{@docRoot}/java.base/java/util/package-summary.html#CollectionsFramework">
	* Java Collections Framework</a>.
	*
	* @author Josh Bloch
	* @author Neal Gafter
	* @author John Rose
	* @since 1.2
	*/
	public class Arrays {

	// Suppresses default constructor, ensuring non-instantiability.
	private Arrays() {}

	/*
	* Sorting methods. Note that all public "sort" methods take the
	* same form: performing argument checks if necessary, and then
	* expanding arguments into those required for the internal
	* implementation methods residing in other package-private
	* classes (except for legacyMergeSort, included in this class).
	*/

	/**
	* Sorts the specified array into ascending numerical order.
	*
	* @implNote The sorting algorithm is a Dual-Pivot Quicksort
	* by Vladimir Yaroslavskiy, Jon Bentley, and Joshua Bloch. This algorithm
	* offers O(n log(n)) performance on all data sets, and is typically
	* faster than traditional (one-pivot) Quicksort implementations.
	*
	* @param a the array to be sorted
	*/
	public static void sort(int[] a) {
	DualPivotQuicksort.sort(a, 0, 0, a.length);
	}

	/**
	* Sorts the specified range of the array into ascending order. The range
	* to be sorted extends from the index {@code fromIndex}, inclusive, to
	* the index {@code toIndex}, exclusive. If {@code fromIndex == toIndex},
	* the range to be sorted is empty.
	*
	* @implNote The sorting algorithm is a Dual-Pivot Quicksort
	* by Vladimir Yaroslavskiy, Jon Bentley, and Joshua Bloch. This algorithm
	* offers O(n log(n)) performance on all data sets, and is typically
	* faster than traditional (one-pivot) Quicksort implementations.
	*
	* @param a the array to be sorted
	* @param fromIndex the index of the first element, inclusive, to be sorted
	* @param toIndex the index of the last element, exclusive, to be sorted
	*
	* @throws IllegalArgumentException if {@code fromIndex > toIndex}
	* @throws ArrayIndexOutOfBoundsException
	* if {@code fromIndex < 0} or {@code toIndex > a.length}
	*/
	public static void sort(int[] a, int fromIndex, int toIndex) {
	rangeCheck(a.length, fromIndex, toIndex);
	DualPivotQuicksort.sort(a, 0, fromIndex, toIndex);
	}

	/**
	* Sorts the specified array into ascending numerical order.
	*
	* @implNote The sorting algorithm is a Dual-Pivot Quicksort
	* by Vladimir Yaroslavskiy, Jon Bentley, and Joshua Bloch. This algorithm
	* offers O(n log(n)) performance on all data sets, and is typically
	* faster than traditional (one-pivot) Quicksort implementations.
	*
	* @param a the array to be sorted
	*/
	public static void sort(long[] a) {
	DualPivotQuicksort.sort(a, 0, 0, a.length);
	}

	/**
	* Sorts the specified range of the array into ascending order. The range
	* to be sorted extends from the index {@code fromIndex}, inclusive, to
	* the index {@code toIndex}, exclusive. If {@code fromIndex == toIndex},
	* the range to be sorted is empty.
	*
	* @implNote The sorting algorithm is a Dual-Pivot Quicksort
	* by Vladimir Yaroslavskiy, Jon Bentley, and Joshua Bloch. This algorithm
	* offers O(n log(n)) performance on all data sets, and is typically
	* faster than traditional (one-pivot) Quicksort implementations.
	*
	* @param a the array to be sorted
	* @param fromIndex the index of the first element, inclusive, to be sorted
	* @param toIndex the index of the last element, exclusive, to be sorted
	*
	* @throws IllegalArgumentException if {@code fromIndex > toIndex}
	* @throws ArrayIndexOutOfBoundsException
	* if {@code fromIndex < 0} or {@code toIndex > a.length}
	*/
	public static void sort(long[] a, int fromIndex, int toIndex) {
	rangeCheck(a.length, fromIndex, toIndex);
	DualPivotQuicksort.sort(a, 0, fromIndex, toIndex);
	}

	/**
	* Sorts the specified array into ascending numerical order.
	*
	* @implNote The sorting algorithm is a Dual-Pivot Quicksort
	* by Vladimir Yaroslavskiy, Jon Bentley, and Joshua Bloch. This algorithm
	* offers O(n log(n)) performance on all data sets, and is typically
	* faster than traditional (one-pivot) Quicksort implementations.
	*
	* @param a the array to be sorted
	*/
	public static void sort(short[] a) {
	DualPivotQuicksort.sort(a, 0, a.length);
	}

	/**
	* Sorts the specified range of the array into ascending order. The range
	* to be sorted extends from the index {@code fromIndex}, inclusive, to
	* the index {@code toIndex}, exclusive. If {@code fromIndex == toIndex},
	* the range to be sorted is empty.
	*
	* @implNote The sorting algorithm is a Dual-Pivot Quicksort
	* by Vladimir Yaroslavskiy, Jon Bentley, and Joshua Bloch. This algorithm
	* offers O(n log(n)) performance on all data sets, and is typically
	* faster than traditional (one-pivot) Quicksort implementations.
	*
	* @param a the array to be sorted
	* @param fromIndex the index of the first element, inclusive, to be sorted
	* @param toIndex the index of the last element, exclusive, to be sorted
	*
	* @throws IllegalArgumentException if {@code fromIndex > toIndex}
	* @throws ArrayIndexOutOfBoundsException
	* if {@code fromIndex < 0} or {@code toIndex > a.length}
	*/
	public static void sort(short[] a, int fromIndex, int toIndex) {
	rangeCheck(a.length, fromIndex, toIndex);
	DualPivotQuicksort.sort(a, fromIndex, toIndex);
	}

	/**
	* Sorts the specified array into ascending numerical order.
	*
	* @implNote The sorting algorithm is a Dual-Pivot Quicksort
	* by Vladimir Yaroslavskiy, Jon Bentley, and Joshua Bloch. This algorithm
	* offers O(n log(n)) performance on all data sets, and is typically
	* faster than traditional (one-pivot) Quicksort implementations.
	*
	* @param a the array to be sorted
	*/
	public static void sort(char[] a) {
	DualPivotQuicksort.sort(a, 0, a.length);
	}

	/**
	* Sorts the specified range of the array into ascending order. The range
	* to be sorted extends from the index {@code fromIndex}, inclusive, to
	* the index {@code toIndex}, exclusive. If {@code fromIndex == toIndex},
	* the range to be sorted is empty.
	*
	* @implNote The sorting algorithm is a Dual-Pivot Quicksort
	* by Vladimir Yaroslavskiy, Jon Bentley, and Joshua Bloch. This algorithm
	* offers O(n log(n)) performance on all data sets, and is typically
	* faster than traditional (one-pivot) Quicksort implementations.
	*
	* @param a the array to be sorted
	* @param fromIndex the index of the first element, inclusive, to be sorted
	* @param toIndex the index of the last element, exclusive, to be sorted
	*
	* @throws IllegalArgumentException if {@code fromIndex > toIndex}
	* @throws ArrayIndexOutOfBoundsException
	* if {@code fromIndex < 0} or {@code toIndex > a.length}
	*/
	public static void sort(char[] a, int fromIndex, int toIndex) {
	rangeCheck(a.length, fromIndex, toIndex);
	DualPivotQuicksort.sort(a, fromIndex, toIndex);
	}

	/**
	* Sorts the specified array into ascending numerical order.
	*
	* @implNote The sorting algorithm is a Dual-Pivot Quicksort
	* by Vladimir Yaroslavskiy, Jon Bentley, and Joshua Bloch. This algorithm
	* offers O(n log(n)) performance on all data sets, and is typically
	* faster than traditional (one-pivot) Quicksort implementations.
	*
	* @param a the array to be sorted
	*/
	public static void sort(byte[] a) {
	DualPivotQuicksort.sort(a, 0, a.length);
	}

	/**
	* Sorts the specified range of the array into ascending order. The range
	* to be sorted extends from the index {@code fromIndex}, inclusive, to
	* the index {@code toIndex}, exclusive. If {@code fromIndex == toIndex},
	* the range to be sorted is empty.
	*
	* @implNote The sorting algorithm is a Dual-Pivot Quicksort
	* by Vladimir Yaroslavskiy, Jon Bentley, and Joshua Bloch. This algorithm
	* offers O(n log(n)) performance on all data sets, and is typically
	* faster than traditional (one-pivot) Quicksort implementations.
	*
	* @param a the array to be sorted
	* @param fromIndex the index of the first element, inclusive, to be sorted
	* @param toIndex the index of the last element, exclusive, to be sorted
	*
	* @throws IllegalArgumentException if {@code fromIndex > toIndex}
	* @throws ArrayIndexOutOfBoundsException
	* if {@code fromIndex < 0} or {@code toIndex > a.length}
	*/
	public static void sort(byte[] a, int fromIndex, int toIndex) {
	rangeCheck(a.length, fromIndex, toIndex);
	DualPivotQuicksort.sort(a, fromIndex, toIndex);
	}

	/**
	* Sorts the specified array into ascending numerical order.
	*
	* <p>The {@code <} relation does not provide a total order on all float
	* values: {@code -0.0f == 0.0f} is {@code true} and a {@code Float.NaN}
	* value compares neither less than, greater than, nor equal to any value,
	* even itself. This method uses the total order imposed by the method
	* {@link Float#compareTo}: {@code -0.0f} is treated as less than value
	* {@code 0.0f} and {@code Float.NaN} is considered greater than any
	* other value and all {@code Float.NaN} values are considered equal.
	*
	* @implNote The sorting algorithm is a Dual-Pivot Quicksort
	* by Vladimir Yaroslavskiy, Jon Bentley, and Joshua Bloch. This algorithm
	* offers O(n log(n)) performance on all data sets, and is typically
	* faster than traditional (one-pivot) Quicksort implementations.
	*
	* @param a the array to be sorted
	*/
	public static void sort(float[] a) {
	DualPivotQuicksort.sort(a, 0, 0, a.length);
	}

	/**
	* Sorts the specified range of the array into ascending order. The range
	* to be sorted extends from the index {@code fromIndex}, inclusive, to
	* the index {@code toIndex}, exclusive. If {@code fromIndex == toIndex},
	* the range to be sorted is empty.
	*
	* <p>The {@code <} relation does not provide a total order on all float
	* values: {@code -0.0f == 0.0f} is {@code true} and a {@code Float.NaN}
	* value compares neither less than, greater than, nor equal to any value,
	* even itself. This method uses the total order imposed by the method
	* {@link Float#compareTo}: {@code -0.0f} is treated as less than value
	* {@code 0.0f} and {@code Float.NaN} is considered greater than any
	* other value and all {@code Float.NaN} values are considered equal.
	*
	* @implNote The sorting algorithm is a Dual-Pivot Quicksort
	* by Vladimir Yaroslavskiy, Jon Bentley, and Joshua Bloch. This algorithm
	* offers O(n log(n)) performance on all data sets, and is typically
	* faster than traditional (one-pivot) Quicksort implementations.
	*
	* @param a the array to be sorted
	* @param fromIndex the index of the first element, inclusive, to be sorted
	* @param toIndex the index of the last element, exclusive, to be sorted
	*
	* @throws IllegalArgumentException if {@code fromIndex > toIndex}
	* @throws ArrayIndexOutOfBoundsException
	* if {@code fromIndex < 0} or {@code toIndex > a.length}
	*/
	public static void sort(float[] a, int fromIndex, int toIndex) {
	rangeCheck(a.length, fromIndex, toIndex);
	DualPivotQuicksort.sort(a, 0, fromIndex, toIndex);
	}

	/**
	* Sorts the specified array into ascending numerical order.
	*
	* <p>The {@code <} relation does not provide a total order on all double
	* values: {@code -0.0d == 0.0d} is {@code true} and a {@code Double.NaN}
	* value compares neither less than, greater than, nor equal to any value,
	* even itself. This method uses the total order imposed by the method
	* {@link Double#compareTo}: {@code -0.0d} is treated as less than value
	* {@code 0.0d} and {@code Double.NaN} is considered greater than any
	* other value and all {@code Double.NaN} values are considered equal.
	*
	* @implNote The sorting algorithm is a Dual-Pivot Quicksort
	* by Vladimir Yaroslavskiy, Jon Bentley, and Joshua Bloch. This algorithm
	* offers O(n log(n)) performance on all data sets, and is typically
	* faster than traditional (one-pivot) Quicksort implementations.
	*
	* @param a the array to be sorted
	*/
	public static void sort(double[] a) {
	DualPivotQuicksort.sort(a, 0, 0, a.length);
	}

	/**
	* Sorts the specified range of the array into ascending order. The range
	* to be sorted extends from the index {@code fromIndex}, inclusive, to
	* the index {@code toIndex}, exclusive. If {@code fromIndex == toIndex},
	* the range to be sorted is empty.
	*
	* <p>The {@code <} relation does not provide a total order on all double
	* values: {@code -0.0d == 0.0d} is {@code true} and a {@code Double.NaN}
	* value compares neither less than, greater than, nor equal to any value,
	* even itself. This method uses the total order imposed by the method
	* {@link Double#compareTo}: {@code -0.0d} is treated as less than value
	* {@code 0.0d} and {@code Double.NaN} is considered greater than any
	* other value and all {@code Double.NaN} values are considered equal.
	*
	* @implNote The sorting algorithm is a Dual-Pivot Quicksort
	* by Vladimir Yaroslavskiy, Jon Bentley, and Joshua Bloch. This algorithm
	* offers O(n log(n)) performance on all data sets, and is typically
	* faster than traditional (one-pivot) Quicksort implementations.
	*
	* @param a the array to be sorted
	* @param fromIndex the index of the first element, inclusive, to be sorted
	* @param toIndex the index of the last element, exclusive, to be sorted
	*
	* @throws IllegalArgumentException if {@code fromIndex > toIndex}
	* @throws ArrayIndexOutOfBoundsException
	* if {@code fromIndex < 0} or {@code toIndex > a.length}
	*/
	public static void sort(double[] a, int fromIndex, int toIndex) {
	rangeCheck(a.length, fromIndex, toIndex);
	DualPivotQuicksort.sort(a, 0, fromIndex, toIndex);
	}

	/**
	* Sorts the specified array into ascending numerical order.
	*
	* @implNote The sorting algorithm is a Dual-Pivot Quicksort by
	* Vladimir Yaroslavskiy, Jon Bentley and Josh Bloch. This algorithm
	* offers O(n log(n)) performance on all data sets, and is typically
	* faster than traditional (one-pivot) Quicksort implementations.
	*
	* @param a the array to be sorted
	*
	* @since 1.8
	*/
	public static void parallelSort(byte[] a) {
	DualPivotQuicksort.sort(a, 0, a.length);
	}

	/**
	* Sorts the specified range of the array into ascending numerical order.
	* The range to be sorted extends from the index {@code fromIndex},
	* inclusive, to the index {@code toIndex}, exclusive. If
	* {@code fromIndex == toIndex}, the range to be sorted is empty.
	*
	* @implNote The sorting algorithm is a Dual-Pivot Quicksort by
	* Vladimir Yaroslavskiy, Jon Bentley and Josh Bloch. This algorithm
	* offers O(n log(n)) performance on all data sets, and is typically
	* faster than traditional (one-pivot) Quicksort implementations.
	*
	* @param a the array to be sorted
	* @param fromIndex the index of the first element, inclusive, to be sorted
	* @param toIndex the index of the last element, exclusive, to be sorted
	*
	* @throws IllegalArgumentException if {@code fromIndex > toIndex}
	* @throws ArrayIndexOutOfBoundsException
	* if {@code fromIndex < 0} or {@code toIndex > a.length}
	*
	* @since 1.8
	*/
	public static void parallelSort(byte[] a, int fromIndex, int toIndex) {
	rangeCheck(a.length, fromIndex, toIndex);
	DualPivotQuicksort.sort(a, fromIndex, toIndex);
	}

	/**
	* Sorts the specified array into ascending numerical order.
	*
	* @implNote The sorting algorithm is a Dual-Pivot Quicksort by
	* Vladimir Yaroslavskiy, Jon Bentley and Josh Bloch. This algorithm
	* offers O(n log(n)) performance on all data sets, and is typically
	* faster than traditional (one-pivot) Quicksort implementations.
	*
	* @param a the array to be sorted
	*
	* @since 1.8
	*/
	public static void parallelSort(char[] a) {
	DualPivotQuicksort.sort(a, 0, a.length);
	}

	/**
	* Sorts the specified range of the array into ascending numerical order.
	* The range to be sorted extends from the index {@code fromIndex},
	* inclusive, to the index {@code toIndex}, exclusive. If
	* {@code fromIndex == toIndex}, the range to be sorted is empty.
	*
	* @implNote The sorting algorithm is a Dual-Pivot Quicksort by
	* Vladimir Yaroslavskiy, Jon Bentley and Josh Bloch. This algorithm
	* offers O(n log(n)) performance on all data sets, and is typically
	* faster than traditional (one-pivot) Quicksort implementations.
	*
	* @param a the array to be sorted
	* @param fromIndex the index of the first element, inclusive, to be sorted
	* @param toIndex the index of the last element, exclusive, to be sorted
	*
	* @throws IllegalArgumentException if {@code fromIndex > toIndex}
	* @throws ArrayIndexOutOfBoundsException
	* if {@code fromIndex < 0} or {@code toIndex > a.length}
	*
	* @since 1.8
	*/
	public static void parallelSort(char[] a, int fromIndex, int toIndex) {
	rangeCheck(a.length, fromIndex, toIndex);
	DualPivotQuicksort.sort(a, fromIndex, toIndex);
	}

	/**
	* Sorts the specified array into ascending numerical order.
	*
	* @implNote The sorting algorithm is a Dual-Pivot Quicksort by
	* Vladimir Yaroslavskiy, Jon Bentley and Josh Bloch. This algorithm
	* offers O(n log(n)) performance on all data sets, and is typically
	* faster than traditional (one-pivot) Quicksort implementations.
	*
	* @param a the array to be sorted
	*
	* @since 1.8
	*/
	public static void parallelSort(short[] a) {
	DualPivotQuicksort.sort(a, 0, a.length);
	}

	/**
	* Sorts the specified range of the array into ascending numerical order.
	* The range to be sorted extends from the index {@code fromIndex},
	* inclusive, to the index {@code toIndex}, exclusive. If
	* {@code fromIndex == toIndex}, the range to be sorted is empty.
	*
	* @implNote The sorting algorithm is a Dual-Pivot Quicksort by
	* Vladimir Yaroslavskiy, Jon Bentley and Josh Bloch. This algorithm
	* offers O(n log(n)) performance on all data sets, and is typically
	* faster than traditional (one-pivot) Quicksort implementations.
	*
	* @param a the array to be sorted
	* @param fromIndex the index of the first element, inclusive, to be sorted
	* @param toIndex the index of the last element, exclusive, to be sorted
	*
	* @throws IllegalArgumentException if {@code fromIndex > toIndex}
	* @throws ArrayIndexOutOfBoundsException
	* if {@code fromIndex < 0} or {@code toIndex > a.length}
	*
	* @since 1.8
	*/
	public static void parallelSort(short[] a, int fromIndex, int toIndex) {
	rangeCheck(a.length, fromIndex, toIndex);
	DualPivotQuicksort.sort(a, fromIndex, toIndex);
	}

	/**
	* Sorts the specified array into ascending numerical order.
	*
	* @implNote The sorting algorithm is a Dual-Pivot Quicksort by
	* Vladimir Yaroslavskiy, Jon Bentley and Josh Bloch. This algorithm
	* offers O(n log(n)) performance on all data sets, and is typically
	* faster than traditional (one-pivot) Quicksort implementations.
	*
	* @param a the array to be sorted
	*
	* @since 1.8
	*/
	public static void parallelSort(int[] a) {
	DualPivotQuicksort.sort(a, ForkJoinPool.getCommonPoolParallelism(), 0, a.length);
	}

	/**
	* Sorts the specified range of the array into ascending numerical order.
	* The range to be sorted extends from the index {@code fromIndex},
	* inclusive, to the index {@code toIndex}, exclusive. If
	* {@code fromIndex == toIndex}, the range to be sorted is empty.
	*
	* @implNote The sorting algorithm is a Dual-Pivot Quicksort by
	* Vladimir Yaroslavskiy, Jon Bentley and Josh Bloch. This algorithm
	* offers O(n log(n)) performance on all data sets, and is typically
	* faster than traditional (one-pivot) Quicksort implementations.
	*
	* @param a the array to be sorted
	* @param fromIndex the index of the first element, inclusive, to be sorted
	* @param toIndex the index of the last element, exclusive, to be sorted
	*
	* @throws IllegalArgumentException if {@code fromIndex > toIndex}
	* @throws ArrayIndexOutOfBoundsException
	* if {@code fromIndex < 0} or {@code toIndex > a.length}
	*
	* @since 1.8
	*/
	public static void parallelSort(int[] a, int fromIndex, int toIndex) {
	rangeCheck(a.length, fromIndex, toIndex);
	DualPivotQuicksort.sort(a, ForkJoinPool.getCommonPoolParallelism(), fromIndex, toIndex);
	}

	/**
	* Sorts the specified array into ascending numerical order.
	*
	* @implNote The sorting algorithm is a Dual-Pivot Quicksort by
	* Vladimir Yaroslavskiy, Jon Bentley and Josh Bloch. This algorithm
	* offers O(n log(n)) performance on all data sets, and is typically
	* faster than traditional (one-pivot) Quicksort implementations.
	*
	* @param a the array to be sorted
	*
	* @since 1.8
	*/
	public static void parallelSort(long[] a) {
	DualPivotQuicksort.sort(a, ForkJoinPool.getCommonPoolParallelism(), 0, a.length);
	}

	/**
	* Sorts the specified range of the array into ascending numerical order.
	* The range to be sorted extends from the index {@code fromIndex},
	* inclusive, to the index {@code toIndex}, exclusive. If
	* {@code fromIndex == toIndex}, the range to be sorted is empty.
	*
	* @implNote The sorting algorithm is a Dual-Pivot Quicksort by
	* Vladimir Yaroslavskiy, Jon Bentley and Josh Bloch. This algorithm
	* offers O(n log(n)) performance on all data sets, and is typically
	* faster than traditional (one-pivot) Quicksort implementations.
	*
	* @param a the array to be sorted
	* @param fromIndex the index of the first element, inclusive, to be sorted
	* @param toIndex the index of the last element, exclusive, to be sorted
	*
	* @throws IllegalArgumentException if {@code fromIndex > toIndex}
	* @throws ArrayIndexOutOfBoundsException
	* if {@code fromIndex < 0} or {@code toIndex > a.length}
	*
	* @since 1.8
	*/
	public static void parallelSort(long[] a, int fromIndex, int toIndex) {
	rangeCheck(a.length, fromIndex, toIndex);
	DualPivotQuicksort.sort(a, ForkJoinPool.getCommonPoolParallelism(), fromIndex, toIndex);
	}

	/**
	* Sorts the specified array into ascending numerical order.
	*
	* <p>The {@code <} relation does not provide a total order on all float
	* values: {@code -0.0f == 0.0f} is {@code true} and a {@code Float.NaN}
	* value compares neither less than, greater than, nor equal to any value,
	* even itself. This method uses the total order imposed by the method
	* {@link Float#compareTo}: {@code -0.0f} is treated as less than value
	* {@code 0.0f} and {@code Float.NaN} is considered greater than any
	* other value and all {@code Float.NaN} values are considered equal.
	*
	* @implNote The sorting algorithm is a Dual-Pivot Quicksort by
	* Vladimir Yaroslavskiy, Jon Bentley and Josh Bloch. This algorithm
	* offers O(n log(n)) performance on all data sets, and is typically
	* faster than traditional (one-pivot) Quicksort implementations.
	*
	* @param a the array to be sorted
	*
	* @since 1.8
	*/
	public static void parallelSort(float[] a) {
	DualPivotQuicksort.sort(a, ForkJoinPool.getCommonPoolParallelism(), 0, a.length);
	}

	/**
	* Sorts the specified range of the array into ascending numerical order.
	* The range to be sorted extends from the index {@code fromIndex},
	* inclusive, to the index {@code toIndex}, exclusive. If
	* {@code fromIndex == toIndex}, the range to be sorted is empty.
	*
	* <p>The {@code <} relation does not provide a total order on all float
	* values: {@code -0.0f == 0.0f} is {@code true} and a {@code Float.NaN}
	* value compares neither less than, greater than, nor equal to any value,
	* even itself. This method uses the total order imposed by the method
	* {@link Float#compareTo}: {@code -0.0f} is treated as less than value
	* {@code 0.0f} and {@code Float.NaN} is considered greater than any
	* other value and all {@code Float.NaN} values are considered equal.
	*
	* @implNote The sorting algorithm is a Dual-Pivot Quicksort by
	* Vladimir Yaroslavskiy, Jon Bentley and Josh Bloch. This algorithm
	* offers O(n log(n)) performance on all data sets, and is typically
	* faster than traditional (one-pivot) Quicksort implementations.
	*
	* @param a the array to be sorted
	* @param fromIndex the index of the first element, inclusive, to be sorted
	* @param toIndex the index of the last element, exclusive, to be sorted
	*
	* @throws IllegalArgumentException if {@code fromIndex > toIndex}
	* @throws ArrayIndexOutOfBoundsException
	* if {@code fromIndex < 0} or {@code toIndex > a.length}
	*
	* @since 1.8
	*/
	public static void parallelSort(float[] a, int fromIndex, int toIndex) {
	rangeCheck(a.length, fromIndex, toIndex);
	DualPivotQuicksort.sort(a, ForkJoinPool.getCommonPoolParallelism(), fromIndex, toIndex);
	}

	/**
	* Sorts the specified array into ascending numerical order.
	*
	* <p>The {@code <} relation does not provide a total order on all double
	* values: {@code -0.0d == 0.0d} is {@code true} and a {@code Double.NaN}
	* value compares neither less than, greater than, nor equal to any value,
	* even itself. This method uses the total order imposed by the method
	* {@link Double#compareTo}: {@code -0.0d} is treated as less than value
	* {@code 0.0d} and {@code Double.NaN} is considered greater than any
	* other value and all {@code Double.NaN} values are considered equal.
	*
	* @implNote The sorting algorithm is a Dual-Pivot Quicksort by
	* Vladimir Yaroslavskiy, Jon Bentley and Josh Bloch. This algorithm
	* offers O(n log(n)) performance on all data sets, and is typically
	* faster than traditional (one-pivot) Quicksort implementations.
	*
	* @param a the array to be sorted
	*
	* @since 1.8
	*/
	public static void parallelSort(double[] a) {
	DualPivotQuicksort.sort(a, ForkJoinPool.getCommonPoolParallelism(), 0, a.length);
	}

	/**
	* Sorts the specified range of the array into ascending numerical order.
	* The range to be sorted extends from the index {@code fromIndex},
	* inclusive, to the index {@code toIndex}, exclusive. If
	* {@code fromIndex == toIndex}, the range to be sorted is empty.
	*
	* <p>The {@code <} relation does not provide a total order on all double
	* values: {@code -0.0d == 0.0d} is {@code true} and a {@code Double.NaN}
	* value compares neither less than, greater than, nor equal to any value,
	* even itself. This method uses the total order imposed by the method
	* {@link Double#compareTo}: {@code -0.0d} is treated as less than value
	* {@code 0.0d} and {@code Double.NaN} is considered greater than any
	* other value and all {@code Double.NaN} values are considered equal.
	*
	* @implNote The sorting algorithm is a Dual-Pivot Quicksort by
	* Vladimir Yaroslavskiy, Jon Bentley and Josh Bloch. This algorithm
	* offers O(n log(n)) performance on all data sets, and is typically
	* faster than traditional (one-pivot) Quicksort implementations.
	*
	* @param a the array to be sorted
	* @param fromIndex the index of the first element, inclusive, to be sorted
	* @param toIndex the index of the last element, exclusive, to be sorted
	*
	* @throws IllegalArgumentException if {@code fromIndex > toIndex}
	* @throws ArrayIndexOutOfBoundsException
	* if {@code fromIndex < 0} or {@code toIndex > a.length}
	*
	* @since 1.8
	*/
	public static void parallelSort(double[] a, int fromIndex, int toIndex) {
	rangeCheck(a.length, fromIndex, toIndex);
	DualPivotQuicksort.sort(a, ForkJoinPool.getCommonPoolParallelism(), fromIndex, toIndex);
	}

	/**
	* Checks that {@code fromIndex} and {@code toIndex} are in
	* the range and throws an exception if they aren't.
	*/
	static void rangeCheck(int arrayLength, int fromIndex, int toIndex) {
	if (fromIndex > toIndex) {
	throw new IllegalArgumentException(
	"fromIndex(" + fromIndex + ") > toIndex(" + toIndex + ")");
	}
	if (fromIndex < 0) {
	throw new ArrayIndexOutOfBoundsException(fromIndex);
	}
	if (toIndex > arrayLength) {
	throw new ArrayIndexOutOfBoundsException(toIndex);
	}
	}

	/**
	* A comparator that implements the natural ordering of a group of
	* mutually comparable elements. May be used when a supplied
	* comparator is null. To simplify code-sharing within underlying
	* implementations, the compare method only declares type Object
	* for its second argument.
	*
	* Arrays class implementor's note: It is an empirical matter
	* whether ComparableTimSort offers any performance benefit over
	* TimSort used with this comparator. If not, you are better off
	* deleting or bypassing ComparableTimSort. There is currently no
	* empirical case for separating them for parallel sorting, so all
	* public Object parallelSort methods use the same comparator
	* based implementation.
	*/
	static final class NaturalOrder implements Comparator<Object> {
	@SuppressWarnings("unchecked")
	public int compare(Object first, Object second) {
	return ((Comparable<Object>)first).compareTo(second);
	}
	static final NaturalOrder INSTANCE = new NaturalOrder();
	}

	/**
	* The minimum array length below which a parallel sorting
	* algorithm will not further partition the sorting task. Using
	* smaller sizes typically results in memory contention across
	* tasks that makes parallel speedups unlikely.
	*/
	private static final int MIN_ARRAY_SORT_GRAN = 1 << 13;

	/**
	* Sorts the specified array of objects into ascending order, according
	* to the {@linkplain Comparable natural ordering} of its elements.
	* All elements in the array must implement the {@link Comparable}
	* interface. Furthermore, all elements in the array must be
	* <i>mutually comparable</i> (that is, {@code e1.compareTo(e2)} must
	* not throw a {@code ClassCastException} for any elements {@code e1}
	* and {@code e2} in the array).
	*
	* <p>This sort is guaranteed to be <i>stable</i>: equal elements will
	* not be reordered as a result of the sort.
	*
	* @implNote The sorting algorithm is a parallel sort-merge that breaks the
	* array into sub-arrays that are themselves sorted and then merged. When
	* the sub-array length reaches a minimum granularity, the sub-array is
	* sorted using the appropriate {@link Arrays#sort(Object[]) Arrays.sort}
	* method. If the length of the specified array is less than the minimum
	* granularity, then it is sorted using the appropriate {@link
	* Arrays#sort(Object[]) Arrays.sort} method. The algorithm requires a
	* working space no greater than the size of the original array. The
	* {@link ForkJoinPool#commonPool() ForkJoin common pool} is used to
	* execute any parallel tasks.
	*
	* @param <T> the class of the objects to be sorted
	* @param a the array to be sorted
	*
	* @throws ClassCastException if the array contains elements that are not
	* <i>mutually comparable</i> (for example, strings and integers)
	* @throws IllegalArgumentException (optional) if the natural
	* ordering of the array elements is found to violate the
	* {@link Comparable} contract
	*
	* @since 1.8
	*/
	@SuppressWarnings("unchecked")
	public static <T extends Comparable<? super T>> void parallelSort(T[] a) {
	int n = a.length, p, g;
	if (n <= MIN_ARRAY_SORT_GRAN \|\|
	(p = ForkJoinPool.getCommonPoolParallelism()) == 1)
	TimSort.sort(a, 0, n, NaturalOrder.INSTANCE, null, 0, 0);
	else
	new ArraysParallelSortHelpers.FJObject.Sorter<>
	(null, a,
	(T[])Array.newInstance(a.getClass().getComponentType(), n),
	0, n, 0, ((g = n / (p << 2)) <= MIN_ARRAY_SORT_GRAN) ?
	MIN_ARRAY_SORT_GRAN : g, NaturalOrder.INSTANCE).invoke();
	}

	/**
	* Sorts the specified range of the specified array of objects into
	* ascending order, according to the
	* {@linkplain Comparable natural ordering} of its
	* elements. The range to be sorted extends from index
	* {@code fromIndex}, inclusive, to index {@code toIndex}, exclusive.
	* (If {@code fromIndex==toIndex}, the range to be sorted is empty.) All
	* elements in this range must implement the {@link Comparable}
	* interface. Furthermore, all elements in this range must be <i>mutually
	* comparable</i> (that is, {@code e1.compareTo(e2)} must not throw a
	* {@code ClassCastException} for any elements {@code e1} and
	* {@code e2} in the array).
	*
	* <p>This sort is guaranteed to be <i>stable</i>: equal elements will
	* not be reordered as a result of the sort.
	*
	* @implNote The sorting algorithm is a parallel sort-merge that breaks the
	* array into sub-arrays that are themselves sorted and then merged. When
	* the sub-array length reaches a minimum granularity, the sub-array is
	* sorted using the appropriate {@link Arrays#sort(Object[]) Arrays.sort}
	* method. If the length of the specified array is less than the minimum
	* granularity, then it is sorted using the appropriate {@link
	* Arrays#sort(Object[]) Arrays.sort} method. The algorithm requires a working
	* space no greater than the size of the specified range of the original
	* array. The {@link ForkJoinPool#commonPool() ForkJoin common pool} is
	* used to execute any parallel tasks.
	*
	* @param <T> the class of the objects to be sorted
	* @param a the array to be sorted
	* @param fromIndex the index of the first element (inclusive) to be
	* sorted
	* @param toIndex the index of the last element (exclusive) to be sorted
	* @throws IllegalArgumentException if {@code fromIndex > toIndex} or
	* (optional) if the natural ordering of the array elements is
	* found to violate the {@link Comparable} contract
	* @throws ArrayIndexOutOfBoundsException if {@code fromIndex < 0} or
	* {@code toIndex > a.length}
	* @throws ClassCastException if the array contains elements that are
	* not <i>mutually comparable</i> (for example, strings and
	* integers).
	*
	* @since 1.8
	*/
	@SuppressWarnings("unchecked")
	public static <T extends Comparable<? super T>>
	void parallelSort(T[] a, int fromIndex, int toIndex) {
	rangeCheck(a.length, fromIndex, toIndex);
	int n = toIndex - fromIndex, p, g;
	if (n <= MIN_ARRAY_SORT_GRAN \|\|
	(p = ForkJoinPool.getCommonPoolParallelism()) == 1)
	TimSort.sort(a, fromIndex, toIndex, NaturalOrder.INSTANCE, null, 0, 0);
	else
	new ArraysParallelSortHelpers.FJObject.Sorter<>
	(null, a,
	(T[])Array.newInstance(a.getClass().getComponentType(), n),
	fromIndex, n, 0, ((g = n / (p << 2)) <= MIN_ARRAY_SORT_GRAN) ?
	MIN_ARRAY_SORT_GRAN : g, NaturalOrder.INSTANCE).invoke();
	}

	/**
	* Sorts the specified array of objects according to the order induced by
	* the specified comparator. All elements in the array must be
	* <i>mutually comparable</i> by the specified comparator (that is,
	* {@code c.compare(e1, e2)} must not throw a {@code ClassCastException}
	* for any elements {@code e1} and {@code e2} in the array).
	*
	* <p>This sort is guaranteed to be <i>stable</i>: equal elements will
	* not be reordered as a result of the sort.
	*
	* @implNote The sorting algorithm is a parallel sort-merge that breaks the
	* array into sub-arrays that are themselves sorted and then merged. When
	* the sub-array length reaches a minimum granularity, the sub-array is
	* sorted using the appropriate {@link Arrays#sort(Object[]) Arrays.sort}
	* method. If the length of the specified array is less than the minimum
	* granularity, then it is sorted using the appropriate {@link
	* Arrays#sort(Object[]) Arrays.sort} method. The algorithm requires a
	* working space no greater than the size of the original array. The
	* {@link ForkJoinPool#commonPool() ForkJoin common pool} is used to
	* execute any parallel tasks.
	*
	* @param <T> the class of the objects to be sorted
	* @param a the array to be sorted
	* @param cmp the comparator to determine the order of the array. A
	* {@code null} value indicates that the elements'
	* {@linkplain Comparable natural ordering} should be used.
	* @throws ClassCastException if the array contains elements that are
	* not <i>mutually comparable</i> using the specified comparator
	* @throws IllegalArgumentException (optional) if the comparator is
	* found to violate the {@link java.util.Comparator} contract
	*
	* @since 1.8
	*/
	@SuppressWarnings("unchecked")
	public static <T> void parallelSort(T[] a, Comparator<? super T> cmp) {
	if (cmp == null)
	cmp = NaturalOrder.INSTANCE;
	int n = a.length, p, g;
	if (n <= MIN_ARRAY_SORT_GRAN \|\|
	(p = ForkJoinPool.getCommonPoolParallelism()) == 1)
	TimSort.sort(a, 0, n, cmp, null, 0, 0);
	else
	new ArraysParallelSortHelpers.FJObject.Sorter<>
	(null, a,
	(T[])Array.newInstance(a.getClass().getComponentType(), n),
	0, n, 0, ((g = n / (p << 2)) <= MIN_ARRAY_SORT_GRAN) ?
	MIN_ARRAY_SORT_GRAN : g, cmp).invoke();
	}

	/**
	* Sorts the specified range of the specified array of objects according
	* to the order induced by the specified comparator. The range to be
	* sorted extends from index {@code fromIndex}, inclusive, to index
	* {@code toIndex}, exclusive. (If {@code fromIndex==toIndex}, the
	* range to be sorted is empty.) All elements in the range must be
	* <i>mutually comparable</i> by the specified comparator (that is,
	* {@code c.compare(e1, e2)} must not throw a {@code ClassCastException}
	* for any elements {@code e1} and {@code e2} in the range).
	*
	* <p>This sort is guaranteed to be <i>stable</i>: equal elements will
	* not be reordered as a result of the sort.
	*
	* @implNote The sorting algorithm is a parallel sort-merge that breaks the
	* array into sub-arrays that are themselves sorted and then merged. When
	* the sub-array length reaches a minimum granularity, the sub-array is
	* sorted using the appropriate {@link Arrays#sort(Object[]) Arrays.sort}
	* method. If the length of the specified array is less than the minimum
	* granularity, then it is sorted using the appropriate {@link
	* Arrays#sort(Object[]) Arrays.sort} method. The algorithm requires a working
	* space no greater than the size of the specified range of the original
	* array. The {@link ForkJoinPool#commonPool() ForkJoin common pool} is
	* used to execute any parallel tasks.
	*
	* @param <T> the class of the objects to be sorted
	* @param a the array to be sorted
	* @param fromIndex the index of the first element (inclusive) to be
	* sorted
	* @param toIndex the index of the last element (exclusive) to be sorted
	* @param cmp the comparator to determine the order of the array. A
	* {@code null} value indicates that the elements'
	* {@linkplain Comparable natural ordering} should be used.
	* @throws IllegalArgumentException if {@code fromIndex > toIndex} or
	* (optional) if the natural ordering of the array elements is
	* found to violate the {@link Comparable} contract
	* @throws ArrayIndexOutOfBoundsException if {@code fromIndex < 0} or
	* {@code toIndex > a.length}
	* @throws ClassCastException if the array contains elements that are
	* not <i>mutually comparable</i> (for example, strings and
	* integers).
	*
	* @since 1.8
	*/
	@SuppressWarnings("unchecked")
	public static <T> void parallelSort(T[] a, int fromIndex, int toIndex,
	Comparator<? super T> cmp) {
	rangeCheck(a.length, fromIndex, toIndex);
	if (cmp == null)
	cmp = NaturalOrder.INSTANCE;
	int n = toIndex - fromIndex, p, g;
	if (n <= MIN_ARRAY_SORT_GRAN \|\|
	(p = ForkJoinPool.getCommonPoolParallelism()) == 1)
	TimSort.sort(a, fromIndex, toIndex, cmp, null, 0, 0);
	else
	new ArraysParallelSortHelpers.FJObject.Sorter<>
	(null, a,
	(T[])Array.newInstance(a.getClass().getComponentType(), n),
	fromIndex, n, 0, ((g = n / (p << 2)) <= MIN_ARRAY_SORT_GRAN) ?
	MIN_ARRAY_SORT_GRAN : g, cmp).invoke();
	}

	/*
	* Sorting of complex type arrays.
	*/

	/**
	* Old merge sort implementation can be selected (for
	* compatibility with broken comparators) using a system property.
	* Cannot be a static boolean in the enclosing class due to
	* circular dependencies. To be removed in a future release.
	*/
	static final class LegacyMergeSort {
	@SuppressWarnings("removal")
	private static final boolean userRequested =
	java.security.AccessController.doPrivileged(
	new sun.security.action.GetBooleanAction(
	"java.util.Arrays.useLegacyMergeSort")).booleanValue();
	}

	/**
	* Sorts the specified array of objects into ascending order, according
	* to the {@linkplain Comparable natural ordering} of its elements.
	* All elements in the array must implement the {@link Comparable}
	* interface. Furthermore, all elements in the array must be
	* <i>mutually comparable</i> (that is, {@code e1.compareTo(e2)} must
	* not throw a {@code ClassCastException} for any elements {@code e1}
	* and {@code e2} in the array).
	*
	* <p>This sort is guaranteed to be <i>stable</i>: equal elements will
	* not be reordered as a result of the sort.
	*
	* <p>Implementation note: This implementation is a stable, adaptive,
	* iterative mergesort that requires far fewer than n lg(n) comparisons
	* when the input array is partially sorted, while offering the
	* performance of a traditional mergesort when the input array is
	* randomly ordered. If the input array is nearly sorted, the
	* implementation requires approximately n comparisons. Temporary
	* storage requirements vary from a small constant for nearly sorted
	* input arrays to n/2 object references for randomly ordered input
	* arrays.
	*
	* <p>The implementation takes equal advantage of ascending and
	* descending order in its input array, and can take advantage of
	* ascending and descending order in different parts of the same
	* input array. It is well-suited to merging two or more sorted arrays:
	* simply concatenate the arrays and sort the resulting array.
	*
	* <p>The implementation was adapted from Tim Peters's list sort for Python
	* (<a href="http://svn.python.org/projects/python/trunk/Objects/listsort.txt">
	* TimSort</a>). It uses techniques from Peter McIlroy's "Optimistic
	* Sorting and Information Theoretic Complexity", in Proceedings of the
	* Fourth Annual ACM-SIAM Symposium on Discrete Algorithms, pp 467-474,
	* January 1993.
	*
	* @param a the array to be sorted
	* @throws ClassCastException if the array contains elements that are not
	* <i>mutually comparable</i> (for example, strings and integers)
	* @throws IllegalArgumentException (optional) if the natural
	* ordering of the array elements is found to violate the
	* {@link Comparable} contract
	*/
	public static void sort(Object[] a) {
	if (LegacyMergeSort.userRequested)
	legacyMergeSort(a);
	else
	ComparableTimSort.sort(a, 0, a.length, null, 0, 0);
	}

	/** To be removed in a future release. */
	private static void legacyMergeSort(Object[] a) {
	Object[] aux = a.clone();
	mergeSort(aux, a, 0, a.length, 0);
	}

	/**
	* Sorts the specified range of the specified array of objects into
	* ascending order, according to the
	* {@linkplain Comparable natural ordering} of its
	* elements. The range to be sorted extends from index
	* {@code fromIndex}, inclusive, to index {@code toIndex}, exclusive.
	* (If {@code fromIndex==toIndex}, the range to be sorted is empty.) All
	* elements in this range must implement the {@link Comparable}
	* interface. Furthermore, all elements in this range must be <i>mutually
	* comparable</i> (that is, {@code e1.compareTo(e2)} must not throw a
	* {@code ClassCastException} for any elements {@code e1} and
	* {@code e2} in the array).
	*
	* <p>This sort is guaranteed to be <i>stable</i>: equal elements will
	* not be reordered as a result of the sort.
	*
	* <p>Implementation note: This implementation is a stable, adaptive,
	* iterative mergesort that requires far fewer than n lg(n) comparisons
	* when the input array is partially sorted, while offering the
	* performance of a traditional mergesort when the input array is
	* randomly ordered. If the input array is nearly sorted, the
	* implementation requires approximately n comparisons. Temporary
	* storage requirements vary from a small constant for nearly sorted
	* input arrays to n/2 object references for randomly ordered input
	* arrays.
	*
	* <p>The implementation takes equal advantage of ascending and
	* descending order in its input array, and can take advantage of
	* ascending and descending order in different parts of the same
	* input array. It is well-suited to merging two or more sorted arrays:
	* simply concatenate the arrays and sort the resulting array.
	*
	* <p>The implementation was adapted from Tim Peters's list sort for Python
	* (<a href="http://svn.python.org/projects/python/trunk/Objects/listsort.txt">
	* TimSort</a>). It uses techniques from Peter McIlroy's "Optimistic
	* Sorting and Information Theoretic Complexity", in Proceedings of the
	* Fourth Annual ACM-SIAM Symposium on Discrete Algorithms, pp 467-474,
	* January 1993.
	*
	* @param a the array to be sorted
	* @param fromIndex the index of the first element (inclusive) to be
	* sorted
	* @param toIndex the index of the last element (exclusive) to be sorted
	* @throws IllegalArgumentException if {@code fromIndex > toIndex} or
	* (optional) if the natural ordering of the array elements is
	* found to violate the {@link Comparable} contract
	* @throws ArrayIndexOutOfBoundsException if {@code fromIndex < 0} or
	* {@code toIndex > a.length}
	* @throws ClassCastException if the array contains elements that are
	* not <i>mutually comparable</i> (for example, strings and
	* integers).
	*/
	public static void sort(Object[] a, int fromIndex, int toIndex) {
	rangeCheck(a.length, fromIndex, toIndex);
	if (LegacyMergeSort.userRequested)
	legacyMergeSort(a, fromIndex, toIndex);
	else
	ComparableTimSort.sort(a, fromIndex, toIndex, null, 0, 0);
	}

	/** To be removed in a future release. */
	private static void legacyMergeSort(Object[] a,
	int fromIndex, int toIndex) {
	Object[] aux = copyOfRange(a, fromIndex, toIndex);
	mergeSort(aux, a, fromIndex, toIndex, -fromIndex);
	}

	/**
	* Tuning parameter: list size at or below which insertion sort will be
	* used in preference to mergesort.
	* To be removed in a future release.
	*/
	private static final int INSERTIONSORT_THRESHOLD = 7;

	/**
	* Src is the source array that starts at index 0
	* Dest is the (possibly larger) array destination with a possible offset
	* low is the index in dest to start sorting
	* high is the end index in dest to end sorting
	* off is the offset to generate corresponding low, high in src
	* To be removed in a future release.
	*/
	@SuppressWarnings({"unchecked", "rawtypes"})
	private static void mergeSort(Object[] src,
	Object[] dest,
	int low,
	int high,
	int off) {
	int length = high - low;

	// Insertion sort on smallest arrays
	if (length < INSERTIONSORT_THRESHOLD) {
	for (int i=low; i<high; i++)
	for (int j=i; j>low &&
	((Comparable) dest[j-1]).compareTo(dest[j])>0; j--)
	swap(dest, j, j-1);
	return;
	}

	// Recursively sort halves of dest into src
	int destLow = low;
	int destHigh = high;
	low += off;
	high += off;
	int mid = (low + high) >>> 1;
	mergeSort(dest, src, low, mid, -off);
	mergeSort(dest, src, mid, high, -off);

	// If list is already sorted, just copy from src to dest. This is an
	// optimization that results in faster sorts for nearly ordered lists.
	if (((Comparable)src[mid-1]).compareTo(src[mid]) <= 0) {
	System.arraycopy(src, low, dest, destLow, length);
	return;
	}

	// Merge sorted halves (now in src) into dest
	for(int i = destLow, p = low, q = mid; i < destHigh; i++) {
	if (q >= high \|\| p < mid && ((Comparable)src[p]).compareTo(src[q])<=0)
	dest[i] = src[p++];
	else
	dest[i] = src[q++];
	}
	}

	/**
	* Swaps x[a] with x[b].
	*/
	private static void swap(Object[] x, int a, int b) {
	Object t = x[a];
	x[a] = x[b];
	x[b] = t;
	}

	/**
	* Sorts the specified array of objects according to the order induced by
	* the specified comparator. All elements in the array must be
	* <i>mutually comparable</i> by the specified comparator (that is,
	* {@code c.compare(e1, e2)} must not throw a {@code ClassCastException}
	* for any elements {@code e1} and {@code e2} in the array).
	*
	* <p>This sort is guaranteed to be <i>stable</i>: equal elements will
	* not be reordered as a result of the sort.
	*
	* <p>Implementation note: This implementation is a stable, adaptive,
	* iterative mergesort that requires far fewer than n lg(n) comparisons
	* when the input array is partially sorted, while offering the
	* performance of a traditional mergesort when the input array is
	* randomly ordered. If the input array is nearly sorted, the
	* implementation requires approximately n comparisons. Temporary
	* storage requirements vary from a small constant for nearly sorted
	* input arrays to n/2 object references for randomly ordered input
	* arrays.
	*
	* <p>The implementation takes equal advantage of ascending and
	* descending order in its input array, and can take advantage of
	* ascending and descending order in different parts of the same
	* input array. It is well-suited to merging two or more sorted arrays:
	* simply concatenate the arrays and sort the resulting array.
	*
	* <p>The implementation was adapted from Tim Peters's list sort for Python
	* (<a href="http://svn.python.org/projects/python/trunk/Objects/listsort.txt">
	* TimSort</a>). It uses techniques from Peter McIlroy's "Optimistic
	* Sorting and Information Theoretic Complexity", in Proceedings of the
	* Fourth Annual ACM-SIAM Symposium on Discrete Algorithms, pp 467-474,
	* January 1993.
	*
	* @param <T> the class of the objects to be sorted
	* @param a the array to be sorted
	* @param c the comparator to determine the order of the array. A
	* {@code null} value indicates that the elements'
	* {@linkplain Comparable natural ordering} should be used.
	* @throws ClassCastException if the array contains elements that are
	* not <i>mutually comparable</i> using the specified comparator
	* @throws IllegalArgumentException (optional) if the comparator is
	* found to violate the {@link Comparator} contract
	*/
	public static <T> void sort(T[] a, Comparator<? super T> c) {
	if (c == null) {
	sort(a);
	} else {
	if (LegacyMergeSort.userRequested)
	legacyMergeSort(a, c);
	else
	TimSort.sort(a, 0, a.length, c, null, 0, 0);
	}
	}

	/** To be removed in a future release. */
	private static <T> void legacyMergeSort(T[] a, Comparator<? super T> c) {
	T[] aux = a.clone();
	if (c==null)
	mergeSort(aux, a, 0, a.length, 0);
	else
	mergeSort(aux, a, 0, a.length, 0, c);
	}

	/**
	* Sorts the specified range of the specified array of objects according
	* to the order induced by the specified comparator. The range to be
	* sorted extends from index {@code fromIndex}, inclusive, to index
	* {@code toIndex}, exclusive. (If {@code fromIndex==toIndex}, the
	* range to be sorted is empty.) All elements in the range must be
	* <i>mutually comparable</i> by the specified comparator (that is,
	* {@code c.compare(e1, e2)} must not throw a {@code ClassCastException}
	* for any elements {@code e1} and {@code e2} in the range).
	*
	* <p>This sort is guaranteed to be <i>stable</i>: equal elements will
	* not be reordered as a result of the sort.
	*
	* <p>Implementation note: This implementation is a stable, adaptive,
	* iterative mergesort that requires far fewer than n lg(n) comparisons
	* when the input array is partially sorted, while offering the
	* performance of a traditional mergesort when the input array is
	* randomly ordered. If the input array is nearly sorted, the
	* implementation requires approximately n comparisons. Temporary
	* storage requirements vary from a small constant for nearly sorted
	* input arrays to n/2 object references for randomly ordered input
	* arrays.
	*
	* <p>The implementation takes equal advantage of ascending and
	* descending order in its input array, and can take advantage of
	* ascending and descending order in different parts of the same
	* input array. It is well-suited to merging two or more sorted arrays:
	* simply concatenate the arrays and sort the resulting array.
	*
	* <p>The implementation was adapted from Tim Peters's list sort for Python
	* (<a href="http://svn.python.org/projects/python/trunk/Objects/listsort.txt">
	* TimSort</a>). It uses techniques from Peter McIlroy's "Optimistic
	* Sorting and Information Theoretic Complexity", in Proceedings of the
	* Fourth Annual ACM-SIAM Symposium on Discrete Algorithms, pp 467-474,
	* January 1993.
	*
	* @param <T> the class of the objects to be sorted
	* @param a the array to be sorted
	* @param fromIndex the index of the first element (inclusive) to be
	* sorted
	* @param toIndex the index of the last element (exclusive) to be sorted
	* @param c the comparator to determine the order of the array. A
	* {@code null} value indicates that the elements'
	* {@linkplain Comparable natural ordering} should be used.
	* @throws ClassCastException if the array contains elements that are not
	* <i>mutually comparable</i> using the specified comparator.
	* @throws IllegalArgumentException if {@code fromIndex > toIndex} or
	* (optional) if the comparator is found to violate the
	* {@link Comparator} contract
	* @throws ArrayIndexOutOfBoundsException if {@code fromIndex < 0} or
	* {@code toIndex > a.length}
	*/
	public static <T> void sort(T[] a, int fromIndex, int toIndex,
	Comparator<? super T> c) {
	if (c == null) {
	sort(a, fromIndex, toIndex);
	} else {
	rangeCheck(a.length, fromIndex, toIndex);
	if (LegacyMergeSort.userRequested)
	legacyMergeSort(a, fromIndex, toIndex, c);
	else
	TimSort.sort(a, fromIndex, toIndex, c, null, 0, 0);
	}
	}

	/** To be removed in a future release. */
	private static <T> void legacyMergeSort(T[] a, int fromIndex, int toIndex,
	Comparator<? super T> c) {
	T[] aux = copyOfRange(a, fromIndex, toIndex);
	if (c==null)
	mergeSort(aux, a, fromIndex, toIndex, -fromIndex);
	else
	mergeSort(aux, a, fromIndex, toIndex, -fromIndex, c);
	}

	/**
	* Src is the source array that starts at index 0
	* Dest is the (possibly larger) array destination with a possible offset
	* low is the index in dest to start sorting
	* high is the end index in dest to end sorting
	* off is the offset into src corresponding to low in dest
	* To be removed in a future release.
	*/
	@SuppressWarnings({"rawtypes", "unchecked"})
	private static void mergeSort(Object[] src,
	Object[] dest,
	int low, int high, int off,
	Comparator c) {
	int length = high - low;

	// Insertion sort on smallest arrays
	if (length < INSERTIONSORT_THRESHOLD) {
	for (int i=low; i<high; i++)
	for (int j=i; j>low && c.compare(dest[j-1], dest[j])>0; j--)
	swap(dest, j, j-1);
	return;
	}

	// Recursively sort halves of dest into src
	int destLow = low;
	int destHigh = high;
	low += off;
	high += off;
	int mid = (low + high) >>> 1;
	mergeSort(dest, src, low, mid, -off, c);
	mergeSort(dest, src, mid, high, -off, c);

	// If list is already sorted, just copy from src to dest. This is an
	// optimization that results in faster sorts for nearly ordered lists.
	if (c.compare(src[mid-1], src[mid]) <= 0) {
	System.arraycopy(src, low, dest, destLow, length);
	return;
	}

	// Merge sorted halves (now in src) into dest
	for(int i = destLow, p = low, q = mid; i < destHigh; i++) {
	if (q >= high \|\| p < mid && c.compare(src[p], src[q]) <= 0)
	dest[i] = src[p++];
	else
	dest[i] = src[q++];
	}
	}

	// Parallel prefix

	/**
	* Cumulates, in parallel, each element of the given array in place,
	* using the supplied function. For example if the array initially
	* holds {@code [2, 1, 0, 3]} and the operation performs addition,
	* then upon return the array holds {@code [2, 3, 3, 6]}.
	* Parallel prefix computation is usually more efficient than
	* sequential loops for large arrays.
	*
	* @param <T> the class of the objects in the array
	* @param array the array, which is modified in-place by this method
	* @param op a side-effect-free, associative function to perform the
	* cumulation
	* @throws NullPointerException if the specified array or function is null
	* @since 1.8
	*/
	public static <T> void parallelPrefix(T[] array, BinaryOperator<T> op) {
	Objects.requireNonNull(op);
	if (array.length > 0)
	new ArrayPrefixHelpers.CumulateTask<>
	(null, op, array, 0, array.length).invoke();
	}

	/**
	* Performs {@link #parallelPrefix(Object[], BinaryOperator)}
	* for the given subrange of the array.
	*
	* @param <T> the class of the objects in the array
	* @param array the array
	* @param fromIndex the index of the first element, inclusive
	* @param toIndex the index of the last element, exclusive
	* @param op a side-effect-free, associative function to perform the
	* cumulation
	* @throws IllegalArgumentException if {@code fromIndex > toIndex}
	* @throws ArrayIndexOutOfBoundsException
	* if {@code fromIndex < 0} or {@code toIndex > array.length}
	* @throws NullPointerException if the specified array or function is null
	* @since 1.8
	*/
	public static <T> void parallelPrefix(T[] array, int fromIndex,
	int toIndex, BinaryOperator<T> op) {
	Objects.requireNonNull(op);
	rangeCheck(array.length, fromIndex, toIndex);
	if (fromIndex < toIndex)
	new ArrayPrefixHelpers.CumulateTask<>
	(null, op, array, fromIndex, toIndex).invoke();
	}

	/**
	* Cumulates, in parallel, each element of the given array in place,
	* using the supplied function. For example if the array initially
	* holds {@code [2, 1, 0, 3]} and the operation performs addition,
	* then upon return the array holds {@code [2, 3, 3, 6]}.
	* Parallel prefix computation is usually more efficient than
	* sequential loops for large arrays.
	*
	* @param array the array, which is modified in-place by this method
	* @param op a side-effect-free, associative function to perform the
	* cumulation
	* @throws NullPointerException if the specified array or function is null
	* @since 1.8
	*/
	public static void parallelPrefix(long[] array, LongBinaryOperator op) {
	Objects.requireNonNull(op);
	if (array.length > 0)
	new ArrayPrefixHelpers.LongCumulateTask
	(null, op, array, 0, array.length).invoke();
	}

	/**
	* Performs {@link #parallelPrefix(long[], LongBinaryOperator)}
	* for the given subrange of the array.
	*
	* @param array the array
	* @param fromIndex the index of the first element, inclusive
	* @param toIndex the index of the last element, exclusive
	* @param op a side-effect-free, associative function to perform the
	* cumulation
	* @throws IllegalArgumentException if {@code fromIndex > toIndex}
	* @throws ArrayIndexOutOfBoundsException
	* if {@code fromIndex < 0} or {@code toIndex > array.length}
	* @throws NullPointerException if the specified array or function is null
	* @since 1.8
	*/
	public static void parallelPrefix(long[] array, int fromIndex,
	int toIndex, LongBinaryOperator op) {
	Objects.requireNonNull(op);
	rangeCheck(array.length, fromIndex, toIndex);
	if (fromIndex < toIndex)
	new ArrayPrefixHelpers.LongCumulateTask
	(null, op, array, fromIndex, toIndex).invoke();
	}

	/**
	* Cumulates, in parallel, each element of the given array in place,
	* using the supplied function. For example if the array initially
	* holds {@code [2.0, 1.0, 0.0, 3.0]} and the operation performs addition,
	* then upon return the array holds {@code [2.0, 3.0, 3.0, 6.0]}.
	* Parallel prefix computation is usually more efficient than
	* sequential loops for large arrays.
	*
	* <p> Because floating-point operations may not be strictly associative,
	* the returned result may not be identical to the value that would be
	* obtained if the operation was performed sequentially.
	*
	* @param array the array, which is modified in-place by this method
	* @param op a side-effect-free function to perform the cumulation
	* @throws NullPointerException if the specified array or function is null
	* @since 1.8
	*/
	public static void parallelPrefix(double[] array, DoubleBinaryOperator op) {
	Objects.requireNonNull(op);
	if (array.length > 0)
	new ArrayPrefixHelpers.DoubleCumulateTask
	(null, op, array, 0, array.length).invoke();
	}

	/**
	* Performs {@link #parallelPrefix(double[], DoubleBinaryOperator)}
	* for the given subrange of the array.
	*
	* @param array the array
	* @param fromIndex the index of the first element, inclusive
	* @param toIndex the index of the last element, exclusive
	* @param op a side-effect-free, associative function to perform the
	* cumulation
	* @throws IllegalArgumentException if {@code fromIndex > toIndex}
	* @throws ArrayIndexOutOfBoundsException
	* if {@code fromIndex < 0} or {@code toIndex > array.length}
	* @throws NullPointerException if the specified array or function is null
	* @since 1.8
	*/
	public static void parallelPrefix(double[] array, int fromIndex,
	int toIndex, DoubleBinaryOperator op) {
	Objects.requireNonNull(op);
	rangeCheck(array.length, fromIndex, toIndex);
	if (fromIndex < toIndex)
	new ArrayPrefixHelpers.DoubleCumulateTask
	(null, op, array, fromIndex, toIndex).invoke();
	}

	/**
	* Cumulates, in parallel, each element of the given array in place,
	* using the supplied function. For example if the array initially
	* holds {@code [2, 1, 0, 3]} and the operation performs addition,
	* then upon return the array holds {@code [2, 3, 3, 6]}.
	* Parallel prefix computation is usually more efficient than
	* sequential loops for large arrays.
	*
	* @param array the array, which is modified in-place by this method
	* @param op a side-effect-free, associative function to perform the
	* cumulation
	* @throws NullPointerException if the specified array or function is null
	* @since 1.8
	*/
	public static void parallelPrefix(int[] array, IntBinaryOperator op) {
	Objects.requireNonNull(op);
	if (array.length > 0)
	new ArrayPrefixHelpers.IntCumulateTask
	(null, op, array, 0, array.length).invoke();
	}

	/**
	* Performs {@link #parallelPrefix(int[], IntBinaryOperator)}
	* for the given subrange of the array.
	*
	* @param array the array
	* @param fromIndex the index of the first element, inclusive
	* @param toIndex the index of the last element, exclusive
	* @param op a side-effect-free, associative function to perform the
	* cumulation
	* @throws IllegalArgumentException if {@code fromIndex > toIndex}
	* @throws ArrayIndexOutOfBoundsException
	* if {@code fromIndex < 0} or {@code toIndex > array.length}
	* @throws NullPointerException if the specified array or function is null
	* @since 1.8
	*/
	public static void parallelPrefix(int[] array, int fromIndex,
	int toIndex, IntBinaryOperator op) {
	Objects.requireNonNull(op);
	rangeCheck(array.length, fromIndex, toIndex);
	if (fromIndex < toIndex)
	new ArrayPrefixHelpers.IntCumulateTask
	(null, op, array, fromIndex, toIndex).invoke();
	}

	// Searching

	/**
	* Searches the specified array of longs for the specified value using the
	* binary search algorithm. The array must be sorted (as
	* by the {@link #sort(long[])} method) prior to making this call. If it
	* is not sorted, the results are undefined. If the array contains
	* multiple elements with the specified value, there is no guarantee which
	* one will be found.
	*
	* @param a the array to be searched
	* @param key the value to be searched for
	* @return index of the search key, if it is contained in the array;
	* otherwise, <code>(-(<i>insertion point</i>) - 1)</code>. The
	* <i>insertion point</i> is defined as the point at which the
	* key would be inserted into the array: the index of the first
	* element greater than the key, or {@code a.length} if all
	* elements in the array are less than the specified key. Note
	* that this guarantees that the return value will be >= 0 if
	* and only if the key is found.
	*/
	public static int binarySearch(long[] a, long key) {
	return binarySearch0(a, 0, a.length, key);
	}

	/**
	* Searches a range of
	* the specified array of longs for the specified value using the
	* binary search algorithm.
	* The range must be sorted (as
	* by the {@link #sort(long[], int, int)} method)
	* prior to making this call. If it
	* is not sorted, the results are undefined. If the range contains
	* multiple elements with the specified value, there is no guarantee which
	* one will be found.
	*
	* @param a the array to be searched
	* @param fromIndex the index of the first element (inclusive) to be
	* searched
	* @param toIndex the index of the last element (exclusive) to be searched
	* @param key the value to be searched for
	* @return index of the search key, if it is contained in the array
	* within the specified range;
	* otherwise, <code>(-(<i>insertion point</i>) - 1)</code>. The
	* <i>insertion point</i> is defined as the point at which the
	* key would be inserted into the array: the index of the first
	* element in the range greater than the key,
	* or {@code toIndex} if all
	* elements in the range are less than the specified key. Note
	* that this guarantees that the return value will be >= 0 if
	* and only if the key is found.
	* @throws IllegalArgumentException
	* if {@code fromIndex > toIndex}
	* @throws ArrayIndexOutOfBoundsException
	* if {@code fromIndex < 0 or toIndex > a.length}
	* @since 1.6
	*/
	public static int binarySearch(long[] a, int fromIndex, int toIndex,
	long key) {
	rangeCheck(a.length, fromIndex, toIndex);
	return binarySearch0(a, fromIndex, toIndex, key);
	}

	// Like public version, but without range checks.
	private static int binarySearch0(long[] a, int fromIndex, int toIndex,
	long key) {
	int low = fromIndex;
	int high = toIndex - 1;

	while (low <= high) {
	int mid = (low + high) >>> 1;
	long midVal = a[mid];

	if (midVal < key)
	low = mid + 1;
	else if (midVal > key)
	high = mid - 1;
	else
	return mid; // key found
	}
	return -(low + 1); // key not found.
	}

	/**
	* Searches the specified array of ints for the specified value using the
	* binary search algorithm. The array must be sorted (as
	* by the {@link #sort(int[])} method) prior to making this call. If it
	* is not sorted, the results are undefined. If the array contains
	* multiple elements with the specified value, there is no guarantee which
	* one will be found.
	*
	* @param a the array to be searched
	* @param key the value to be searched for
	* @return index of the search key, if it is contained in the array;
	* otherwise, <code>(-(<i>insertion point</i>) - 1)</code>. The
	* <i>insertion point</i> is defined as the point at which the
	* key would be inserted into the array: the index of the first
	* element greater than the key, or {@code a.length} if all
	* elements in the array are less than the specified key. Note
	* that this guarantees that the return value will be >= 0 if
	* and only if the key is found.
	*/
	public static int binarySearch(int[] a, int key) {
	return binarySearch0(a, 0, a.length, key);
	}

	/**
	* Searches a range of
	* the specified array of ints for the specified value using the
	* binary search algorithm.
	* The range must be sorted (as
	* by the {@link #sort(int[], int, int)} method)
	* prior to making this call. If it
	* is not sorted, the results are undefined. If the range contains
	* multiple elements with the specified value, there is no guarantee which
	* one will be found.
	*
	* @param a the array to be searched
	* @param fromIndex the index of the first element (inclusive) to be
	* searched
	* @param toIndex the index of the last element (exclusive) to be searched
	* @param key the value to be searched for
	* @return index of the search key, if it is contained in the array
	* within the specified range;
	* otherwise, <code>(-(<i>insertion point</i>) - 1)</code>. The
	* <i>insertion point</i> is defined as the point at which the
	* key would be inserted into the array: the index of the first
	* element in the range greater than the key,
	* or {@code toIndex} if all
	* elements in the range are less than the specified key. Note
	* that this guarantees that the return value will be >= 0 if
	* and only if the key is found.
	* @throws IllegalArgumentException
	* if {@code fromIndex > toIndex}
	* @throws ArrayIndexOutOfBoundsException
	* if {@code fromIndex < 0 or toIndex > a.length}
	* @since 1.6
	*/
	public static int binarySearch(int[] a, int fromIndex, int toIndex,
	int key) {
	rangeCheck(a.length, fromIndex, toIndex);
	return binarySearch0(a, fromIndex, toIndex, key);
	}

	// Like public version, but without range checks.
	private static int binarySearch0(int[] a, int fromIndex, int toIndex,
	int key) {
	int low = fromIndex;
	int high = toIndex - 1;

	while (low <= high) {
	int mid = (low + high) >>> 1;
	int midVal = a[mid];

	if (midVal < key)
	low = mid + 1;
	else if (midVal > key)
	high = mid - 1;
	else
	return mid; // key found
	}
	return -(low + 1); // key not found.
	}

	/**
	* Searches the specified array of shorts for the specified value using
	* the binary search algorithm. The array must be sorted
	* (as by the {@link #sort(short[])} method) prior to making this call. If
	* it is not sorted, the results are undefined. If the array contains
	* multiple elements with the specified value, there is no guarantee which
	* one will be found.
	*
	* @param a the array to be searched
	* @param key the value to be searched for
	* @return index of the search key, if it is contained in the array;
	* otherwise, <code>(-(<i>insertion point</i>) - 1)</code>. The
	* <i>insertion point</i> is defined as the point at which the
	* key would be inserted into the array: the index of the first
	* element greater than the key, or {@code a.length} if all
	* elements in the array are less than the specified key. Note
	* that this guarantees that the return value will be >= 0 if
	* and only if the key is found.
	*/
	public static int binarySearch(short[] a, short key) {
	return binarySearch0(a, 0, a.length, key);
	}

	/**
	* Searches a range of
	* the specified array of shorts for the specified value using
	* the binary search algorithm.
	* The range must be sorted
	* (as by the {@link #sort(short[], int, int)} method)
	* prior to making this call. If
	* it is not sorted, the results are undefined. If the range contains
	* multiple elements with the specified value, there is no guarantee which
	* one will be found.
	*
	* @param a the array to be searched
	* @param fromIndex the index of the first element (inclusive) to be
	* searched
	* @param toIndex the index of the last element (exclusive) to be searched
	* @param key the value to be searched for
	* @return index of the search key, if it is contained in the array
	* within the specified range;
	* otherwise, <code>(-(<i>insertion point</i>) - 1)</code>. The
	* <i>insertion point</i> is defined as the point at which the
	* key would be inserted into the array: the index of the first
	* element in the range greater than the key,
	* or {@code toIndex} if all
	* elements in the range are less than the specified key. Note
	* that this guarantees that the return value will be >= 0 if
	* and only if the key is found.
	* @throws IllegalArgumentException
	* if {@code fromIndex > toIndex}
	* @throws ArrayIndexOutOfBoundsException
	* if {@code fromIndex < 0 or toIndex > a.length}
	* @since 1.6
	*/
	public static int binarySearch(short[] a, int fromIndex, int toIndex,
	short key) {
	rangeCheck(a.length, fromIndex, toIndex);
	return binarySearch0(a, fromIndex, toIndex, key);
	}

	// Like public version, but without range checks.
	private static int binarySearch0(short[] a, int fromIndex, int toIndex,
	short key) {
	int low = fromIndex;
	int high = toIndex - 1;

	while (low <= high) {
	int mid = (low + high) >>> 1;
	short midVal = a[mid];

	if (midVal < key)
	low = mid + 1;
	else if (midVal > key)
	high = mid - 1;
	else
	return mid; // key found
	}
	return -(low + 1); // key not found.
	}

	/**
	* Searches the specified array of chars for the specified value using the
	* binary search algorithm. The array must be sorted (as
	* by the {@link #sort(char[])} method) prior to making this call. If it
	* is not sorted, the results are undefined. If the array contains
	* multiple elements with the specified value, there is no guarantee which
	* one will be found.
	*
	* @param a the array to be searched
	* @param key the value to be searched for
	* @return index of the search key, if it is contained in the array;
	* otherwise, <code>(-(<i>insertion point</i>) - 1)</code>. The
	* <i>insertion point</i> is defined as the point at which the
	* key would be inserted into the array: the index of the first
	* element greater than the key, or {@code a.length} if all
	* elements in the array are less than the specified key. Note
	* that this guarantees that the return value will be >= 0 if
	* and only if the key is found.
	*/
	public static int binarySearch(char[] a, char key) {
	return binarySearch0(a, 0, a.length, key);
	}

	/**
	* Searches a range of
	* the specified array of chars for the specified value using the
	* binary search algorithm.
	* The range must be sorted (as
	* by the {@link #sort(char[], int, int)} method)
	* prior to making this call. If it
	* is not sorted, the results are undefined. If the range contains
	* multiple elements with the specified value, there is no guarantee which
	* one will be found.
	*
	* @param a the array to be searched
	* @param fromIndex the index of the first element (inclusive) to be
	* searched
	* @param toIndex the index of the last element (exclusive) to be searched
	* @param key the value to be searched for
	* @return index of the search key, if it is contained in the array
	* within the specified range;
	* otherwise, <code>(-(<i>insertion point</i>) - 1)</code>. The
	* <i>insertion point</i> is defined as the point at which the
	* key would be inserted into the array: the index of the first
	* element in the range greater than the key,
	* or {@code toIndex} if all
	* elements in the range are less than the specified key. Note
	* that this guarantees that the return value will be >= 0 if
	* and only if the key is found.
	* @throws IllegalArgumentException
	* if {@code fromIndex > toIndex}
	* @throws ArrayIndexOutOfBoundsException
	* if {@code fromIndex < 0 or toIndex > a.length}
	* @since 1.6
	*/
	public static int binarySearch(char[] a, int fromIndex, int toIndex,
	char key) {
	rangeCheck(a.length, fromIndex, toIndex);
	return binarySearch0(a, fromIndex, toIndex, key);
	}

	// Like public version, but without range checks.
	private static int binarySearch0(char[] a, int fromIndex, int toIndex,
	char key) {
	int low = fromIndex;
	int high = toIndex - 1;

	while (low <= high) {
	int mid = (low + high) >>> 1;
	char midVal = a[mid];

	if (midVal < key)
	low = mid + 1;
	else if (midVal > key)
	high = mid - 1;
	else
	return mid; // key found
	}
	return -(low + 1); // key not found.
	}

	/**
	* Searches the specified array of bytes for the specified value using the
	* binary search algorithm. The array must be sorted (as
	* by the {@link #sort(byte[])} method) prior to making this call. If it
	* is not sorted, the results are undefined. If the array contains
	* multiple elements with the specified value, there is no guarantee which
	* one will be found.
	*
	* @param a the array to be searched
	* @param key the value to be searched for
	* @return index of the search key, if it is contained in the array;
	* otherwise, <code>(-(<i>insertion point</i>) - 1)</code>. The
	* <i>insertion point</i> is defined as the point at which the
	* key would be inserted into the array: the index of the first
	* element greater than the key, or {@code a.length} if all
	* elements in the array are less than the specified key. Note
	* that this guarantees that the return value will be >= 0 if
	* and only if the key is found.
	*/
	public static int binarySearch(byte[] a, byte key) {
	return binarySearch0(a, 0, a.length, key);
	}

	/**
	* Searches a range of
	* the specified array of bytes for the specified value using the
	* binary search algorithm.
	* The range must be sorted (as
	* by the {@link #sort(byte[], int, int)} method)
	* prior to making this call. If it
	* is not sorted, the results are undefined. If the range contains
	* multiple elements with the specified value, there is no guarantee which
	* one will be found.
	*
	* @param a the array to be searched
	* @param fromIndex the index of the first element (inclusive) to be
	* searched
	* @param toIndex the index of the last element (exclusive) to be searched
	* @param key the value to be searched for
	* @return index of the search key, if it is contained in the array
	* within the specified range;
	* otherwise, <code>(-(<i>insertion point</i>) - 1)</code>. The
	* <i>insertion point</i> is defined as the point at which the
	* key would be inserted into the array: the index of the first
	* element in the range greater than the key,
	* or {@code toIndex} if all
	* elements in the range are less than the specified key. Note
	* that this guarantees that the return value will be >= 0 if
	* and only if the key is found.
	* @throws IllegalArgumentException
	* if {@code fromIndex > toIndex}
	* @throws ArrayIndexOutOfBoundsException
	* if {@code fromIndex < 0 or toIndex > a.length}
	* @since 1.6
	*/
	public static int binarySearch(byte[] a, int fromIndex, int toIndex,
	byte key) {
	rangeCheck(a.length, fromIndex, toIndex);
	return binarySearch0(a, fromIndex, toIndex, key);
	}

	// Like public version, but without range checks.
	private static int binarySearch0(byte[] a, int fromIndex, int toIndex,
	byte key) {
	int low = fromIndex;
	int high = toIndex - 1;

	while (low <= high) {
	int mid = (low + high) >>> 1;
	byte midVal = a[mid];

	if (midVal < key)
	low = mid + 1;
	else if (midVal > key)
	high = mid - 1;
	else
	return mid; // key found
	}
	return -(low + 1); // key not found.
	}

	/**
	* Searches the specified array of doubles for the specified value using
	* the binary search algorithm. The array must be sorted
	* (as by the {@link #sort(double[])} method) prior to making this call.
	* If it is not sorted, the results are undefined. If the array contains
	* multiple elements with the specified value, there is no guarantee which
	* one will be found. This method considers all NaN values to be
	* equivalent and equal.
	*
	* @param a the array to be searched
	* @param key the value to be searched for
	* @return index of the search key, if it is contained in the array;
	* otherwise, <code>(-(<i>insertion point</i>) - 1)</code>. The
	* <i>insertion point</i> is defined as the point at which the
	* key would be inserted into the array: the index of the first
	* element greater than the key, or {@code a.length} if all
	* elements in the array are less than the specified key. Note
	* that this guarantees that the return value will be >= 0 if
	* and only if the key is found.
	*/
	public static int binarySearch(double[] a, double key) {
	return binarySearch0(a, 0, a.length, key);
	}

	/**
	* Searches a range of
	* the specified array of doubles for the specified value using
	* the binary search algorithm.
	* The range must be sorted
	* (as by the {@link #sort(double[], int, int)} method)
	* prior to making this call.
	* If it is not sorted, the results are undefined. If the range contains
	* multiple elements with the specified value, there is no guarantee which
	* one will be found. This method considers all NaN values to be
	* equivalent and equal.
	*
	* @param a the array to be searched
	* @param fromIndex the index of the first element (inclusive) to be
	* searched
	* @param toIndex the index of the last element (exclusive) to be searched
	* @param key the value to be searched for
	* @return index of the search key, if it is contained in the array
	* within the specified range;
	* otherwise, <code>(-(<i>insertion point</i>) - 1)</code>. The
	* <i>insertion point</i> is defined as the point at which the
	* key would be inserted into the array: the index of the first
	* element in the range greater than the key,
	* or {@code toIndex} if all
	* elements in the range are less than the specified key. Note
	* that this guarantees that the return value will be >= 0 if
	* and only if the key is found.
	* @throws IllegalArgumentException
	* if {@code fromIndex > toIndex}
	* @throws ArrayIndexOutOfBoundsException
	* if {@code fromIndex < 0 or toIndex > a.length}
	* @since 1.6
	*/
	public static int binarySearch(double[] a, int fromIndex, int toIndex,
	double key) {
	rangeCheck(a.length, fromIndex, toIndex);
	return binarySearch0(a, fromIndex, toIndex, key);
	}

	// Like public version, but without range checks.
	private static int binarySearch0(double[] a, int fromIndex, int toIndex,
	double key) {
	int low = fromIndex;
	int high = toIndex - 1;

	while (low <= high) {
	int mid = (low + high) >>> 1;
	double midVal = a[mid];

	if (midVal < key)
	low = mid + 1; // Neither val is NaN, thisVal is smaller
	else if (midVal > key)
	high = mid - 1; // Neither val is NaN, thisVal is larger
	else {
	long midBits = Double.doubleToLongBits(midVal);
	long keyBits = Double.doubleToLongBits(key);
	if (midBits == keyBits) // Values are equal
	return mid; // Key found
	else if (midBits < keyBits) // (-0.0, 0.0) or (!NaN, NaN)
	low = mid + 1;
	else // (0.0, -0.0) or (NaN, !NaN)
	high = mid - 1;
	}
	}
	return -(low + 1); // key not found.
	}

	/**
	* Searches the specified array of floats for the specified value using
	* the binary search algorithm. The array must be sorted
	* (as by the {@link #sort(float[])} method) prior to making this call. If
	* it is not sorted, the results are undefined. If the array contains
	* multiple elements with the specified value, there is no guarantee which
	* one will be found. This method considers all NaN values to be
	* equivalent and equal.
	*
	* @param a the array to be searched
	* @param key the value to be searched for
	* @return index of the search key, if it is contained in the array;
	* otherwise, <code>(-(<i>insertion point</i>) - 1)</code>. The
	* <i>insertion point</i> is defined as the point at which the
	* key would be inserted into the array: the index of the first
	* element greater than the key, or {@code a.length} if all
	* elements in the array are less than the specified key. Note
	* that this guarantees that the return value will be >= 0 if
	* and only if the key is found.
	*/
	public static int binarySearch(float[] a, float key) {
	return binarySearch0(a, 0, a.length, key);
	}

	/**
	* Searches a range of
	* the specified array of floats for the specified value using
	* the binary search algorithm.
	* The range must be sorted
	* (as by the {@link #sort(float[], int, int)} method)
	* prior to making this call. If
	* it is not sorted, the results are undefined. If the range contains
	* multiple elements with the specified value, there is no guarantee which
	* one will be found. This method considers all NaN values to be
	* equivalent and equal.
	*
	* @param a the array to be searched
	* @param fromIndex the index of the first element (inclusive) to be
	* searched
	* @param toIndex the index of the last element (exclusive) to be searched
	* @param key the value to be searched for
	* @return index of the search key, if it is contained in the array
	* within the specified range;
	* otherwise, <code>(-(<i>insertion point</i>) - 1)</code>. The
	* <i>insertion point</i> is defined as the point at which the
	* key would be inserted into the array: the index of the first
	* element in the range greater than the key,
	* or {@code toIndex} if all
	* elements in the range are less than the specified key. Note
	* that this guarantees that the return value will be >= 0 if
	* and only if the key is found.
	* @throws IllegalArgumentException
	* if {@code fromIndex > toIndex}
	* @throws ArrayIndexOutOfBoundsException
	* if {@code fromIndex < 0 or toIndex > a.length}
	* @since 1.6
	*/
	public static int binarySearch(float[] a, int fromIndex, int toIndex,
	float key) {
	rangeCheck(a.length, fromIndex, toIndex);
	return binarySearch0(a, fromIndex, toIndex, key);
	}

	// Like public version, but without range checks.
	private static int binarySearch0(float[] a, int fromIndex, int toIndex,
	float key) {
	int low = fromIndex;
	int high = toIndex - 1;

	while (low <= high) {
	int mid = (low + high) >>> 1;
	float midVal = a[mid];

	if (midVal < key)
	low = mid + 1; // Neither val is NaN, thisVal is smaller
	else if (midVal > key)
	high = mid - 1; // Neither val is NaN, thisVal is larger
	else {
	int midBits = Float.floatToIntBits(midVal);
	int keyBits = Float.floatToIntBits(key);
	if (midBits == keyBits) // Values are equal
	return mid; // Key found
	else if (midBits < keyBits) // (-0.0, 0.0) or (!NaN, NaN)
	low = mid + 1;
	else // (0.0, -0.0) or (NaN, !NaN)
	high = mid - 1;
	}
	}
	return -(low + 1); // key not found.
	}

	/**
	* Searches the specified array for the specified object using the binary
	* search algorithm. The array must be sorted into ascending order
	* according to the
	* {@linkplain Comparable natural ordering}
	* of its elements (as by the
	* {@link #sort(Object[])} method) prior to making this call.
	* If it is not sorted, the results are undefined.
	* (If the array contains elements that are not mutually comparable (for
	* example, strings and integers), it <i>cannot</i> be sorted according
	* to the natural ordering of its elements, hence results are undefined.)
	* If the array contains multiple
	* elements equal to the specified object, there is no guarantee which
	* one will be found.
	*
	* @param a the array to be searched
	* @param key the value to be searched for
	* @return index of the search key, if it is contained in the array;
	* otherwise, <code>(-(<i>insertion point</i>) - 1)</code>. The
	* <i>insertion point</i> is defined as the point at which the
	* key would be inserted into the array: the index of the first
	* element greater than the key, or {@code a.length} if all
	* elements in the array are less than the specified key. Note
	* that this guarantees that the return value will be >= 0 if
	* and only if the key is found.
	* @throws ClassCastException if the search key is not comparable to the
	* elements of the array.
	*/
	public static int binarySearch(Object[] a, Object key) {
	return binarySearch0(a, 0, a.length, key);
	}

	/**
	* Searches a range of
	* the specified array for the specified object using the binary
	* search algorithm.
	* The range must be sorted into ascending order
	* according to the
	* {@linkplain Comparable natural ordering}
	* of its elements (as by the
	* {@link #sort(Object[], int, int)} method) prior to making this
	* call. If it is not sorted, the results are undefined.
	* (If the range contains elements that are not mutually comparable (for
	* example, strings and integers), it <i>cannot</i> be sorted according
	* to the natural ordering of its elements, hence results are undefined.)
	* If the range contains multiple
	* elements equal to the specified object, there is no guarantee which
	* one will be found.
	*
	* @param a the array to be searched
	* @param fromIndex the index of the first element (inclusive) to be
	* searched
	* @param toIndex the index of the last element (exclusive) to be searched
	* @param key the value to be searched for
	* @return index of the search key, if it is contained in the array
	* within the specified range;
	* otherwise, <code>(-(<i>insertion point</i>) - 1)</code>. The
	* <i>insertion point</i> is defined as the point at which the
	* key would be inserted into the array: the index of the first
	* element in the range greater than the key,
	* or {@code toIndex} if all
	* elements in the range are less than the specified key. Note
	* that this guarantees that the return value will be >= 0 if
	* and only if the key is found.
	* @throws ClassCastException if the search key is not comparable to the
	* elements of the array within the specified range.
	* @throws IllegalArgumentException
	* if {@code fromIndex > toIndex}
	* @throws ArrayIndexOutOfBoundsException
	* if {@code fromIndex < 0 or toIndex > a.length}
	* @since 1.6
	*/
	public static int binarySearch(Object[] a, int fromIndex, int toIndex,
	Object key) {
	rangeCheck(a.length, fromIndex, toIndex);
	return binarySearch0(a, fromIndex, toIndex, key);
	}

	// Like public version, but without range checks.
	private static int binarySearch0(Object[] a, int fromIndex, int toIndex,
	Object key) {
	int low = fromIndex;
	int high = toIndex - 1;

	while (low <= high) {
	int mid = (low + high) >>> 1;
	@SuppressWarnings("rawtypes")
	Comparable midVal = (Comparable)a[mid];
	@SuppressWarnings("unchecked")
	int cmp = midVal.compareTo(key);

	if (cmp < 0)
	low = mid + 1;
	else if (cmp > 0)
	high = mid - 1;
	else
	return mid; // key found
	}
	return -(low + 1); // key not found.
	}

	/**
	* Searches the specified array for the specified object using the binary
	* search algorithm. The array must be sorted into ascending order
	* according to the specified comparator (as by the
	* {@link #sort(Object[], Comparator) sort(T[], Comparator)}
	* method) prior to making this call. If it is
	* not sorted, the results are undefined.
	* If the array contains multiple
	* elements equal to the specified object, there is no guarantee which one
	* will be found.
	*
	* @param <T> the class of the objects in the array
	* @param a the array to be searched
	* @param key the value to be searched for
	* @param c the comparator by which the array is ordered. A
	* {@code null} value indicates that the elements'
	* {@linkplain Comparable natural ordering} should be used.
	* @return index of the search key, if it is contained in the array;
	* otherwise, <code>(-(<i>insertion point</i>) - 1)</code>. The
	* <i>insertion point</i> is defined as the point at which the
	* key would be inserted into the array: the index of the first
	* element greater than the key, or {@code a.length} if all
	* elements in the array are less than the specified key. Note
	* that this guarantees that the return value will be >= 0 if
	* and only if the key is found.
	* @throws ClassCastException if the array contains elements that are not
	* <i>mutually comparable</i> using the specified comparator,
	* or the search key is not comparable to the
	* elements of the array using this comparator.
	*/
	public static <T> int binarySearch(T[] a, T key, Comparator<? super T> c) {
	return binarySearch0(a, 0, a.length, key, c);
	}

	/**
	* Searches a range of
	* the specified array for the specified object using the binary
	* search algorithm.
	* The range must be sorted into ascending order
	* according to the specified comparator (as by the
	* {@link #sort(Object[], int, int, Comparator)
	* sort(T[], int, int, Comparator)}
	* method) prior to making this call.
	* If it is not sorted, the results are undefined.
	* If the range contains multiple elements equal to the specified object,
	* there is no guarantee which one will be found.
	*
	* @param <T> the class of the objects in the array
	* @param a the array to be searched
	* @param fromIndex the index of the first element (inclusive) to be
	* searched
	* @param toIndex the index of the last element (exclusive) to be searched
	* @param key the value to be searched for
	* @param c the comparator by which the array is ordered. A
	* {@code null} value indicates that the elements'
	* {@linkplain Comparable natural ordering} should be used.
	* @return index of the search key, if it is contained in the array
	* within the specified range;
	* otherwise, <code>(-(<i>insertion point</i>) - 1)</code>. The
	* <i>insertion point</i> is defined as the point at which the
	* key would be inserted into the array: the index of the first
	* element in the range greater than the key,
	* or {@code toIndex} if all
	* elements in the range are less than the specified key. Note
	* that this guarantees that the return value will be >= 0 if
	* and only if the key is found.
	* @throws ClassCastException if the range contains elements that are not
	* <i>mutually comparable</i> using the specified comparator,
	* or the search key is not comparable to the
	* elements in the range using this comparator.
	* @throws IllegalArgumentException
	* if {@code fromIndex > toIndex}
	* @throws ArrayIndexOutOfBoundsException
	* if {@code fromIndex < 0 or toIndex > a.length}
	* @since 1.6
	*/
	public static <T> int binarySearch(T[] a, int fromIndex, int toIndex,
	T key, Comparator<? super T> c) {
	rangeCheck(a.length, fromIndex, toIndex);
	return binarySearch0(a, fromIndex, toIndex, key, c);
	}

	// Like public version, but without range checks.
	private static <T> int binarySearch0(T[] a, int fromIndex, int toIndex,
	T key, Comparator<? super T> c) {
	if (c == null) {
	return binarySearch0(a, fromIndex, toIndex, key);
	}
	int low = fromIndex;
	int high = toIndex - 1;

	while (low <= high) {
	int mid = (low + high) >>> 1;
	T midVal = a[mid];
	int cmp = c.compare(midVal, key);
	if (cmp < 0)
	low = mid + 1;
	else if (cmp > 0)
	high = mid - 1;
	else
	return mid; // key found
	}
	return -(low + 1); // key not found.
	}

	// Equality Testing

	/**
	* Returns {@code true} if the two specified arrays of longs are
	* <i>equal</i> to one another. Two arrays are considered equal if both
	* arrays contain the same number of elements, and all corresponding pairs
	* of elements in the two arrays are equal. In other words, two arrays
	* are equal if they contain the same elements in the same order. Also,
	* two array references are considered equal if both are {@code null}.
	*
	* @param a one array to be tested for equality
	* @param a2 the other array to be tested for equality
	* @return {@code true} if the two arrays are equal
	*/
	public static boolean equals(long[] a, long[] a2) {
	if (a==a2)
	return true;
	if (a==null \|\| a2==null)
	return false;

	int length = a.length;
	if (a2.length != length)
	return false;

	return ArraysSupport.mismatch(a, a2, length) < 0;
	}

	/**
	* Returns true if the two specified arrays of longs, over the specified
	* ranges, are <i>equal</i> to one another.
	*
	* <p>Two arrays are considered equal if the number of elements covered by
	* each range is the same, and all corresponding pairs of elements over the
	* specified ranges in the two arrays are equal. In other words, two arrays
	* are equal if they contain, over the specified ranges, the same elements
	* in the same order.
	*
	* @param a the first array to be tested for equality
	* @param aFromIndex the index (inclusive) of the first element in the
	* first array to be tested
	* @param aToIndex the index (exclusive) of the last element in the
	* first array to be tested
	* @param b the second array to be tested for equality
	* @param bFromIndex the index (inclusive) of the first element in the
	* second array to be tested
	* @param bToIndex the index (exclusive) of the last element in the
	* second array to be tested
	* @return {@code true} if the two arrays, over the specified ranges, are
	* equal
	* @throws IllegalArgumentException
	* if {@code aFromIndex > aToIndex} or
	* if {@code bFromIndex > bToIndex}
	* @throws ArrayIndexOutOfBoundsException
	* if {@code aFromIndex < 0 or aToIndex > a.length} or
	* if {@code bFromIndex < 0 or bToIndex > b.length}
	* @throws NullPointerException
	* if either array is {@code null}
	* @since 9
	*/
	public static boolean equals(long[] a, int aFromIndex, int aToIndex,
	long[] b, int bFromIndex, int bToIndex) {
	rangeCheck(a.length, aFromIndex, aToIndex);
	rangeCheck(b.length, bFromIndex, bToIndex);

	int aLength = aToIndex - aFromIndex;
	int bLength = bToIndex - bFromIndex;
	if (aLength != bLength)
	return false;

	return ArraysSupport.mismatch(a, aFromIndex,
	b, bFromIndex,
	aLength) < 0;
	}

	/**
	* Returns {@code true} if the two specified arrays of ints are
	* <i>equal</i> to one another. Two arrays are considered equal if both
	* arrays contain the same number of elements, and all corresponding pairs
	* of elements in the two arrays are equal. In other words, two arrays
	* are equal if they contain the same elements in the same order. Also,
	* two array references are considered equal if both are {@code null}.
	*
	* @param a one array to be tested for equality
	* @param a2 the other array to be tested for equality
	* @return {@code true} if the two arrays are equal
	*/
	public static boolean equals(int[] a, int[] a2) {
	if (a==a2)
	return true;
	if (a==null \|\| a2==null)
	return false;

	int length = a.length;
	if (a2.length != length)
	return false;

	return ArraysSupport.mismatch(a, a2, length) < 0;
	}

	/**
	* Returns true if the two specified arrays of ints, over the specified
	* ranges, are <i>equal</i> to one another.
	*
	* <p>Two arrays are considered equal if the number of elements covered by
	* each range is the same, and all corresponding pairs of elements over the
	* specified ranges in the two arrays are equal. In other words, two arrays
	* are equal if they contain, over the specified ranges, the same elements
	* in the same order.
	*
	* @param a the first array to be tested for equality
	* @param aFromIndex the index (inclusive) of the first element in the
	* first array to be tested
	* @param aToIndex the index (exclusive) of the last element in the
	* first array to be tested
	* @param b the second array to be tested for equality
	* @param bFromIndex the index (inclusive) of the first element in the
	* second array to be tested
	* @param bToIndex the index (exclusive) of the last element in the
	* second array to be tested
	* @return {@code true} if the two arrays, over the specified ranges, are
	* equal
	* @throws IllegalArgumentException
	* if {@code aFromIndex > aToIndex} or
	* if {@code bFromIndex > bToIndex}
	* @throws ArrayIndexOutOfBoundsException
	* if {@code aFromIndex < 0 or aToIndex > a.length} or
	* if {@code bFromIndex < 0 or bToIndex > b.length}
	* @throws NullPointerException
	* if either array is {@code null}
	* @since 9
	*/
	public static boolean equals(int[] a, int aFromIndex, int aToIndex,
	int[] b, int bFromIndex, int bToIndex) {
	rangeCheck(a.length, aFromIndex, aToIndex);
	rangeCheck(b.length, bFromIndex, bToIndex);

	int aLength = aToIndex - aFromIndex;
	int bLength = bToIndex - bFromIndex;
	if (aLength != bLength)
	return false;

	return ArraysSupport.mismatch(a, aFromIndex,
	b, bFromIndex,
	aLength) < 0;
	}

	/**
	* Returns {@code true} if the two specified arrays of shorts are
	* <i>equal</i> to one another. Two arrays are considered equal if both
	* arrays contain the same number of elements, and all corresponding pairs
	* of elements in the two arrays are equal. In other words, two arrays
	* are equal if they contain the same elements in the same order. Also,
	* two array references are considered equal if both are {@code null}.
	*
	* @param a one array to be tested for equality
	* @param a2 the other array to be tested for equality
	* @return {@code true} if the two arrays are equal
	*/
	public static boolean equals(short[] a, short a2[]) {
	if (a==a2)
	return true;
	if (a==null \|\| a2==null)
	return false;

	int length = a.length;
	if (a2.length != length)
	return false;

	return ArraysSupport.mismatch(a, a2, length) < 0;
	}

	/**
	* Returns true if the two specified arrays of shorts, over the specified
	* ranges, are <i>equal</i> to one another.
	*
	* <p>Two arrays are considered equal if the number of elements covered by
	* each range is the same, and all corresponding pairs of elements over the
	* specified ranges in the two arrays are equal. In other words, two arrays
	* are equal if they contain, over the specified ranges, the same elements
	* in the same order.
	*
	* @param a the first array to be tested for equality
	* @param aFromIndex the index (inclusive) of the first element in the
	* first array to be tested
	* @param aToIndex the index (exclusive) of the last element in the
	* first array to be tested
	* @param b the second array to be tested for equality
	* @param bFromIndex the index (inclusive) of the first element in the
	* second array to be tested
	* @param bToIndex the index (exclusive) of the last element in the
	* second array to be tested
	* @return {@code true} if the two arrays, over the specified ranges, are
	* equal
	* @throws IllegalArgumentException
	* if {@code aFromIndex > aToIndex} or
	* if {@code bFromIndex > bToIndex}
	* @throws ArrayIndexOutOfBoundsException
	* if {@code aFromIndex < 0 or aToIndex > a.length} or
	* if {@code bFromIndex < 0 or bToIndex > b.length}
	* @throws NullPointerException
	* if either array is {@code null}
	* @since 9
	*/
	public static boolean equals(short[] a, int aFromIndex, int aToIndex,
	short[] b, int bFromIndex, int bToIndex) {
	rangeCheck(a.length, aFromIndex, aToIndex);
	rangeCheck(b.length, bFromIndex, bToIndex);

	int aLength = aToIndex - aFromIndex;
	int bLength = bToIndex - bFromIndex;
	if (aLength != bLength)
	return false;

	return ArraysSupport.mismatch(a, aFromIndex,
	b, bFromIndex,
	aLength) < 0;
	}

	/**
	* Returns {@code true} if the two specified arrays of chars are
	* <i>equal</i> to one another. Two arrays are considered equal if both
	* arrays contain the same number of elements, and all corresponding pairs
	* of elements in the two arrays are equal. In other words, two arrays
	* are equal if they contain the same elements in the same order. Also,
	* two array references are considered equal if both are {@code null}.
	*
	* @param a one array to be tested for equality
	* @param a2 the other array to be tested for equality
	* @return {@code true} if the two arrays are equal
	*/
	@IntrinsicCandidate
	public static boolean equals(char[] a, char[] a2) {
	if (a==a2)
	return true;
	if (a==null \|\| a2==null)
	return false;

	int length = a.length;
	if (a2.length != length)
	return false;

	return ArraysSupport.mismatch(a, a2, length) < 0;
	}

	/**
	* Returns true if the two specified arrays of chars, over the specified
	* ranges, are <i>equal</i> to one another.
	*
	* <p>Two arrays are considered equal if the number of elements covered by
	* each range is the same, and all corresponding pairs of elements over the
	* specified ranges in the two arrays are equal. In other words, two arrays
	* are equal if they contain, over the specified ranges, the same elements
	* in the same order.
	*
	* @param a the first array to be tested for equality
	* @param aFromIndex the index (inclusive) of the first element in the
	* first array to be tested
	* @param aToIndex the index (exclusive) of the last element in the
	* first array to be tested
	* @param b the second array to be tested for equality
	* @param bFromIndex the index (inclusive) of the first element in the
	* second array to be tested
	* @param bToIndex the index (exclusive) of the last element in the
	* second array to be tested
	* @return {@code true} if the two arrays, over the specified ranges, are
	* equal
	* @throws IllegalArgumentException
	* if {@code aFromIndex > aToIndex} or
	* if {@code bFromIndex > bToIndex}
	* @throws ArrayIndexOutOfBoundsException
	* if {@code aFromIndex < 0 or aToIndex > a.length} or
	* if {@code bFromIndex < 0 or bToIndex > b.length}
	* @throws NullPointerException
	* if either array is {@code null}
	* @since 9
	*/
	public static boolean equals(char[] a, int aFromIndex, int aToIndex,
	char[] b, int bFromIndex, int bToIndex) {
	rangeCheck(a.length, aFromIndex, aToIndex);
	rangeCheck(b.length, bFromIndex, bToIndex);

	int aLength = aToIndex - aFromIndex;
	int bLength = bToIndex - bFromIndex;
	if (aLength != bLength)
	return false;

	return ArraysSupport.mismatch(a, aFromIndex,
	b, bFromIndex,
	aLength) < 0;
	}

	/**
	* Returns {@code true} if the two specified arrays of bytes are
	* <i>equal</i> to one another. Two arrays are considered equal if both
	* arrays contain the same number of elements, and all corresponding pairs
	* of elements in the two arrays are equal. In other words, two arrays
	* are equal if they contain the same elements in the same order. Also,
	* two array references are considered equal if both are {@code null}.
	*
	* @param a one array to be tested for equality
	* @param a2 the other array to be tested for equality
	* @return {@code true} if the two arrays are equal
	*/
	@IntrinsicCandidate
	public static boolean equals(byte[] a, byte[] a2) {
	if (a==a2)
	return true;
	if (a==null \|\| a2==null)
	return false;

	int length = a.length;
	if (a2.length != length)
	return false;

	return ArraysSupport.mismatch(a, a2, length) < 0;
	}

	/**
	* Returns true if the two specified arrays of bytes, over the specified
	* ranges, are <i>equal</i> to one another.
	*
	* <p>Two arrays are considered equal if the number of elements covered by
	* each range is the same, and all corresponding pairs of elements over the
	* specified ranges in the two arrays are equal. In other words, two arrays
	* are equal if they contain, over the specified ranges, the same elements
	* in the same order.
	*
	* @param a the first array to be tested for equality
	* @param aFromIndex the index (inclusive) of the first element in the
	* first array to be tested
	* @param aToIndex the index (exclusive) of the last element in the
	* first array to be tested
	* @param b the second array to be tested for equality
	* @param bFromIndex the index (inclusive) of the first element in the
	* second array to be tested
	* @param bToIndex the index (exclusive) of the last element in the
	* second array to be tested
	* @return {@code true} if the two arrays, over the specified ranges, are
	* equal
	* @throws IllegalArgumentException
	* if {@code aFromIndex > aToIndex} or
	* if {@code bFromIndex > bToIndex}
	* @throws ArrayIndexOutOfBoundsException
	* if {@code aFromIndex < 0 or aToIndex > a.length} or
	* if {@code bFromIndex < 0 or bToIndex > b.length}
	* @throws NullPointerException
	* if either array is {@code null}
	* @since 9
	*/
	public static boolean equals(byte[] a, int aFromIndex, int aToIndex,
	byte[] b, int bFromIndex, int bToIndex) {
	rangeCheck(a.length, aFromIndex, aToIndex);
	rangeCheck(b.length, bFromIndex, bToIndex);

	int aLength = aToIndex - aFromIndex;
	int bLength = bToIndex - bFromIndex;
	if (aLength != bLength)
	return false;

	return ArraysSupport.mismatch(a, aFromIndex,
	b, bFromIndex,
	aLength) < 0;
	}

	/**
	* Returns {@code true} if the two specified arrays of booleans are
	* <i>equal</i> to one another. Two arrays are considered equal if both
	* arrays contain the same number of elements, and all corresponding pairs
	* of elements in the two arrays are equal. In other words, two arrays
	* are equal if they contain the same elements in the same order. Also,
	* two array references are considered equal if both are {@code null}.
	*
	* @param a one array to be tested for equality
	* @param a2 the other array to be tested for equality
	* @return {@code true} if the two arrays are equal
	*/
	public static boolean equals(boolean[] a, boolean[] a2) {
	if (a==a2)
	return true;
	if (a==null \|\| a2==null)
	return false;

	int length = a.length;
	if (a2.length != length)
	return false;

	return ArraysSupport.mismatch(a, a2, length) < 0;
	}

	/**
	* Returns true if the two specified arrays of booleans, over the specified
	* ranges, are <i>equal</i> to one another.
	*
	* <p>Two arrays are considered equal if the number of elements covered by
	* each range is the same, and all corresponding pairs of elements over the
	* specified ranges in the two arrays are equal. In other words, two arrays
	* are equal if they contain, over the specified ranges, the same elements
	* in the same order.
	*
	* @param a the first array to be tested for equality
	* @param aFromIndex the index (inclusive) of the first element in the
	* first array to be tested
	* @param aToIndex the index (exclusive) of the last element in the
	* first array to be tested
	* @param b the second array to be tested for equality
	* @param bFromIndex the index (inclusive) of the first element in the
	* second array to be tested
	* @param bToIndex the index (exclusive) of the last element in the
	* second array to be tested
	* @return {@code true} if the two arrays, over the specified ranges, are
	* equal
	* @throws IllegalArgumentException
	* if {@code aFromIndex > aToIndex} or
	* if {@code bFromIndex > bToIndex}
	* @throws ArrayIndexOutOfBoundsException
	* if {@code aFromIndex < 0 or aToIndex > a.length} or
	* if {@code bFromIndex < 0 or bToIndex > b.length}
	* @throws NullPointerException
	* if either array is {@code null}
	* @since 9
	*/
	public static boolean equals(boolean[] a, int aFromIndex, int aToIndex,
	boolean[] b, int bFromIndex, int bToIndex) {
	rangeCheck(a.length, aFromIndex, aToIndex);
	rangeCheck(b.length, bFromIndex, bToIndex);

	int aLength = aToIndex - aFromIndex;
	int bLength = bToIndex - bFromIndex;
	if (aLength != bLength)
	return false;

	return ArraysSupport.mismatch(a, aFromIndex,
	b, bFromIndex,
	aLength) < 0;
	}

	/**
	* Returns {@code true} if the two specified arrays of doubles are
	* <i>equal</i> to one another. Two arrays are considered equal if both
	* arrays contain the same number of elements, and all corresponding pairs
	* of elements in the two arrays are equal. In other words, two arrays
	* are equal if they contain the same elements in the same order. Also,
	* two array references are considered equal if both are {@code null}.
	*
	* Two doubles {@code d1} and {@code d2} are considered equal if:
	* <pre> {@code new Double(d1).equals(new Double(d2))}</pre>
	* (Unlike the {@code ==} operator, this method considers
	* {@code NaN} equal to itself, and 0.0d unequal to -0.0d.)
	*
	* @param a one array to be tested for equality
	* @param a2 the other array to be tested for equality
	* @return {@code true} if the two arrays are equal
	* @see Double#equals(Object)
	*/
	public static boolean equals(double[] a, double[] a2) {
	if (a==a2)
	return true;
	if (a==null \|\| a2==null)
	return false;

	int length = a.length;
	if (a2.length != length)
	return false;

	return ArraysSupport.mismatch(a, a2, length) < 0;
	}

	/**
	* Returns true if the two specified arrays of doubles, over the specified
	* ranges, are <i>equal</i> to one another.
	*
	* <p>Two arrays are considered equal if the number of elements covered by
	* each range is the same, and all corresponding pairs of elements over the
	* specified ranges in the two arrays are equal. In other words, two arrays
	* are equal if they contain, over the specified ranges, the same elements
	* in the same order.
	*
	* <p>Two doubles {@code d1} and {@code d2} are considered equal if:
	* <pre> {@code new Double(d1).equals(new Double(d2))}</pre>
	* (Unlike the {@code ==} operator, this method considers
	* {@code NaN} equal to itself, and 0.0d unequal to -0.0d.)
	*
	* @param a the first array to be tested for equality
	* @param aFromIndex the index (inclusive) of the first element in the
	* first array to be tested
	* @param aToIndex the index (exclusive) of the last element in the
	* first array to be tested
	* @param b the second array to be tested for equality
	* @param bFromIndex the index (inclusive) of the first element in the
	* second array to be tested
	* @param bToIndex the index (exclusive) of the last element in the
	* second array to be tested
	* @return {@code true} if the two arrays, over the specified ranges, are
	* equal
	* @throws IllegalArgumentException
	* if {@code aFromIndex > aToIndex} or
	* if {@code bFromIndex > bToIndex}
	* @throws ArrayIndexOutOfBoundsException
	* if {@code aFromIndex < 0 or aToIndex > a.length} or
	* if {@code bFromIndex < 0 or bToIndex > b.length}
	* @throws NullPointerException
	* if either array is {@code null}
	* @see Double#equals(Object)
	* @since 9
	*/
	public static boolean equals(double[] a, int aFromIndex, int aToIndex,
	double[] b, int bFromIndex, int bToIndex) {
	rangeCheck(a.length, aFromIndex, aToIndex);
	rangeCheck(b.length, bFromIndex, bToIndex);

	int aLength = aToIndex - aFromIndex;
	int bLength = bToIndex - bFromIndex;
	if (aLength != bLength)
	return false;

	return ArraysSupport.mismatch(a, aFromIndex,
	b, bFromIndex, aLength) < 0;
	}

	/**
	* Returns {@code true} if the two specified arrays of floats are
	* <i>equal</i> to one another. Two arrays are considered equal if both
	* arrays contain the same number of elements, and all corresponding pairs
	* of elements in the two arrays are equal. In other words, two arrays
	* are equal if they contain the same elements in the same order. Also,
	* two array references are considered equal if both are {@code null}.
	*
	* Two floats {@code f1} and {@code f2} are considered equal if:
	* <pre> {@code new Float(f1).equals(new Float(f2))}</pre>
	* (Unlike the {@code ==} operator, this method considers
	* {@code NaN} equal to itself, and 0.0f unequal to -0.0f.)
	*
	* @param a one array to be tested for equality
	* @param a2 the other array to be tested for equality
	* @return {@code true} if the two arrays are equal
	* @see Float#equals(Object)
	*/
	public static boolean equals(float[] a, float[] a2) {
	if (a==a2)
	return true;
	if (a==null \|\| a2==null)
	return false;

	int length = a.length;
	if (a2.length != length)
	return false;

	return ArraysSupport.mismatch(a, a2, length) < 0;
	}

	/**
	* Returns true if the two specified arrays of floats, over the specified
	* ranges, are <i>equal</i> to one another.
	*
	* <p>Two arrays are considered equal if the number of elements covered by
	* each range is the same, and all corresponding pairs of elements over the
	* specified ranges in the two arrays are equal. In other words, two arrays
	* are equal if they contain, over the specified ranges, the same elements
	* in the same order.
	*
	* <p>Two floats {@code f1} and {@code f2} are considered equal if:
	* <pre> {@code new Float(f1).equals(new Float(f2))}</pre>
	* (Unlike the {@code ==} operator, this method considers
	* {@code NaN} equal to itself, and 0.0f unequal to -0.0f.)
	*
	* @param a the first array to be tested for equality
	* @param aFromIndex the index (inclusive) of the first element in the
	* first array to be tested
	* @param aToIndex the index (exclusive) of the last element in the
	* first array to be tested
	* @param b the second array to be tested for equality
	* @param bFromIndex the index (inclusive) of the first element in the
	* second array to be tested
	* @param bToIndex the index (exclusive) of the last element in the
	* second array to be tested
	* @return {@code true} if the two arrays, over the specified ranges, are
	* equal
	* @throws IllegalArgumentException
	* if {@code aFromIndex > aToIndex} or
	* if {@code bFromIndex > bToIndex}
	* @throws ArrayIndexOutOfBoundsException
	* if {@code aFromIndex < 0 or aToIndex > a.length} or
	* if {@code bFromIndex < 0 or bToIndex > b.length}
	* @throws NullPointerException
	* if either array is {@code null}
	* @see Float#equals(Object)
	* @since 9
	*/
	public static boolean equals(float[] a, int aFromIndex, int aToIndex,
	float[] b, int bFromIndex, int bToIndex) {
	rangeCheck(a.length, aFromIndex, aToIndex);
	rangeCheck(b.length, bFromIndex, bToIndex);

	int aLength = aToIndex - aFromIndex;
	int bLength = bToIndex - bFromIndex;
	if (aLength != bLength)
	return false;

	return ArraysSupport.mismatch(a, aFromIndex,
	b, bFromIndex, aLength) < 0;
	}

	/**
	* Returns {@code true} if the two specified arrays of Objects are
	* <i>equal</i> to one another. The two arrays are considered equal if
	* both arrays contain the same number of elements, and all corresponding
	* pairs of elements in the two arrays are equal. Two objects {@code e1}
	* and {@code e2} are considered <i>equal</i> if
	* {@code Objects.equals(e1, e2)}.
	* In other words, the two arrays are equal if
	* they contain the same elements in the same order. Also, two array
	* references are considered equal if both are {@code null}.
	*
	* @param a one array to be tested for equality
	* @param a2 the other array to be tested for equality
	* @return {@code true} if the two arrays are equal
	*/
	public static boolean equals(Object[] a, Object[] a2) {
	if (a==a2)
	return true;
	if (a==null \|\| a2==null)
	return false;

	int length = a.length;
	if (a2.length != length)
	return false;

	for (int i=0; i<length; i++) {
	if (!Objects.equals(a[i], a2[i]))
	return false;
	}

	return true;
	}

	/**
	* Returns true if the two specified arrays of Objects, over the specified
	* ranges, are <i>equal</i> to one another.
	*
	* <p>Two arrays are considered equal if the number of elements covered by
	* each range is the same, and all corresponding pairs of elements over the
	* specified ranges in the two arrays are equal. In other words, two arrays
	* are equal if they contain, over the specified ranges, the same elements
	* in the same order.
	*
	* <p>Two objects {@code e1} and {@code e2} are considered <i>equal</i> if
	* {@code Objects.equals(e1, e2)}.
	*
	* @param a the first array to be tested for equality
	* @param aFromIndex the index (inclusive) of the first element in the
	* first array to be tested
	* @param aToIndex the index (exclusive) of the last element in the
	* first array to be tested
	* @param b the second array to be tested for equality
	* @param bFromIndex the index (inclusive) of the first element in the
	* second array to be tested
	* @param bToIndex the index (exclusive) of the last element in the
	* second array to be tested
	* @return {@code true} if the two arrays, over the specified ranges, are
	* equal
	* @throws IllegalArgumentException
	* if {@code aFromIndex > aToIndex} or
	* if {@code bFromIndex > bToIndex}
	* @throws ArrayIndexOutOfBoundsException
	* if {@code aFromIndex < 0 or aToIndex > a.length} or
	* if {@code bFromIndex < 0 or bToIndex > b.length}
	* @throws NullPointerException
	* if either array is {@code null}
	* @since 9
	*/
	public static boolean equals(Object[] a, int aFromIndex, int aToIndex,
	Object[] b, int bFromIndex, int bToIndex) {
	rangeCheck(a.length, aFromIndex, aToIndex);
	rangeCheck(b.length, bFromIndex, bToIndex);

	int aLength = aToIndex - aFromIndex;
	int bLength = bToIndex - bFromIndex;
	if (aLength != bLength)
	return false;

	for (int i = 0; i < aLength; i++) {
	if (!Objects.equals(a[aFromIndex++], b[bFromIndex++]))
	return false;
	}

	return true;
	}

	/**
	* Returns {@code true} if the two specified arrays of Objects are
	* <i>equal</i> to one another.
	*
	* <p>Two arrays are considered equal if both arrays contain the same number
	* of elements, and all corresponding pairs of elements in the two arrays
	* are equal. In other words, the two arrays are equal if they contain the
	* same elements in the same order. Also, two array references are
	* considered equal if both are {@code null}.
	*
	* <p>Two objects {@code e1} and {@code e2} are considered <i>equal</i> if,
	* given the specified comparator, {@code cmp.compare(e1, e2) == 0}.
	*
	* @param a one array to be tested for equality
	* @param a2 the other array to be tested for equality
	* @param cmp the comparator to compare array elements
	* @param <T> the type of array elements
	* @return {@code true} if the two arrays are equal
	* @throws NullPointerException if the comparator is {@code null}
	* @since 9
	*/
	public static <T> boolean equals(T[] a, T[] a2, Comparator<? super T> cmp) {
	Objects.requireNonNull(cmp);
	if (a==a2)
	return true;
	if (a==null \|\| a2==null)
	return false;

	int length = a.length;
	if (a2.length != length)
	return false;

	for (int i=0; i<length; i++) {
	if (cmp.compare(a[i], a2[i]) != 0)
	return false;
	}

	return true;
	}

	/**
	* Returns true if the two specified arrays of Objects, over the specified
	* ranges, are <i>equal</i> to one another.
	*
	* <p>Two arrays are considered equal if the number of elements covered by
	* each range is the same, and all corresponding pairs of elements over the
	* specified ranges in the two arrays are equal. In other words, two arrays
	* are equal if they contain, over the specified ranges, the same elements
	* in the same order.
	*
	* <p>Two objects {@code e1} and {@code e2} are considered <i>equal</i> if,
	* given the specified comparator, {@code cmp.compare(e1, e2) == 0}.
	*
	* @param a the first array to be tested for equality
	* @param aFromIndex the index (inclusive) of the first element in the
	* first array to be tested
	* @param aToIndex the index (exclusive) of the last element in the
	* first array to be tested
	* @param b the second array to be tested for equality
	* @param bFromIndex the index (inclusive) of the first element in the
	* second array to be tested
	* @param bToIndex the index (exclusive) of the last element in the
	* second array to be tested
	* @param cmp the comparator to compare array elements
	* @param <T> the type of array elements
	* @return {@code true} if the two arrays, over the specified ranges, are
	* equal
	* @throws IllegalArgumentException
	* if {@code aFromIndex > aToIndex} or
	* if {@code bFromIndex > bToIndex}
	* @throws ArrayIndexOutOfBoundsException
	* if {@code aFromIndex < 0 or aToIndex > a.length} or
	* if {@code bFromIndex < 0 or bToIndex > b.length}
	* @throws NullPointerException
	* if either array or the comparator is {@code null}
	* @since 9
	*/
	public static <T> boolean equals(T[] a, int aFromIndex, int aToIndex,
	T[] b, int bFromIndex, int bToIndex,
	Comparator<? super T> cmp) {
	Objects.requireNonNull(cmp);
	rangeCheck(a.length, aFromIndex, aToIndex);
	rangeCheck(b.length, bFromIndex, bToIndex);

	int aLength = aToIndex - aFromIndex;
	int bLength = bToIndex - bFromIndex;
	if (aLength != bLength)
	return false;

	for (int i = 0; i < aLength; i++) {
	if (cmp.compare(a[aFromIndex++], b[bFromIndex++]) != 0)
	return false;
	}

	return true;
	}

	// Filling

	/**
	* Assigns the specified long value to each element of the specified array
	* of longs.
	*
	* @param a the array to be filled
	* @param val the value to be stored in all elements of the array
	*/
	public static void fill(long[] a, long val) {
	for (int i = 0, len = a.length; i < len; i++)
	a[i] = val;
	}

	/**
	* Assigns the specified long value to each element of the specified
	* range of the specified array of longs. The range to be filled
	* extends from index {@code fromIndex}, inclusive, to index
	* {@code toIndex}, exclusive. (If {@code fromIndex==toIndex}, the
	* range to be filled is empty.)
	*
	* @param a the array to be filled
	* @param fromIndex the index of the first element (inclusive) to be
	* filled with the specified value
	* @param toIndex the index of the last element (exclusive) to be
	* filled with the specified value
	* @param val the value to be stored in all elements of the array
	* @throws IllegalArgumentException if {@code fromIndex > toIndex}
	* @throws ArrayIndexOutOfBoundsException if {@code fromIndex < 0} or
	* {@code toIndex > a.length}
	*/
	public static void fill(long[] a, int fromIndex, int toIndex, long val) {
	rangeCheck(a.length, fromIndex, toIndex);
	for (int i = fromIndex; i < toIndex; i++)
	a[i] = val;
	}

	/**
	* Assigns the specified int value to each element of the specified array
	* of ints.
	*
	* @param a the array to be filled
	* @param val the value to be stored in all elements of the array
	*/
	public static void fill(int[] a, int val) {
	for (int i = 0, len = a.length; i < len; i++)
	a[i] = val;
	}

	/**
	* Assigns the specified int value to each element of the specified
	* range of the specified array of ints. The range to be filled
	* extends from index {@code fromIndex}, inclusive, to index
	* {@code toIndex}, exclusive. (If {@code fromIndex==toIndex}, the
	* range to be filled is empty.)
	*
	* @param a the array to be filled
	* @param fromIndex the index of the first element (inclusive) to be
	* filled with the specified value
	* @param toIndex the index of the last element (exclusive) to be
	* filled with the specified value
	* @param val the value to be stored in all elements of the array
	* @throws IllegalArgumentException if {@code fromIndex > toIndex}
	* @throws ArrayIndexOutOfBoundsException if {@code fromIndex < 0} or
	* {@code toIndex > a.length}
	*/
	public static void fill(int[] a, int fromIndex, int toIndex, int val) {
	rangeCheck(a.length, fromIndex, toIndex);
	for (int i = fromIndex; i < toIndex; i++)
	a[i] = val;
	}

	/**
	* Assigns the specified short value to each element of the specified array
	* of shorts.
	*
	* @param a the array to be filled
	* @param val the value to be stored in all elements of the array
	*/
	public static void fill(short[] a, short val) {
	for (int i = 0, len = a.length; i < len; i++)
	a[i] = val;
	}

	/**
	* Assigns the specified short value to each element of the specified
	* range of the specified array of shorts. The range to be filled
	* extends from index {@code fromIndex}, inclusive, to index
	* {@code toIndex}, exclusive. (If {@code fromIndex==toIndex}, the
	* range to be filled is empty.)
	*
	* @param a the array to be filled
	* @param fromIndex the index of the first element (inclusive) to be
	* filled with the specified value
	* @param toIndex the index of the last element (exclusive) to be
	* filled with the specified value
	* @param val the value to be stored in all elements of the array
	* @throws IllegalArgumentException if {@code fromIndex > toIndex}
	* @throws ArrayIndexOutOfBoundsException if {@code fromIndex < 0} or
	* {@code toIndex > a.length}
	*/
	public static void fill(short[] a, int fromIndex, int toIndex, short val) {
	rangeCheck(a.length, fromIndex, toIndex);
	for (int i = fromIndex; i < toIndex; i++)
	a[i] = val;
	}

	/**
	* Assigns the specified char value to each element of the specified array
	* of chars.
	*
	* @param a the array to be filled
	* @param val the value to be stored in all elements of the array
	*/
	public static void fill(char[] a, char val) {
	for (int i = 0, len = a.length; i < len; i++)
	a[i] = val;
	}

	/**
	* Assigns the specified char value to each element of the specified
	* range of the specified array of chars. The range to be filled
	* extends from index {@code fromIndex}, inclusive, to index
	* {@code toIndex}, exclusive. (If {@code fromIndex==toIndex}, the
	* range to be filled is empty.)
	*
	* @param a the array to be filled
	* @param fromIndex the index of the first element (inclusive) to be
	* filled with the specified value
	* @param toIndex the index of the last element (exclusive) to be
	* filled with the specified value
	* @param val the value to be stored in all elements of the array
	* @throws IllegalArgumentException if {@code fromIndex > toIndex}
	* @throws ArrayIndexOutOfBoundsException if {@code fromIndex < 0} or
	* {@code toIndex > a.length}
	*/
	public static void fill(char[] a, int fromIndex, int toIndex, char val) {
	rangeCheck(a.length, fromIndex, toIndex);
	for (int i = fromIndex; i < toIndex; i++)
	a[i] = val;
	}

	/**
	* Assigns the specified byte value to each element of the specified array
	* of bytes.
	*
	* @param a the array to be filled
	* @param val the value to be stored in all elements of the array
	*/
	public static void fill(byte[] a, byte val) {
	for (int i = 0, len = a.length; i < len; i++)
	a[i] = val;
	}

	/**
	* Assigns the specified byte value to each element of the specified
	* range of the specified array of bytes. The range to be filled
	* extends from index {@code fromIndex}, inclusive, to index
	* {@code toIndex}, exclusive. (If {@code fromIndex==toIndex}, the
	* range to be filled is empty.)
	*
	* @param a the array to be filled
	* @param fromIndex the index of the first element (inclusive) to be
	* filled with the specified value
	* @param toIndex the index of the last element (exclusive) to be
	* filled with the specified value
	* @param val the value to be stored in all elements of the array
	* @throws IllegalArgumentException if {@code fromIndex > toIndex}
	* @throws ArrayIndexOutOfBoundsException if {@code fromIndex < 0} or
	* {@code toIndex > a.length}
	*/
	public static void fill(byte[] a, int fromIndex, int toIndex, byte val) {
	rangeCheck(a.length, fromIndex, toIndex);
	for (int i = fromIndex; i < toIndex; i++)
	a[i] = val;
	}

	/**
	* Assigns the specified boolean value to each element of the specified
	* array of booleans.
	*
	* @param a the array to be filled
	* @param val the value to be stored in all elements of the array
	*/
	public static void fill(boolean[] a, boolean val) {
	for (int i = 0, len = a.length; i < len; i++)
	a[i] = val;
	}

	/**
	* Assigns the specified boolean value to each element of the specified
	* range of the specified array of booleans. The range to be filled
	* extends from index {@code fromIndex}, inclusive, to index
	* {@code toIndex}, exclusive. (If {@code fromIndex==toIndex}, the
	* range to be filled is empty.)
	*
	* @param a the array to be filled
	* @param fromIndex the index of the first element (inclusive) to be
	* filled with the specified value
	* @param toIndex the index of the last element (exclusive) to be
	* filled with the specified value
	* @param val the value to be stored in all elements of the array
	* @throws IllegalArgumentException if {@code fromIndex > toIndex}
	* @throws ArrayIndexOutOfBoundsException if {@code fromIndex < 0} or
	* {@code toIndex > a.length}
	*/
	public static void fill(boolean[] a, int fromIndex, int toIndex,
	boolean val) {
	rangeCheck(a.length, fromIndex, toIndex);
	for (int i = fromIndex; i < toIndex; i++)
	a[i] = val;
	}

	/**
	* Assigns the specified double value to each element of the specified
	* array of doubles.
	*
	* @param a the array to be filled
	* @param val the value to be stored in all elements of the array
	*/
	public static void fill(double[] a, double val) {
	for (int i = 0, len = a.length; i < len; i++)
	a[i] = val;
	}

	/**
	* Assigns the specified double value to each element of the specified
	* range of the specified array of doubles. The range to be filled
	* extends from index {@code fromIndex}, inclusive, to index
	* {@code toIndex}, exclusive. (If {@code fromIndex==toIndex}, the
	* range to be filled is empty.)
	*
	* @param a the array to be filled
	* @param fromIndex the index of the first element (inclusive) to be
	* filled with the specified value
	* @param toIndex the index of the last element (exclusive) to be
	* filled with the specified value
	* @param val the value to be stored in all elements of the array
	* @throws IllegalArgumentException if {@code fromIndex > toIndex}
	* @throws ArrayIndexOutOfBoundsException if {@code fromIndex < 0} or
	* {@code toIndex > a.length}
	*/
	public static void fill(double[] a, int fromIndex, int toIndex,double val){
	rangeCheck(a.length, fromIndex, toIndex);
	for (int i = fromIndex; i < toIndex; i++)
	a[i] = val;
	}

	/**
	* Assigns the specified float value to each element of the specified array
	* of floats.
	*
	* @param a the array to be filled
	* @param val the value to be stored in all elements of the array
	*/
	public static void fill(float[] a, float val) {
	for (int i = 0, len = a.length; i < len; i++)
	a[i] = val;
	}

	/**
	* Assigns the specified float value to each element of the specified
	* range of the specified array of floats. The range to be filled
	* extends from index {@code fromIndex}, inclusive, to index
	* {@code toIndex}, exclusive. (If {@code fromIndex==toIndex}, the
	* range to be filled is empty.)
	*
	* @param a the array to be filled
	* @param fromIndex the index of the first element (inclusive) to be
	* filled with the specified value
	* @param toIndex the index of the last element (exclusive) to be
	* filled with the specified value
	* @param val the value to be stored in all elements of the array
	* @throws IllegalArgumentException if {@code fromIndex > toIndex}
	* @throws ArrayIndexOutOfBoundsException if {@code fromIndex < 0} or
	* {@code toIndex > a.length}
	*/
	public static void fill(float[] a, int fromIndex, int toIndex, float val) {
	rangeCheck(a.length, fromIndex, toIndex);
	for (int i = fromIndex; i < toIndex; i++)
	a[i] = val;
	}

	/**
	* Assigns the specified Object reference to each element of the specified
	* array of Objects.
	*
	* @param a the array to be filled
	* @param val the value to be stored in all elements of the array
	* @throws ArrayStoreException if the specified value is not of a
	* runtime type that can be stored in the specified array
	*/
	public static void fill(Object[] a, Object val) {
	for (int i = 0, len = a.length; i < len; i++)
	a[i] = val;
	}

	/**
	* Assigns the specified Object reference to each element of the specified
	* range of the specified array of Objects. The range to be filled
	* extends from index {@code fromIndex}, inclusive, to index
	* {@code toIndex}, exclusive. (If {@code fromIndex==toIndex}, the
	* range to be filled is empty.)
	*
	* @param a the array to be filled
	* @param fromIndex the index of the first element (inclusive) to be
	* filled with the specified value
	* @param toIndex the index of the last element (exclusive) to be
	* filled with the specified value
	* @param val the value to be stored in all elements of the array
	* @throws IllegalArgumentException if {@code fromIndex > toIndex}
	* @throws ArrayIndexOutOfBoundsException if {@code fromIndex < 0} or
	* {@code toIndex > a.length}
	* @throws ArrayStoreException if the specified value is not of a
	* runtime type that can be stored in the specified array
	*/
	public static void fill(Object[] a, int fromIndex, int toIndex, Object val) {
	rangeCheck(a.length, fromIndex, toIndex);
	for (int i = fromIndex; i < toIndex; i++)
	a[i] = val;
	}

	// Cloning

	/**
	* Copies the specified array, truncating or padding with nulls (if necessary)
	* so the copy has the specified length. For all indices that are
	* valid in both the original array and the copy, the two arrays will
	* contain identical values. For any indices that are valid in the
	* copy but not the original, the copy will contain {@code null}.
	* Such indices will exist if and only if the specified length
	* is greater than that of the original array.
	* The resulting array is of exactly the same class as the original array.
	*
	* @param <T> the class of the objects in the array
	* @param original the array to be copied
	* @param newLength the length of the copy to be returned
	* @return a copy of the original array, truncated or padded with nulls
	* to obtain the specified length
	* @throws NegativeArraySizeException if {@code newLength} is negative
	* @throws NullPointerException if {@code original} is null
	* @since 1.6
	*/
	@SuppressWarnings("unchecked")
	public static <T> T[] copyOf(T[] original, int newLength) {
	return (T[]) copyOf(original, newLength, original.getClass());
	}

	/**
	* Copies the specified array, truncating or padding with nulls (if necessary)
	* so the copy has the specified length. For all indices that are
	* valid in both the original array and the copy, the two arrays will
	* contain identical values. For any indices that are valid in the
	* copy but not the original, the copy will contain {@code null}.
	* Such indices will exist if and only if the specified length
	* is greater than that of the original array.
	* The resulting array is of the class {@code newType}.
	*
	* @param <U> the class of the objects in the original array
	* @param <T> the class of the objects in the returned array
	* @param original the array to be copied
	* @param newLength the length of the copy to be returned
	* @param newType the class of the copy to be returned
	* @return a copy of the original array, truncated or padded with nulls
	* to obtain the specified length
	* @throws NegativeArraySizeException if {@code newLength} is negative
	* @throws NullPointerException if {@code original} is null
	* @throws ArrayStoreException if an element copied from
	* {@code original} is not of a runtime type that can be stored in
	* an array of class {@code newType}
	* @since 1.6
	*/
	@IntrinsicCandidate
	public static <T,U> T[] copyOf(U[] original, int newLength, Class<? extends T[]> newType) {
	@SuppressWarnings("unchecked")
	T[] copy = ((Object)newType == (Object)Object[].class)
	? (T[]) new Object[newLength]
	: (T[]) Array.newInstance(newType.getComponentType(), newLength);
	System.arraycopy(original, 0, copy, 0,
	Math.min(original.length, newLength));
	return copy;
	}

	/**
	* Copies the specified array, truncating or padding with zeros (if necessary)
	* so the copy has the specified length. For all indices that are
	* valid in both the original array and the copy, the two arrays will
	* contain identical values. For any indices that are valid in the
	* copy but not the original, the copy will contain {@code (byte)0}.
	* Such indices will exist if and only if the specified length
	* is greater than that of the original array.
	*
	* @param original the array to be copied
	* @param newLength the length of the copy to be returned
	* @return a copy of the original array, truncated or padded with zeros
	* to obtain the specified length
	* @throws NegativeArraySizeException if {@code newLength} is negative
	* @throws NullPointerException if {@code original} is null
	* @since 1.6
	*/
	public static byte[] copyOf(byte[] original, int newLength) {
	byte[] copy = new byte[newLength];
	System.arraycopy(original, 0, copy, 0,
	Math.min(original.length, newLength));
	return copy;
	}

	/**
	* Copies the specified array, truncating or padding with zeros (if necessary)
	* so the copy has the specified length. For all indices that are
	* valid in both the original array and the copy, the two arrays will
	* contain identical values. For any indices that are valid in the
	* copy but not the original, the copy will contain {@code (short)0}.
	* Such indices will exist if and only if the specified length
	* is greater than that of the original array.
	*
	* @param original the array to be copied
	* @param newLength the length of the copy to be returned
	* @return a copy of the original array, truncated or padded with zeros
	* to obtain the specified length
	* @throws NegativeArraySizeException if {@code newLength} is negative
	* @throws NullPointerException if {@code original} is null
	* @since 1.6
	*/
	public static short[] copyOf(short[] original, int newLength) {
	short[] copy = new short[newLength];
	System.arraycopy(original, 0, copy, 0,
	Math.min(original.length, newLength));
	return copy;
	}

	/**
	* Copies the specified array, truncating or padding with zeros (if necessary)
	* so the copy has the specified length. For all indices that are
	* valid in both the original array and the copy, the two arrays will
	* contain identical values. For any indices that are valid in the
	* copy but not the original, the copy will contain {@code 0}.
	* Such indices will exist if and only if the specified length
	* is greater than that of the original array.
	*
	* @param original the array to be copied
	* @param newLength the length of the copy to be returned
	* @return a copy of the original array, truncated or padded with zeros
	* to obtain the specified length
	* @throws NegativeArraySizeException if {@code newLength} is negative
	* @throws NullPointerException if {@code original} is null
	* @since 1.6
	*/
	public static int[] copyOf(int[] original, int newLength) {
	int[] copy = new int[newLength];
	System.arraycopy(original, 0, copy, 0,
	Math.min(original.length, newLength));
	return copy;
	}

	/**
	* Copies the specified array, truncating or padding with zeros (if necessary)
	* so the copy has the specified length. For all indices that are
	* valid in both the original array and the copy, the two arrays will
	* contain identical values. For any indices that are valid in the
	* copy but not the original, the copy will contain {@code 0L}.
	* Such indices will exist if and only if the specified length
	* is greater than that of the original array.
	*
	* @param original the array to be copied
	* @param newLength the length of the copy to be returned
	* @return a copy of the original array, truncated or padded with zeros
	* to obtain the specified length
	* @throws NegativeArraySizeException if {@code newLength} is negative
	* @throws NullPointerException if {@code original} is null
	* @since 1.6
	*/
	public static long[] copyOf(long[] original, int newLength) {
	long[] copy = new long[newLength];
	System.arraycopy(original, 0, copy, 0,
	Math.min(original.length, newLength));
	return copy;
	}

	/**
	* Copies the specified array, truncating or padding with null characters (if necessary)
	* so the copy has the specified length. For all indices that are valid
	* in both the original array and the copy, the two arrays will contain
	* identical values. For any indices that are valid in the copy but not
	* the original, the copy will contain {@code '\u005cu0000'}. Such indices
	* will exist if and only if the specified length is greater than that of
	* the original array.
	*
	* @param original the array to be copied
	* @param newLength the length of the copy to be returned
	* @return a copy of the original array, truncated or padded with null characters
	* to obtain the specified length
	* @throws NegativeArraySizeException if {@code newLength} is negative
	* @throws NullPointerException if {@code original} is null
	* @since 1.6
	*/
	public static char[] copyOf(char[] original, int newLength) {
	char[] copy = new char[newLength];
	System.arraycopy(original, 0, copy, 0,
	Math.min(original.length, newLength));
	return copy;
	}

	/**
	* Copies the specified array, truncating or padding with zeros (if necessary)
	* so the copy has the specified length. For all indices that are
	* valid in both the original array and the copy, the two arrays will
	* contain identical values. For any indices that are valid in the
	* copy but not the original, the copy will contain {@code 0f}.
	* Such indices will exist if and only if the specified length
	* is greater than that of the original array.
	*
	* @param original the array to be copied
	* @param newLength the length of the copy to be returned
	* @return a copy of the original array, truncated or padded with zeros
	* to obtain the specified length
	* @throws NegativeArraySizeException if {@code newLength} is negative
	* @throws NullPointerException if {@code original} is null
	* @since 1.6
	*/
	public static float[] copyOf(float[] original, int newLength) {
	float[] copy = new float[newLength];
	System.arraycopy(original, 0, copy, 0,
	Math.min(original.length, newLength));
	return copy;
	}

	/**
	* Copies the specified array, truncating or padding with zeros (if necessary)
	* so the copy has the specified length. For all indices that are
	* valid in both the original array and the copy, the two arrays will
	* contain identical values. For any indices that are valid in the
	* copy but not the original, the copy will contain {@code 0d}.
	* Such indices will exist if and only if the specified length
	* is greater than that of the original array.
	*
	* @param original the array to be copied
	* @param newLength the length of the copy to be returned
	* @return a copy of the original array, truncated or padded with zeros
	* to obtain the specified length
	* @throws NegativeArraySizeException if {@code newLength} is negative
	* @throws NullPointerException if {@code original} is null
	* @since 1.6
	*/
	public static double[] copyOf(double[] original, int newLength) {
	double[] copy = new double[newLength];
	System.arraycopy(original, 0, copy, 0,
	Math.min(original.length, newLength));
	return copy;
	}

	/**
	* Copies the specified array, truncating or padding with {@code false} (if necessary)
	* so the copy has the specified length. For all indices that are
	* valid in both the original array and the copy, the two arrays will
	* contain identical values. For any indices that are valid in the
	* copy but not the original, the copy will contain {@code false}.
	* Such indices will exist if and only if the specified length
	* is greater than that of the original array.
	*
	* @param original the array to be copied
	* @param newLength the length of the copy to be returned
	* @return a copy of the original array, truncated or padded with false elements
	* to obtain the specified length
	* @throws NegativeArraySizeException if {@code newLength} is negative
	* @throws NullPointerException if {@code original} is null
	* @since 1.6
	*/
	public static boolean[] copyOf(boolean[] original, int newLength) {
	boolean[] copy = new boolean[newLength];
	System.arraycopy(original, 0, copy, 0,
	Math.min(original.length, newLength));
	return copy;
	}

	/**
	* Copies the specified range of the specified array into a new array.
	* The initial index of the range ({@code from}) must lie between zero
	* and {@code original.length}, inclusive. The value at
	* {@code original[from]} is placed into the initial element of the copy
	* (unless {@code from == original.length} or {@code from == to}).
	* Values from subsequent elements in the original array are placed into
	* subsequent elements in the copy. The final index of the range
	* ({@code to}), which must be greater than or equal to {@code from},
	* may be greater than {@code original.length}, in which case
	* {@code null} is placed in all elements of the copy whose index is
	* greater than or equal to {@code original.length - from}. The length
	* of the returned array will be {@code to - from}.
	* <p>
	* The resulting array is of exactly the same class as the original array.
	*
	* @param <T> the class of the objects in the array
	* @param original the array from which a range is to be copied
	* @param from the initial index of the range to be copied, inclusive
	* @param to the final index of the range to be copied, exclusive.
	* (This index may lie outside the array.)
	* @return a new array containing the specified range from the original array,
	* truncated or padded with nulls to obtain the required length
	* @throws ArrayIndexOutOfBoundsException if {@code from < 0}
	* or {@code from > original.length}
	* @throws IllegalArgumentException if {@code from > to}
	* @throws NullPointerException if {@code original} is null
	* @since 1.6
	*/
	@SuppressWarnings("unchecked")
	public static <T> T[] copyOfRange(T[] original, int from, int to) {
	return copyOfRange(original, from, to, (Class<? extends T[]>) original.getClass());
	}

	/**
	* Copies the specified range of the specified array into a new array.
	* The initial index of the range ({@code from}) must lie between zero
	* and {@code original.length}, inclusive. The value at
	* {@code original[from]} is placed into the initial element of the copy
	* (unless {@code from == original.length} or {@code from == to}).
	* Values from subsequent elements in the original array are placed into
	* subsequent elements in the copy. The final index of the range
	* ({@code to}), which must be greater than or equal to {@code from},
	* may be greater than {@code original.length}, in which case
	* {@code null} is placed in all elements of the copy whose index is
	* greater than or equal to {@code original.length - from}. The length
	* of the returned array will be {@code to - from}.
	* The resulting array is of the class {@code newType}.
	*
	* @param <U> the class of the objects in the original array
	* @param <T> the class of the objects in the returned array
	* @param original the array from which a range is to be copied
	* @param from the initial index of the range to be copied, inclusive
	* @param to the final index of the range to be copied, exclusive.
	* (This index may lie outside the array.)
	* @param newType the class of the copy to be returned
	* @return a new array containing the specified range from the original array,
	* truncated or padded with nulls to obtain the required length
	* @throws ArrayIndexOutOfBoundsException if {@code from < 0}
	* or {@code from > original.length}
	* @throws IllegalArgumentException if {@code from > to}
	* @throws NullPointerException if {@code original} is null
	* @throws ArrayStoreException if an element copied from
	* {@code original} is not of a runtime type that can be stored in
	* an array of class {@code newType}.
	* @since 1.6
	*/
	@IntrinsicCandidate
	public static <T,U> T[] copyOfRange(U[] original, int from, int to, Class<? extends T[]> newType) {
	int newLength = to - from;
	if (newLength < 0)
	throw new IllegalArgumentException(from + " > " + to);
	@SuppressWarnings("unchecked")
	T[] copy = ((Object)newType == (Object)Object[].class)
	? (T[]) new Object[newLength]
	: (T[]) Array.newInstance(newType.getComponentType(), newLength);
	System.arraycopy(original, from, copy, 0,
	Math.min(original.length - from, newLength));
	return copy;
	}

	/**
	* Copies the specified range of the specified array into a new array.
	* The initial index of the range ({@code from}) must lie between zero
	* and {@code original.length}, inclusive. The value at
	* {@code original[from]} is placed into the initial element of the copy
	* (unless {@code from == original.length} or {@code from == to}).
	* Values from subsequent elements in the original array are placed into
	* subsequent elements in the copy. The final index of the range
	* ({@code to}), which must be greater than or equal to {@code from},
	* may be greater than {@code original.length}, in which case
	* {@code (byte)0} is placed in all elements of the copy whose index is
	* greater than or equal to {@code original.length - from}. The length
	* of the returned array will be {@code to - from}.
	*
	* @param original the array from which a range is to be copied
	* @param from the initial index of the range to be copied, inclusive
	* @param to the final index of the range to be copied, exclusive.
	* (This index may lie outside the array.)
	* @return a new array containing the specified range from the original array,
	* truncated or padded with zeros to obtain the required length
	* @throws ArrayIndexOutOfBoundsException if {@code from < 0}
	* or {@code from > original.length}
	* @throws IllegalArgumentException if {@code from > to}
	* @throws NullPointerException if {@code original} is null
	* @since 1.6
	*/
	public static byte[] copyOfRange(byte[] original, int from, int to) {
	int newLength = to - from;
	if (newLength < 0)
	throw new IllegalArgumentException(from + " > " + to);
	byte[] copy = new byte[newLength];
	System.arraycopy(original, from, copy, 0,
	Math.min(original.length - from, newLength));
	return copy;
	}

	/**
	* Copies the specified range of the specified array into a new array.
	* The initial index of the range ({@code from}) must lie between zero
	* and {@code original.length}, inclusive. The value at
	* {@code original[from]} is placed into the initial element of the copy
	* (unless {@code from == original.length} or {@code from == to}).
	* Values from subsequent elements in the original array are placed into
	* subsequent elements in the copy. The final index of the range
	* ({@code to}), which must be greater than or equal to {@code from},
	* may be greater than {@code original.length}, in which case
	* {@code (short)0} is placed in all elements of the copy whose index is
	* greater than or equal to {@code original.length - from}. The length
	* of the returned array will be {@code to - from}.
	*
	* @param original the array from which a range is to be copied
	* @param from the initial index of the range to be copied, inclusive
	* @param to the final index of the range to be copied, exclusive.
	* (This index may lie outside the array.)
	* @return a new array containing the specified range from the original array,
	* truncated or padded with zeros to obtain the required length
	* @throws ArrayIndexOutOfBoundsException if {@code from < 0}
	* or {@code from > original.length}
	* @throws IllegalArgumentException if {@code from > to}
	* @throws NullPointerException if {@code original} is null
	* @since 1.6
	*/
	public static short[] copyOfRange(short[] original, int from, int to) {
	int newLength = to - from;
	if (newLength < 0)
	throw new IllegalArgumentException(from + " > " + to);
	short[] copy = new short[newLength];
	System.arraycopy(original, from, copy, 0,
	Math.min(original.length - from, newLength));
	return copy;
	}

	/**
	* Copies the specified range of the specified array into a new array.
	* The initial index of the range ({@code from}) must lie between zero
	* and {@code original.length}, inclusive. The value at
	* {@code original[from]} is placed into the initial element of the copy
	* (unless {@code from == original.length} or {@code from == to}).
	* Values from subsequent elements in the original array are placed into
	* subsequent elements in the copy. The final index of the range
	* ({@code to}), which must be greater than or equal to {@code from},
	* may be greater than {@code original.length}, in which case
	* {@code 0} is placed in all elements of the copy whose index is
	* greater than or equal to {@code original.length - from}. The length
	* of the returned array will be {@code to - from}.
	*
	* @param original the array from which a range is to be copied
	* @param from the initial index of the range to be copied, inclusive
	* @param to the final index of the range to be copied, exclusive.
	* (This index may lie outside the array.)
	* @return a new array containing the specified range from the original array,
	* truncated or padded with zeros to obtain the required length
	* @throws ArrayIndexOutOfBoundsException if {@code from < 0}
	* or {@code from > original.length}
	* @throws IllegalArgumentException if {@code from > to}
	* @throws NullPointerException if {@code original} is null
	* @since 1.6
	*/
	public static int[] copyOfRange(int[] original, int from, int to) {
	int newLength = to - from;
	if (newLength < 0)
	throw new IllegalArgumentException(from + " > " + to);
	int[] copy = new int[newLength];
	System.arraycopy(original, from, copy, 0,
	Math.min(original.length - from, newLength));
	return copy;
	}

	/**
	* Copies the specified range of the specified array into a new array.
	* The initial index of the range ({@code from}) must lie between zero
	* and {@code original.length}, inclusive. The value at
	* {@code original[from]} is placed into the initial element of the copy
	* (unless {@code from == original.length} or {@code from == to}).
	* Values from subsequent elements in the original array are placed into
	* subsequent elements in the copy. The final index of the range
	* ({@code to}), which must be greater than or equal to {@code from},
	* may be greater than {@code original.length}, in which case
	* {@code 0L} is placed in all elements of the copy whose index is
	* greater than or equal to {@code original.length - from}. The length
	* of the returned array will be {@code to - from}.
	*
	* @param original the array from which a range is to be copied
	* @param from the initial index of the range to be copied, inclusive
	* @param to the final index of the range to be copied, exclusive.
	* (This index may lie outside the array.)
	* @return a new array containing the specified range from the original array,
	* truncated or padded with zeros to obtain the required length
	* @throws ArrayIndexOutOfBoundsException if {@code from < 0}
	* or {@code from > original.length}
	* @throws IllegalArgumentException if {@code from > to}
	* @throws NullPointerException if {@code original} is null
	* @since 1.6
	*/
	public static long[] copyOfRange(long[] original, int from, int to) {
	int newLength = to - from;
	if (newLength < 0)
	throw new IllegalArgumentException(from + " > " + to);
	long[] copy = new long[newLength];
	System.arraycopy(original, from, copy, 0,
	Math.min(original.length - from, newLength));
	return copy;
	}

	/**
	* Copies the specified range of the specified array into a new array.
	* The initial index of the range ({@code from}) must lie between zero
	* and {@code original.length}, inclusive. The value at
	* {@code original[from]} is placed into the initial element of the copy
	* (unless {@code from == original.length} or {@code from == to}).
	* Values from subsequent elements in the original array are placed into
	* subsequent elements in the copy. The final index of the range
	* ({@code to}), which must be greater than or equal to {@code from},
	* may be greater than {@code original.length}, in which case
	* {@code '\u005cu0000'} is placed in all elements of the copy whose index is
	* greater than or equal to {@code original.length - from}. The length
	* of the returned array will be {@code to - from}.
	*
	* @param original the array from which a range is to be copied
	* @param from the initial index of the range to be copied, inclusive
	* @param to the final index of the range to be copied, exclusive.
	* (This index may lie outside the array.)
	* @return a new array containing the specified range from the original array,
	* truncated or padded with null characters to obtain the required length
	* @throws ArrayIndexOutOfBoundsException if {@code from < 0}
	* or {@code from > original.length}
	* @throws IllegalArgumentException if {@code from > to}
	* @throws NullPointerException if {@code original} is null
	* @since 1.6
	*/
	public static char[] copyOfRange(char[] original, int from, int to) {
	int newLength = to - from;
	if (newLength < 0)
	throw new IllegalArgumentException(from + " > " + to);
	char[] copy = new char[newLength];
	System.arraycopy(original, from, copy, 0,
	Math.min(original.length - from, newLength));
	return copy;
	}

	/**
	* Copies the specified range of the specified array into a new array.
	* The initial index of the range ({@code from}) must lie between zero
	* and {@code original.length}, inclusive. The value at
	* {@code original[from]} is placed into the initial element of the copy
	* (unless {@code from == original.length} or {@code from == to}).
	* Values from subsequent elements in the original array are placed into
	* subsequent elements in the copy. The final index of the range
	* ({@code to}), which must be greater than or equal to {@code from},
	* may be greater than {@code original.length}, in which case
	* {@code 0f} is placed in all elements of the copy whose index is
	* greater than or equal to {@code original.length - from}. The length
	* of the returned array will be {@code to - from}.
	*
	* @param original the array from which a range is to be copied
	* @param from the initial index of the range to be copied, inclusive
	* @param to the final index of the range to be copied, exclusive.
	* (This index may lie outside the array.)
	* @return a new array containing the specified range from the original array,
	* truncated or padded with zeros to obtain the required length
	* @throws ArrayIndexOutOfBoundsException if {@code from < 0}
	* or {@code from > original.length}
	* @throws IllegalArgumentException if {@code from > to}
	* @throws NullPointerException if {@code original} is null
	* @since 1.6
	*/
	public static float[] copyOfRange(float[] original, int from, int to) {
	int newLength = to - from;
	if (newLength < 0)
	throw new IllegalArgumentException(from + " > " + to);
	float[] copy = new float[newLength];
	System.arraycopy(original, from, copy, 0,
	Math.min(original.length - from, newLength));
	return copy;
	}

	/**
	* Copies the specified range of the specified array into a new array.
	* The initial index of the range ({@code from}) must lie between zero
	* and {@code original.length}, inclusive. The value at
	* {@code original[from]} is placed into the initial element of the copy
	* (unless {@code from == original.length} or {@code from == to}).
	* Values from subsequent elements in the original array are placed into
	* subsequent elements in the copy. The final index of the range
	* ({@code to}), which must be greater than or equal to {@code from},
	* may be greater than {@code original.length}, in which case
	* {@code 0d} is placed in all elements of the copy whose index is
	* greater than or equal to {@code original.length - from}. The length
	* of the returned array will be {@code to - from}.
	*
	* @param original the array from which a range is to be copied
	* @param from the initial index of the range to be copied, inclusive
	* @param to the final index of the range to be copied, exclusive.
	* (This index may lie outside the array.)
	* @return a new array containing the specified range from the original array,
	* truncated or padded with zeros to obtain the required length
	* @throws ArrayIndexOutOfBoundsException if {@code from < 0}
	* or {@code from > original.length}
	* @throws IllegalArgumentException if {@code from > to}
	* @throws NullPointerException if {@code original} is null
	* @since 1.6
	*/
	public static double[] copyOfRange(double[] original, int from, int to) {
	int newLength = to - from;
	if (newLength < 0)
	throw new IllegalArgumentException(from + " > " + to);
	double[] copy = new double[newLength];
	System.arraycopy(original, from, copy, 0,
	Math.min(original.length - from, newLength));
	return copy;
	}

	/**
	* Copies the specified range of the specified array into a new array.
	* The initial index of the range ({@code from}) must lie between zero
	* and {@code original.length}, inclusive. The value at
	* {@code original[from]} is placed into the initial element of the copy
	* (unless {@code from == original.length} or {@code from == to}).
	* Values from subsequent elements in the original array are placed into
	* subsequent elements in the copy. The final index of the range
	* ({@code to}), which must be greater than or equal to {@code from},
	* may be greater than {@code original.length}, in which case
	* {@code false} is placed in all elements of the copy whose index is
	* greater than or equal to {@code original.length - from}. The length
	* of the returned array will be {@code to - from}.
	*
	* @param original the array from which a range is to be copied
	* @param from the initial index of the range to be copied, inclusive
	* @param to the final index of the range to be copied, exclusive.
	* (This index may lie outside the array.)
	* @return a new array containing the specified range from the original array,
	* truncated or padded with false elements to obtain the required length
	* @throws ArrayIndexOutOfBoundsException if {@code from < 0}
	* or {@code from > original.length}
	* @throws IllegalArgumentException if {@code from > to}
	* @throws NullPointerException if {@code original} is null
	* @since 1.6
	*/
	public static boolean[] copyOfRange(boolean[] original, int from, int to) {
	int newLength = to - from;
	if (newLength < 0)
	throw new IllegalArgumentException(from + " > " + to);
	boolean[] copy = new boolean[newLength];
	System.arraycopy(original, from, copy, 0,
	Math.min(original.length - from, newLength));
	return copy;
	}

	// Misc

	/**
	* Returns a fixed-size list backed by the specified array. Changes made to
	* the array will be visible in the returned list, and changes made to the
	* list will be visible in the array. The returned list is
	* {@link Serializable} and implements {@link RandomAccess}.
	*
	* <p>The returned list implements the optional {@code Collection} methods, except
	* those that would change the size of the returned list. Those methods leave
	* the list unchanged and throw {@link UnsupportedOperationException}.
	*
	* @apiNote
	* This method acts as bridge between array-based and collection-based
	* APIs, in combination with {@link Collection#toArray}.
	*
	* <p>This method provides a way to wrap an existing array:
	* <pre>{@code
	* Integer[] numbers = ...
	* ...
	* List<Integer> values = Arrays.asList(numbers);
	* }</pre>
	*
	* <p>This method also provides a convenient way to create a fixed-size
	* list initialized to contain several elements:
	* <pre>{@code
	* List<String> stooges = Arrays.asList("Larry", "Moe", "Curly");
	* }</pre>
	*
	* <p><em>The list returned by this method is modifiable.</em>
	* To create an unmodifiable list, use
	* {@link Collections#unmodifiableList Collections.unmodifiableList}
	* or <a href="List.html#unmodifiable">Unmodifiable Lists</a>.
	*
	* @param <T> the class of the objects in the array
	* @param a the array by which the list will be backed
	* @return a list view of the specified array
	* @throws NullPointerException if the specified array is {@code null}
	*/
	@SafeVarargs
	@SuppressWarnings("varargs")
	public static <T> List<T> asList(T... a) {
	return new ArrayList<>(a);
	}

	/**
	* @serial include
	*/
	private static class ArrayList<E> extends AbstractList<E>
	implements RandomAccess, java.io.Serializable
	{
	@java.io.Serial
	private static final long serialVersionUID = -2764017481108945198L;
	@SuppressWarnings("serial") // Conditionally serializable
	private final E[] a;

	ArrayList(E[] array) {
	a = Objects.requireNonNull(array);
	}

	@Override
	public int size() {
	return a.length;
	}

	@Override
	public Object[] toArray() {
	return Arrays.copyOf(a, a.length, Object[].class);
	}

	@Override
	@SuppressWarnings("unchecked")
	public <T> T[] toArray(T[] a) {
	int size = size();
	if (a.length < size)
	return Arrays.copyOf(this.a, size,
	(Class<? extends T[]>) a.getClass());
	System.arraycopy(this.a, 0, a, 0, size);
	if (a.length > size)
	a[size] = null;
	return a;
	}

	@Override
	public E get(int index) {
	return a[index];
	}

	@Override
	public E set(int index, E element) {
	E oldValue = a[index];
	a[index] = element;
	return oldValue;
	}

	@Override
	public int indexOf(Object o) {
	E[] a = this.a;
	if (o == null) {
	for (int i = 0; i < a.length; i++)
	if (a[i] == null)
	return i;
	} else {
	for (int i = 0; i < a.length; i++)
	if (o.equals(a[i]))
	return i;
	}
	return -1;
	}

	@Override
	public boolean contains(Object o) {
	return indexOf(o) >= 0;
	}

	@Override
	public Spliterator<E> spliterator() {
	return Spliterators.spliterator(a, Spliterator.ORDERED);
	}

	@Override
	public void forEach(Consumer<? super E> action) {
	Objects.requireNonNull(action);
	for (E e : a) {
	action.accept(e);
	}
	}

	@Override
	public void replaceAll(UnaryOperator<E> operator) {
	Objects.requireNonNull(operator);
	E[] a = this.a;
	for (int i = 0; i < a.length; i++) {
	a[i] = operator.apply(a[i]);
	}
	}

	@Override
	public void sort(Comparator<? super E> c) {
	Arrays.sort(a, c);
	}

	@Override
	public Iterator<E> iterator() {
	return new ArrayItr<>(a);
	}
	}

	private static class ArrayItr<E> implements Iterator<E> {
	private int cursor;
	private final E[] a;

	ArrayItr(E[] a) {
	this.a = a;
	}

	@Override
	public boolean hasNext() {
	return cursor < a.length;
	}

	@Override
	public E next() {
	int i = cursor;
	if (i >= a.length) {
	throw new NoSuchElementException();
	}
	cursor = i + 1;
	return a[i];
	}
	}

	/**
	* Returns a hash code based on the contents of the specified array.
	* For any two {@code long} arrays {@code a} and {@code b}
	* such that {@code Arrays.equals(a, b)}, it is also the case that
	* {@code Arrays.hashCode(a) == Arrays.hashCode(b)}.
	*
	* <p>The value returned by this method is the same value that would be
	* obtained by invoking the {@link List#hashCode() hashCode}
	* method on a {@link List} containing a sequence of {@link Long}
	* instances representing the elements of {@code a} in the same order.
	* If {@code a} is {@code null}, this method returns 0.
	*
	* @param a the array whose hash value to compute
	* @return a content-based hash code for {@code a}
	* @since 1.5
	*/
	public static int hashCode(long a[]) {
	if (a == null)
	return 0;

	int result = 1;
	for (long element : a) {
	int elementHash = (int)(element ^ (element >>> 32));
	result = 31 * result + elementHash;
	}

	return result;
	}

	/**
	* Returns a hash code based on the contents of the specified array.
	* For any two non-null {@code int} arrays {@code a} and {@code b}
	* such that {@code Arrays.equals(a, b)}, it is also the case that
	* {@code Arrays.hashCode(a) == Arrays.hashCode(b)}.
	*
	* <p>The value returned by this method is the same value that would be
	* obtained by invoking the {@link List#hashCode() hashCode}
	* method on a {@link List} containing a sequence of {@link Integer}
	* instances representing the elements of {@code a} in the same order.
	* If {@code a} is {@code null}, this method returns 0.
	*
	* @param a the array whose hash value to compute
	* @return a content-based hash code for {@code a}
	* @since 1.5
	*/
	public static int hashCode(int a[]) {
	if (a == null)
	return 0;

	int result = 1;
	for (int element : a)
	result = 31 * result + element;

	return result;
	}

	/**
	* Returns a hash code based on the contents of the specified array.
	* For any two {@code short} arrays {@code a} and {@code b}
	* such that {@code Arrays.equals(a, b)}, it is also the case that
	* {@code Arrays.hashCode(a) == Arrays.hashCode(b)}.
	*
	* <p>The value returned by this method is the same value that would be
	* obtained by invoking the {@link List#hashCode() hashCode}
	* method on a {@link List} containing a sequence of {@link Short}
	* instances representing the elements of {@code a} in the same order.
	* If {@code a} is {@code null}, this method returns 0.
	*
	* @param a the array whose hash value to compute
	* @return a content-based hash code for {@code a}
	* @since 1.5
	*/
	public static int hashCode(short a[]) {
	if (a == null)
	return 0;

	int result = 1;
	for (short element : a)
	result = 31 * result + element;

	return result;
	}

	/**
	* Returns a hash code based on the contents of the specified array.
	* For any two {@code char} arrays {@code a} and {@code b}
	* such that {@code Arrays.equals(a, b)}, it is also the case that
	* {@code Arrays.hashCode(a) == Arrays.hashCode(b)}.
	*
	* <p>The value returned by this method is the same value that would be
	* obtained by invoking the {@link List#hashCode() hashCode}
	* method on a {@link List} containing a sequence of {@link Character}
	* instances representing the elements of {@code a} in the same order.
	* If {@code a} is {@code null}, this method returns 0.
	*
	* @param a the array whose hash value to compute
	* @return a content-based hash code for {@code a}
	* @since 1.5
	*/
	public static int hashCode(char a[]) {
	if (a == null)
	return 0;

	int result = 1;
	for (char element : a)
	result = 31 * result + element;

	return result;
	}

	/**
	* Returns a hash code based on the contents of the specified array.
	* For any two {@code byte} arrays {@code a} and {@code b}
	* such that {@code Arrays.equals(a, b)}, it is also the case that
	* {@code Arrays.hashCode(a) == Arrays.hashCode(b)}.
	*
	* <p>The value returned by this method is the same value that would be
	* obtained by invoking the {@link List#hashCode() hashCode}
	* method on a {@link List} containing a sequence of {@link Byte}
	* instances representing the elements of {@code a} in the same order.
	* If {@code a} is {@code null}, this method returns 0.
	*
	* @param a the array whose hash value to compute
	* @return a content-based hash code for {@code a}
	* @since 1.5
	*/
	public static int hashCode(byte a[]) {
	if (a == null)
	return 0;

	int result = 1;
	for (byte element : a)
	result = 31 * result + element;

	return result;
	}

	/**
	* Returns a hash code based on the contents of the specified array.
	* For any two {@code boolean} arrays {@code a} and {@code b}
	* such that {@code Arrays.equals(a, b)}, it is also the case that
	* {@code Arrays.hashCode(a) == Arrays.hashCode(b)}.
	*
	* <p>The value returned by this method is the same value that would be
	* obtained by invoking the {@link List#hashCode() hashCode}
	* method on a {@link List} containing a sequence of {@link Boolean}
	* instances representing the elements of {@code a} in the same order.
	* If {@code a} is {@code null}, this method returns 0.
	*
	* @param a the array whose hash value to compute
	* @return a content-based hash code for {@code a}
	* @since 1.5
	*/
	public static int hashCode(boolean a[]) {
	if (a == null)
	return 0;

	int result = 1;
	for (boolean element : a)
	result = 31 * result + (element ? 1231 : 1237);

	return result;
	}

	/**
	* Returns a hash code based on the contents of the specified array.
	* For any two {@code float} arrays {@code a} and {@code b}
	* such that {@code Arrays.equals(a, b)}, it is also the case that
	* {@code Arrays.hashCode(a) == Arrays.hashCode(b)}.
	*
	* <p>The value returned by this method is the same value that would be
	* obtained by invoking the {@link List#hashCode() hashCode}
	* method on a {@link List} containing a sequence of {@link Float}
	* instances representing the elements of {@code a} in the same order.
	* If {@code a} is {@code null}, this method returns 0.
	*
	* @param a the array whose hash value to compute
	* @return a content-based hash code for {@code a}
	* @since 1.5
	*/
	public static int hashCode(float a[]) {
	if (a == null)
	return 0;

	int result = 1;
	for (float element : a)
	result = 31 * result + Float.floatToIntBits(element);

	return result;
	}

	/**
	* Returns a hash code based on the contents of the specified array.
	* For any two {@code double} arrays {@code a} and {@code b}
	* such that {@code Arrays.equals(a, b)}, it is also the case that
	* {@code Arrays.hashCode(a) == Arrays.hashCode(b)}.
	*
	* <p>The value returned by this method is the same value that would be
	* obtained by invoking the {@link List#hashCode() hashCode}
	* method on a {@link List} containing a sequence of {@link Double}
	* instances representing the elements of {@code a} in the same order.
	* If {@code a} is {@code null}, this method returns 0.
	*
	* @param a the array whose hash value to compute
	* @return a content-based hash code for {@code a}
	* @since 1.5
	*/
	public static int hashCode(double a[]) {
	if (a == null)
	return 0;

	int result = 1;
	for (double element : a) {
	long bits = Double.doubleToLongBits(element);
	result = 31 * result + (int)(bits ^ (bits >>> 32));
	}
	return result;
	}

	/**
	* Returns a hash code based on the contents of the specified array. If
	* the array contains other arrays as elements, the hash code is based on
	* their identities rather than their contents. It is therefore
	* acceptable to invoke this method on an array that contains itself as an
	* element, either directly or indirectly through one or more levels of
	* arrays.
	*
	* <p>For any two arrays {@code a} and {@code b} such that
	* {@code Arrays.equals(a, b)}, it is also the case that
	* {@code Arrays.hashCode(a) == Arrays.hashCode(b)}.
	*
	* <p>The value returned by this method is equal to the value that would
	* be returned by {@code Arrays.asList(a).hashCode()}, unless {@code a}
	* is {@code null}, in which case {@code 0} is returned.
	*
	* @param a the array whose content-based hash code to compute
	* @return a content-based hash code for {@code a}
	* @see #deepHashCode(Object[])
	* @since 1.5
	*/
	public static int hashCode(Object a[]) {
	if (a == null)
	return 0;

	int result = 1;

	for (Object element : a)
	result = 31 * result + (element == null ? 0 : element.hashCode());

	return result;
	}

	/**
	* Returns a hash code based on the "deep contents" of the specified
	* array. If the array contains other arrays as elements, the
	* hash code is based on their contents and so on, ad infinitum.
	* It is therefore unacceptable to invoke this method on an array that
	* contains itself as an element, either directly or indirectly through
	* one or more levels of arrays. The behavior of such an invocation is
	* undefined.
	*
	* <p>For any two arrays {@code a} and {@code b} such that
	* {@code Arrays.deepEquals(a, b)}, it is also the case that
	* {@code Arrays.deepHashCode(a) == Arrays.deepHashCode(b)}.
	*
	* <p>The computation of the value returned by this method is similar to
	* that of the value returned by {@link List#hashCode()} on a list
	* containing the same elements as {@code a} in the same order, with one
	* difference: If an element {@code e} of {@code a} is itself an array,
	* its hash code is computed not by calling {@code e.hashCode()}, but as
	* by calling the appropriate overloading of {@code Arrays.hashCode(e)}
	* if {@code e} is an array of a primitive type, or as by calling
	* {@code Arrays.deepHashCode(e)} recursively if {@code e} is an array
	* of a reference type. If {@code a} is {@code null}, this method
	* returns 0.
	*
	* @param a the array whose deep-content-based hash code to compute
	* @return a deep-content-based hash code for {@code a}
	* @see #hashCode(Object[])
	* @since 1.5
	*/
	public static int deepHashCode(Object a[]) {
	if (a == null)
	return 0;

	int result = 1;

	for (Object element : a) {
	final int elementHash;
	final Class<?> cl;
	if (element == null)
	elementHash = 0;
	else if ((cl = element.getClass().getComponentType()) == null)
	elementHash = element.hashCode();
	else if (element instanceof Object[])
	elementHash = deepHashCode((Object[]) element);
	else
	elementHash = primitiveArrayHashCode(element, cl);

	result = 31 * result + elementHash;
	}

	return result;
	}

	private static int primitiveArrayHashCode(Object a, Class<?> cl) {
	return
	(cl == byte.class) ? hashCode((byte[]) a) :
	(cl == int.class) ? hashCode((int[]) a) :
	(cl == long.class) ? hashCode((long[]) a) :
	(cl == char.class) ? hashCode((char[]) a) :
	(cl == short.class) ? hashCode((short[]) a) :
	(cl == boolean.class) ? hashCode((boolean[]) a) :
	(cl == double.class) ? hashCode((double[]) a) :
	// If new primitive types are ever added, this method must be
	// expanded or we will fail here with ClassCastException.
	hashCode((float[]) a);
	}

	/**
	* Returns {@code true} if the two specified arrays are <i>deeply
	* equal</i> to one another. Unlike the {@link #equals(Object[],Object[])}
	* method, this method is appropriate for use with nested arrays of
	* arbitrary depth.
	*
	* <p>Two array references are considered deeply equal if both
	* are {@code null}, or if they refer to arrays that contain the same
	* number of elements and all corresponding pairs of elements in the two
	* arrays are deeply equal.
	*
	* <p>Two possibly {@code null} elements {@code e1} and {@code e2} are
	* deeply equal if any of the following conditions hold:
	* <ul>
	* <li> {@code e1} and {@code e2} are both arrays of object reference
	* types, and {@code Arrays.deepEquals(e1, e2) would return true}
	* <li> {@code e1} and {@code e2} are arrays of the same primitive
	* type, and the appropriate overloading of
	* {@code Arrays.equals(e1, e2)} would return true.
	* <li> {@code e1 == e2}
	* <li> {@code e1.equals(e2)} would return true.
	* </ul>
	* Note that this definition permits {@code null} elements at any depth.
	*
	* <p>If either of the specified arrays contain themselves as elements
	* either directly or indirectly through one or more levels of arrays,
	* the behavior of this method is undefined.
	*
	* @param a1 one array to be tested for equality
	* @param a2 the other array to be tested for equality
	* @return {@code true} if the two arrays are equal
	* @see #equals(Object[],Object[])
	* @see Objects#deepEquals(Object, Object)
	* @since 1.5
	*/
	public static boolean deepEquals(Object[] a1, Object[] a2) {
	if (a1 == a2)
	return true;
	if (a1 == null \|\| a2==null)
	return false;
	int length = a1.length;
	if (a2.length != length)
	return false;

	for (int i = 0; i < length; i++) {
	Object e1 = a1[i];
	Object e2 = a2[i];

	if (e1 == e2)
	continue;
	if (e1 == null)
	return false;

	// Figure out whether the two elements are equal
	boolean eq = deepEquals0(e1, e2);

	if (!eq)
	return false;
	}
	return true;
	}

	static boolean deepEquals0(Object e1, Object e2) {
	assert e1 != null;
	boolean eq;
	if (e1 instanceof Object[] && e2 instanceof Object[])
	eq = deepEquals ((Object[]) e1, (Object[]) e2);
	else if (e1 instanceof byte[] && e2 instanceof byte[])
	eq = equals((byte[]) e1, (byte[]) e2);
	else if (e1 instanceof short[] && e2 instanceof short[])
	eq = equals((short[]) e1, (short[]) e2);
	else if (e1 instanceof int[] && e2 instanceof int[])
	eq = equals((int[]) e1, (int[]) e2);
	else if (e1 instanceof long[] && e2 instanceof long[])
	eq = equals((long[]) e1, (long[]) e2);
	else if (e1 instanceof char[] && e2 instanceof char[])
	eq = equals((char[]) e1, (char[]) e2);
	else if (e1 instanceof float[] && e2 instanceof float[])
	eq = equals((float[]) e1, (float[]) e2);
	else if (e1 instanceof double[] && e2 instanceof double[])
	eq = equals((double[]) e1, (double[]) e2);
	else if (e1 instanceof boolean[] && e2 instanceof boolean[])
	eq = equals((boolean[]) e1, (boolean[]) e2);
	else
	eq = e1.equals(e2);
	return eq;
	}

	/**
	* Returns a string representation of the contents of the specified array.
	* The string representation consists of a list of the array's elements,
	* enclosed in square brackets ({@code "[]"}). Adjacent elements are
	* separated by the characters {@code ", "} (a comma followed by a
	* space). Elements are converted to strings as by
	* {@code String.valueOf(long)}. Returns {@code "null"} if {@code a}
	* is {@code null}.
	*
	* @param a the array whose string representation to return
	* @return a string representation of {@code a}
	* @since 1.5
	*/
	public static String toString(long[] a) {
	if (a == null)
	return "null";
	int iMax = a.length - 1;
	if (iMax == -1)
	return "[]";

	StringBuilder b = new StringBuilder();
	b.append('[');
	for (int i = 0; ; i++) {
	b.append(a[i]);
	if (i == iMax)
	return b.append(']').toString();
	b.append(", ");
	}
	}

	/**
	* Returns a string representation of the contents of the specified array.
	* The string representation consists of a list of the array's elements,
	* enclosed in square brackets ({@code "[]"}). Adjacent elements are
	* separated by the characters {@code ", "} (a comma followed by a
	* space). Elements are converted to strings as by
	* {@code String.valueOf(int)}. Returns {@code "null"} if {@code a} is
	* {@code null}.
	*
	* @param a the array whose string representation to return
	* @return a string representation of {@code a}
	* @since 1.5
	*/
	public static String toString(int[] a) {
	if (a == null)
	return "null";
	int iMax = a.length - 1;
	if (iMax == -1)
	return "[]";

	StringBuilder b = new StringBuilder();
	b.append('[');
	for (int i = 0; ; i++) {
	b.append(a[i]);
	if (i == iMax)
	return b.append(']').toString();
	b.append(", ");
	}
	}

	/**
	* Returns a string representation of the contents of the specified array.
	* The string representation consists of a list of the array's elements,
	* enclosed in square brackets ({@code "[]"}). Adjacent elements are
	* separated by the characters {@code ", "} (a comma followed by a
	* space). Elements are converted to strings as by
	* {@code String.valueOf(short)}. Returns {@code "null"} if {@code a}
	* is {@code null}.
	*
	* @param a the array whose string representation to return
	* @return a string representation of {@code a}
	* @since 1.5
	*/
	public static String toString(short[] a) {
	if (a == null)
	return "null";
	int iMax = a.length - 1;
	if (iMax == -1)
	return "[]";

	StringBuilder b = new StringBuilder();
	b.append('[');
	for (int i = 0; ; i++) {
	b.append(a[i]);
	if (i == iMax)
	return b.append(']').toString();
	b.append(", ");
	}
	}

	/**
	* Returns a string representation of the contents of the specified array.
	* The string representation consists of a list of the array's elements,
	* enclosed in square brackets ({@code "[]"}). Adjacent elements are
	* separated by the characters {@code ", "} (a comma followed by a
	* space). Elements are converted to strings as by
	* {@code String.valueOf(char)}. Returns {@code "null"} if {@code a}
	* is {@code null}.
	*
	* @param a the array whose string representation to return
	* @return a string representation of {@code a}
	* @since 1.5
	*/
	public static String toString(char[] a) {
	if (a == null)
	return "null";
	int iMax = a.length - 1;
	if (iMax == -1)
	return "[]";

	StringBuilder b = new StringBuilder();
	b.append('[');
	for (int i = 0; ; i++) {
	b.append(a[i]);
	if (i == iMax)
	return b.append(']').toString();
	b.append(", ");
	}
	}

	/**
	* Returns a string representation of the contents of the specified array.
	* The string representation consists of a list of the array's elements,
	* enclosed in square brackets ({@code "[]"}). Adjacent elements
	* are separated by the characters {@code ", "} (a comma followed
	* by a space). Elements are converted to strings as by
	* {@code String.valueOf(byte)}. Returns {@code "null"} if
	* {@code a} is {@code null}.
	*
	* @param a the array whose string representation to return
	* @return a string representation of {@code a}
	* @since 1.5
	*/
	public static String toString(byte[] a) {
	if (a == null)
	return "null";
	int iMax = a.length - 1;
	if (iMax == -1)
	return "[]";

	StringBuilder b = new StringBuilder();
	b.append('[');
	for (int i = 0; ; i++) {
	b.append(a[i]);
	if (i == iMax)
	return b.append(']').toString();
	b.append(", ");
	}
	}

	/**
	* Returns a string representation of the contents of the specified array.
	* The string representation consists of a list of the array's elements,
	* enclosed in square brackets ({@code "[]"}). Adjacent elements are
	* separated by the characters {@code ", "} (a comma followed by a
	* space). Elements are converted to strings as by
	* {@code String.valueOf(boolean)}. Returns {@code "null"} if
	* {@code a} is {@code null}.
	*
	* @param a the array whose string representation to return
	* @return a string representation of {@code a}
	* @since 1.5
	*/
	public static String toString(boolean[] a) {
	if (a == null)
	return "null";
	int iMax = a.length - 1;
	if (iMax == -1)
	return "[]";

	StringBuilder b = new StringBuilder();
	b.append('[');
	for (int i = 0; ; i++) {
	b.append(a[i]);
	if (i == iMax)
	return b.append(']').toString();
	b.append(", ");
	}
	}

	/**
	* Returns a string representation of the contents of the specified array.
	* The string representation consists of a list of the array's elements,
	* enclosed in square brackets ({@code "[]"}). Adjacent elements are
	* separated by the characters {@code ", "} (a comma followed by a
	* space). Elements are converted to strings as by
	* {@code String.valueOf(float)}. Returns {@code "null"} if {@code a}
	* is {@code null}.
	*
	* @param a the array whose string representation to return
	* @return a string representation of {@code a}
	* @since 1.5
	*/
	public static String toString(float[] a) {
	if (a == null)
	return "null";

	int iMax = a.length - 1;
	if (iMax == -1)
	return "[]";

	StringBuilder b = new StringBuilder();
	b.append('[');
	for (int i = 0; ; i++) {
	b.append(a[i]);
	if (i == iMax)
	return b.append(']').toString();
	b.append(", ");
	}
	}

	/**
	* Returns a string representation of the contents of the specified array.
	* The string representation consists of a list of the array's elements,
	* enclosed in square brackets ({@code "[]"}). Adjacent elements are
	* separated by the characters {@code ", "} (a comma followed by a
	* space). Elements are converted to strings as by
	* {@code String.valueOf(double)}. Returns {@code "null"} if {@code a}
	* is {@code null}.
	*
	* @param a the array whose string representation to return
	* @return a string representation of {@code a}
	* @since 1.5
	*/
	public static String toString(double[] a) {
	if (a == null)
	return "null";
	int iMax = a.length - 1;
	if (iMax == -1)
	return "[]";

	StringBuilder b = new StringBuilder();
	b.append('[');
	for (int i = 0; ; i++) {
	b.append(a[i]);
	if (i == iMax)
	return b.append(']').toString();
	b.append(", ");
	}
	}

	/**
	* Returns a string representation of the contents of the specified array.
	* If the array contains other arrays as elements, they are converted to
	* strings by the {@link Object#toString} method inherited from
	* {@code Object}, which describes their <i>identities</i> rather than
	* their contents.
	*
	* <p>The value returned by this method is equal to the value that would
	* be returned by {@code Arrays.asList(a).toString()}, unless {@code a}
	* is {@code null}, in which case {@code "null"} is returned.
	*
	* @param a the array whose string representation to return
	* @return a string representation of {@code a}
	* @see #deepToString(Object[])
	* @since 1.5
	*/
	public static String toString(Object[] a) {
	if (a == null)
	return "null";

	int iMax = a.length - 1;
	if (iMax == -1)
	return "[]";

	StringBuilder b = new StringBuilder();
	b.append('[');
	for (int i = 0; ; i++) {
	b.append(String.valueOf(a[i]));
	if (i == iMax)
	return b.append(']').toString();
	b.append(", ");
	}
	}

	/**
	* Returns a string representation of the "deep contents" of the specified
	* array. If the array contains other arrays as elements, the string
	* representation contains their contents and so on. This method is
	* designed for converting multidimensional arrays to strings.
	*
	* <p>The string representation consists of a list of the array's
	* elements, enclosed in square brackets ({@code "[]"}). Adjacent
	* elements are separated by the characters {@code ", "} (a comma
	* followed by a space). Elements are converted to strings as by
	* {@code String.valueOf(Object)}, unless they are themselves
	* arrays.
	*
	* <p>If an element {@code e} is an array of a primitive type, it is
	* converted to a string as by invoking the appropriate overloading of
	* {@code Arrays.toString(e)}. If an element {@code e} is an array of a
	* reference type, it is converted to a string as by invoking
	* this method recursively.
	*
	* <p>To avoid infinite recursion, if the specified array contains itself
	* as an element, or contains an indirect reference to itself through one
	* or more levels of arrays, the self-reference is converted to the string
	* {@code "[...]"}. For example, an array containing only a reference
	* to itself would be rendered as {@code "[[...]]"}.
	*
	* <p>This method returns {@code "null"} if the specified array
	* is {@code null}.
	*
	* @param a the array whose string representation to return
	* @return a string representation of {@code a}
	* @see #toString(Object[])
	* @since 1.5
	*/
	public static String deepToString(Object[] a) {
	if (a == null)
	return "null";

	int bufLen = 20 * a.length;
	if (a.length != 0 && bufLen <= 0)
	bufLen = Integer.MAX_VALUE;
	StringBuilder buf = new StringBuilder(bufLen);
	deepToString(a, buf, new HashSet<>());
	return buf.toString();
	}

	private static void deepToString(Object[] a, StringBuilder buf,
	Set<Object[]> dejaVu) {
	if (a == null) {
	buf.append("null");
	return;
	}
	int iMax = a.length - 1;
	if (iMax == -1) {
	buf.append("[]");
	return;
	}

	dejaVu.add(a);
	buf.append('[');
	for (int i = 0; ; i++) {

	Object element = a[i];
	if (element == null) {
	buf.append("null");
	} else {
	Class<?> eClass = element.getClass();

	if (eClass.isArray()) {
	if (eClass == byte[].class)
	buf.append(toString((byte[]) element));
	else if (eClass == short[].class)
	buf.append(toString((short[]) element));
	else if (eClass == int[].class)
	buf.append(toString((int[]) element));
	else if (eClass == long[].class)
	buf.append(toString((long[]) element));
	else if (eClass == char[].class)
	buf.append(toString((char[]) element));
	else if (eClass == float[].class)
	buf.append(toString((float[]) element));
	else if (eClass == double[].class)
	buf.append(toString((double[]) element));
	else if (eClass == boolean[].class)
	buf.append(toString((boolean[]) element));
	else { // element is an array of object references
	if (dejaVu.contains(element))
	buf.append("[...]");
	else
	deepToString((Object[])element, buf, dejaVu);
	}
	} else { // element is non-null and not an array
	buf.append(element.toString());
	}
	}
	if (i == iMax)
	break;
	buf.append(", ");
	}
	buf.append(']');
	dejaVu.remove(a);
	}


	/**
	* Set all elements of the specified array, using the provided
	* generator function to compute each element.
	*
	* <p>If the generator function throws an exception, it is relayed to
	* the caller and the array is left in an indeterminate state.
	*
	* @apiNote
	* Setting a subrange of an array, using a generator function to compute
	* each element, can be written as follows:
	* <pre>{@code
	* IntStream.range(startInclusive, endExclusive)
	* .forEach(i -> array[i] = generator.apply(i));
	* }</pre>
	*
	* @param <T> type of elements of the array
	* @param array array to be initialized
	* @param generator a function accepting an index and producing the desired
	* value for that position
	* @throws NullPointerException if the generator is null
	* @since 1.8
	*/
	public static <T> void setAll(T[] array, IntFunction<? extends T> generator) {
	Objects.requireNonNull(generator);
	for (int i = 0; i < array.length; i++)
	array[i] = generator.apply(i);
	}

	/**
	* Set all elements of the specified array, in parallel, using the
	* provided generator function to compute each element.
	*
	* <p>If the generator function throws an exception, an unchecked exception
	* is thrown from {@code parallelSetAll} and the array is left in an
	* indeterminate state.
	*
	* @apiNote
	* Setting a subrange of an array, in parallel, using a generator function
	* to compute each element, can be written as follows:
	* <pre>{@code
	* IntStream.range(startInclusive, endExclusive)
	* .parallel()
	* .forEach(i -> array[i] = generator.apply(i));
	* }</pre>
	*
	* @param <T> type of elements of the array
	* @param array array to be initialized
	* @param generator a function accepting an index and producing the desired
	* value for that position
	* @throws NullPointerException if the generator is null
	* @since 1.8
	*/
	public static <T> void parallelSetAll(T[] array, IntFunction<? extends T> generator) {
	Objects.requireNonNull(generator);
	IntStream.range(0, array.length).parallel().forEach(i -> { array[i] = generator.apply(i); });
	}

	/**
	* Set all elements of the specified array, using the provided
	* generator function to compute each element.
	*
	* <p>If the generator function throws an exception, it is relayed to
	* the caller and the array is left in an indeterminate state.
	*
	* @apiNote
	* Setting a subrange of an array, using a generator function to compute
	* each element, can be written as follows:
	* <pre>{@code
	* IntStream.range(startInclusive, endExclusive)
	* .forEach(i -> array[i] = generator.applyAsInt(i));
	* }</pre>
	*
	* @param array array to be initialized
	* @param generator a function accepting an index and producing the desired
	* value for that position
	* @throws NullPointerException if the generator is null
	* @since 1.8
	*/
	public static void setAll(int[] array, IntUnaryOperator generator) {
	Objects.requireNonNull(generator);
	for (int i = 0; i < array.length; i++)
	array[i] = generator.applyAsInt(i);
	}

	/**
	* Set all elements of the specified array, in parallel, using the
	* provided generator function to compute each element.
	*
	* <p>If the generator function throws an exception, an unchecked exception
	* is thrown from {@code parallelSetAll} and the array is left in an
	* indeterminate state.
	*
	* @apiNote
	* Setting a subrange of an array, in parallel, using a generator function
	* to compute each element, can be written as follows:
	* <pre>{@code
	* IntStream.range(startInclusive, endExclusive)
	* .parallel()
	* .forEach(i -> array[i] = generator.applyAsInt(i));
	* }</pre>
	*
	* @param array array to be initialized
	* @param generator a function accepting an index and producing the desired
	* value for that position
	* @throws NullPointerException if the generator is null
	* @since 1.8
	*/
	public static void parallelSetAll(int[] array, IntUnaryOperator generator) {
	Objects.requireNonNull(generator);
	IntStream.range(0, array.length).parallel().forEach(i -> { array[i] = generator.applyAsInt(i); });
	}

	/**
	* Set all elements of the specified array, using the provided
	* generator function to compute each element.
	*
	* <p>If the generator function throws an exception, it is relayed to
	* the caller and the array is left in an indeterminate state.
	*
	* @apiNote
	* Setting a subrange of an array, using a generator function to compute
	* each element, can be written as follows:
	* <pre>{@code
	* IntStream.range(startInclusive, endExclusive)
	* .forEach(i -> array[i] = generator.applyAsLong(i));
	* }</pre>
	*
	* @param array array to be initialized
	* @param generator a function accepting an index and producing the desired
	* value for that position
	* @throws NullPointerException if the generator is null
	* @since 1.8
	*/
	public static void setAll(long[] array, IntToLongFunction generator) {
	Objects.requireNonNull(generator);
	for (int i = 0; i < array.length; i++)
	array[i] = generator.applyAsLong(i);
	}

	/**
	* Set all elements of the specified array, in parallel, using the
	* provided generator function to compute each element.
	*
	* <p>If the generator function throws an exception, an unchecked exception
	* is thrown from {@code parallelSetAll} and the array is left in an
	* indeterminate state.
	*
	* @apiNote
	* Setting a subrange of an array, in parallel, using a generator function
	* to compute each element, can be written as follows:
	* <pre>{@code
	* IntStream.range(startInclusive, endExclusive)
	* .parallel()
	* .forEach(i -> array[i] = generator.applyAsLong(i));
	* }</pre>
	*
	* @param array array to be initialized
	* @param generator a function accepting an index and producing the desired
	* value for that position
	* @throws NullPointerException if the generator is null
	* @since 1.8
	*/
	public static void parallelSetAll(long[] array, IntToLongFunction generator) {
	Objects.requireNonNull(generator);
	IntStream.range(0, array.length).parallel().forEach(i -> { array[i] = generator.applyAsLong(i); });
	}

	/**
	* Set all elements of the specified array, using the provided
	* generator function to compute each element.
	*
	* <p>If the generator function throws an exception, it is relayed to
	* the caller and the array is left in an indeterminate state.
	*
	* @apiNote
	* Setting a subrange of an array, using a generator function to compute
	* each element, can be written as follows:
	* <pre>{@code
	* IntStream.range(startInclusive, endExclusive)
	* .forEach(i -> array[i] = generator.applyAsDouble(i));
	* }</pre>
	*
	* @param array array to be initialized
	* @param generator a function accepting an index and producing the desired
	* value for that position
	* @throws NullPointerException if the generator is null
	* @since 1.8
	*/
	public static void setAll(double[] array, IntToDoubleFunction generator) {
	Objects.requireNonNull(generator);
	for (int i = 0; i < array.length; i++)
	array[i] = generator.applyAsDouble(i);
	}

	/**
	* Set all elements of the specified array, in parallel, using the
	* provided generator function to compute each element.
	*
	* <p>If the generator function throws an exception, an unchecked exception
	* is thrown from {@code parallelSetAll} and the array is left in an
	* indeterminate state.
	*
	* @apiNote
	* Setting a subrange of an array, in parallel, using a generator function
	* to compute each element, can be written as follows:
	* <pre>{@code
	* IntStream.range(startInclusive, endExclusive)
	* .parallel()
	* .forEach(i -> array[i] = generator.applyAsDouble(i));
	* }</pre>
	*
	* @param array array to be initialized
	* @param generator a function accepting an index and producing the desired
	* value for that position
	* @throws NullPointerException if the generator is null
	* @since 1.8
	*/
	public static void parallelSetAll(double[] array, IntToDoubleFunction generator) {
	Objects.requireNonNull(generator);
	IntStream.range(0, array.length).parallel().forEach(i -> { array[i] = generator.applyAsDouble(i); });
	}

	/**
	* Returns a {@link Spliterator} covering all of the specified array.
	*
	* <p>The spliterator reports {@link Spliterator#SIZED},
	* {@link Spliterator#SUBSIZED}, {@link Spliterator#ORDERED}, and
	* {@link Spliterator#IMMUTABLE}.
	*
	* @param <T> type of elements
	* @param array the array, assumed to be unmodified during use
	* @return a spliterator for the array elements
	* @since 1.8
	*/
	public static <T> Spliterator<T> spliterator(T[] array) {
	return Spliterators.spliterator(array,
	Spliterator.ORDERED \| Spliterator.IMMUTABLE);
	}

	/**
	* Returns a {@link Spliterator} covering the specified range of the
	* specified array.
	*
	* <p>The spliterator reports {@link Spliterator#SIZED},
	* {@link Spliterator#SUBSIZED}, {@link Spliterator#ORDERED}, and
	* {@link Spliterator#IMMUTABLE}.
	*
	* @param <T> type of elements
	* @param array the array, assumed to be unmodified during use
	* @param startInclusive the first index to cover, inclusive
	* @param endExclusive index immediately past the last index to cover
	* @return a spliterator for the array elements
	* @throws ArrayIndexOutOfBoundsException if {@code startInclusive} is
	* negative, {@code endExclusive} is less than
	* {@code startInclusive}, or {@code endExclusive} is greater than
	* the array size
	* @since 1.8
	*/
	public static <T> Spliterator<T> spliterator(T[] array, int startInclusive, int endExclusive) {
	return Spliterators.spliterator(array, startInclusive, endExclusive,
	Spliterator.ORDERED \| Spliterator.IMMUTABLE);
	}

	/**
	* Returns a {@link Spliterator.OfInt} covering all of the specified array.
	*
	* <p>The spliterator reports {@link Spliterator#SIZED},
	* {@link Spliterator#SUBSIZED}, {@link Spliterator#ORDERED}, and
	* {@link Spliterator#IMMUTABLE}.
	*
	* @param array the array, assumed to be unmodified during use
	* @return a spliterator for the array elements
	* @since 1.8
	*/
	public static Spliterator.OfInt spliterator(int[] array) {
	return Spliterators.spliterator(array,
	Spliterator.ORDERED \| Spliterator.IMMUTABLE);
	}

	/**
	* Returns a {@link Spliterator.OfInt} covering the specified range of the
	* specified array.
	*
	* <p>The spliterator reports {@link Spliterator#SIZED},
	* {@link Spliterator#SUBSIZED}, {@link Spliterator#ORDERED}, and
	* {@link Spliterator#IMMUTABLE}.
	*
	* @param array the array, assumed to be unmodified during use
	* @param startInclusive the first index to cover, inclusive
	* @param endExclusive index immediately past the last index to cover
	* @return a spliterator for the array elements
	* @throws ArrayIndexOutOfBoundsException if {@code startInclusive} is
	* negative, {@code endExclusive} is less than
	* {@code startInclusive}, or {@code endExclusive} is greater than
	* the array size
	* @since 1.8
	*/
	public static Spliterator.OfInt spliterator(int[] array, int startInclusive, int endExclusive) {
	return Spliterators.spliterator(array, startInclusive, endExclusive,
	Spliterator.ORDERED \| Spliterator.IMMUTABLE);
	}

	/**
	* Returns a {@link Spliterator.OfLong} covering all of the specified array.
	*
	* <p>The spliterator reports {@link Spliterator#SIZED},
	* {@link Spliterator#SUBSIZED}, {@link Spliterator#ORDERED}, and
	* {@link Spliterator#IMMUTABLE}.
	*
	* @param array the array, assumed to be unmodified during use
	* @return the spliterator for the array elements
	* @since 1.8
	*/
	public static Spliterator.OfLong spliterator(long[] array) {
	return Spliterators.spliterator(array,
	Spliterator.ORDERED \| Spliterator.IMMUTABLE);
	}

	/**
	* Returns a {@link Spliterator.OfLong} covering the specified range of the
	* specified array.
	*
	* <p>The spliterator reports {@link Spliterator#SIZED},
	* {@link Spliterator#SUBSIZED}, {@link Spliterator#ORDERED}, and
	* {@link Spliterator#IMMUTABLE}.
	*
	* @param array the array, assumed to be unmodified during use
	* @param startInclusive the first index to cover, inclusive
	* @param endExclusive index immediately past the last index to cover
	* @return a spliterator for the array elements
	* @throws ArrayIndexOutOfBoundsException if {@code startInclusive} is
	* negative, {@code endExclusive} is less than
	* {@code startInclusive}, or {@code endExclusive} is greater than
	* the array size
	* @since 1.8
	*/
	public static Spliterator.OfLong spliterator(long[] array, int startInclusive, int endExclusive) {
	return Spliterators.spliterator(array, startInclusive, endExclusive,
	Spliterator.ORDERED \| Spliterator.IMMUTABLE);
	}

	/**
	* Returns a {@link Spliterator.OfDouble} covering all of the specified
	* array.
	*
	* <p>The spliterator reports {@link Spliterator#SIZED},
	* {@link Spliterator#SUBSIZED}, {@link Spliterator#ORDERED}, and
	* {@link Spliterator#IMMUTABLE}.
	*
	* @param array the array, assumed to be unmodified during use
	* @return a spliterator for the array elements
	* @since 1.8
	*/
	public static Spliterator.OfDouble spliterator(double[] array) {
	return Spliterators.spliterator(array,
	Spliterator.ORDERED \| Spliterator.IMMUTABLE);
	}

	/**
	* Returns a {@link Spliterator.OfDouble} covering the specified range of
	* the specified array.
	*
	* <p>The spliterator reports {@link Spliterator#SIZED},
	* {@link Spliterator#SUBSIZED}, {@link Spliterator#ORDERED}, and
	* {@link Spliterator#IMMUTABLE}.
	*
	* @param array the array, assumed to be unmodified during use
	* @param startInclusive the first index to cover, inclusive
	* @param endExclusive index immediately past the last index to cover
	* @return a spliterator for the array elements
	* @throws ArrayIndexOutOfBoundsException if {@code startInclusive} is
	* negative, {@code endExclusive} is less than
	* {@code startInclusive}, or {@code endExclusive} is greater than
	* the array size
	* @since 1.8
	*/
	public static Spliterator.OfDouble spliterator(double[] array, int startInclusive, int endExclusive) {
	return Spliterators.spliterator(array, startInclusive, endExclusive,
	Spliterator.ORDERED \| Spliterator.IMMUTABLE);
	}

	/**
	* Returns a sequential {@link Stream} with the specified array as its
	* source.
	*
	* @param <T> The type of the array elements
	* @param array The array, assumed to be unmodified during use
	* @return a {@code Stream} for the array
	* @since 1.8
	*/
	public static <T> Stream<T> stream(T[] array) {
	return stream(array, 0, array.length);
	}

	/**
	* Returns a sequential {@link Stream} with the specified range of the
	* specified array as its source.
	*
	* @param <T> the type of the array elements
	* @param array the array, assumed to be unmodified during use
	* @param startInclusive the first index to cover, inclusive
	* @param endExclusive index immediately past the last index to cover
	* @return a {@code Stream} for the array range
	* @throws ArrayIndexOutOfBoundsException if {@code startInclusive} is
	* negative, {@code endExclusive} is less than
	* {@code startInclusive}, or {@code endExclusive} is greater than
	* the array size
	* @since 1.8
	*/
	public static <T> Stream<T> stream(T[] array, int startInclusive, int endExclusive) {
	return StreamSupport.stream(spliterator(array, startInclusive, endExclusive), false);
	}

	/**
	* Returns a sequential {@link IntStream} with the specified array as its
	* source.
	*
	* @param array the array, assumed to be unmodified during use
	* @return an {@code IntStream} for the array
	* @since 1.8
	*/
	public static IntStream stream(int[] array) {
	return stream(array, 0, array.length);
	}

	/**
	* Returns a sequential {@link IntStream} with the specified range of the
	* specified array as its source.
	*
	* @param array the array, assumed to be unmodified during use
	* @param startInclusive the first index to cover, inclusive
	* @param endExclusive index immediately past the last index to cover
	* @return an {@code IntStream} for the array range
	* @throws ArrayIndexOutOfBoundsException if {@code startInclusive} is
	* negative, {@code endExclusive} is less than
	* {@code startInclusive}, or {@code endExclusive} is greater than
	* the array size
	* @since 1.8
	*/
	public static IntStream stream(int[] array, int startInclusive, int endExclusive) {
	return StreamSupport.intStream(spliterator(array, startInclusive, endExclusive), false);
	}

	/**
	* Returns a sequential {@link LongStream} with the specified array as its
	* source.
	*
	* @param array the array, assumed to be unmodified during use
	* @return a {@code LongStream} for the array
	* @since 1.8
	*/
	public static LongStream stream(long[] array) {
	return stream(array, 0, array.length);
	}

	/**
	* Returns a sequential {@link LongStream} with the specified range of the
	* specified array as its source.
	*
	* @param array the array, assumed to be unmodified during use
	* @param startInclusive the first index to cover, inclusive
	* @param endExclusive index immediately past the last index to cover
	* @return a {@code LongStream} for the array range
	* @throws ArrayIndexOutOfBoundsException if {@code startInclusive} is
	* negative, {@code endExclusive} is less than
	* {@code startInclusive}, or {@code endExclusive} is greater than
	* the array size
	* @since 1.8
	*/
	public static LongStream stream(long[] array, int startInclusive, int endExclusive) {
	return StreamSupport.longStream(spliterator(array, startInclusive, endExclusive), false);
	}

	/**
	* Returns a sequential {@link DoubleStream} with the specified array as its
	* source.
	*
	* @param array the array, assumed to be unmodified during use
	* @return a {@code DoubleStream} for the array
	* @since 1.8
	*/
	public static DoubleStream stream(double[] array) {
	return stream(array, 0, array.length);
	}

	/**
	* Returns a sequential {@link DoubleStream} with the specified range of the
	* specified array as its source.
	*
	* @param array the array, assumed to be unmodified during use
	* @param startInclusive the first index to cover, inclusive
	* @param endExclusive index immediately past the last index to cover
	* @return a {@code DoubleStream} for the array range
	* @throws ArrayIndexOutOfBoundsException if {@code startInclusive} is
	* negative, {@code endExclusive} is less than
	* {@code startInclusive}, or {@code endExclusive} is greater than
	* the array size
	* @since 1.8
	*/
	public static DoubleStream stream(double[] array, int startInclusive, int endExclusive) {
	return StreamSupport.doubleStream(spliterator(array, startInclusive, endExclusive), false);
	}


	// Comparison methods

	// Compare boolean

	/**
	* Compares two {@code boolean} arrays lexicographically.
	*
	* <p>If the two arrays share a common prefix then the lexicographic
	* comparison is the result of comparing two elements, as if by
	* {@link Boolean#compare(boolean, boolean)}, at an index within the
	* respective arrays that is the prefix length.
	* Otherwise, one array is a proper prefix of the other and, lexicographic
	* comparison is the result of comparing the two array lengths.
	* (See {@link #mismatch(boolean[], boolean[])} for the definition of a
	* common and proper prefix.)
	*
	* <p>A {@code null} array reference is considered lexicographically less
	* than a non-{@code null} array reference. Two {@code null} array
	* references are considered equal.
	*
	* <p>The comparison is consistent with {@link #equals(boolean[], boolean[]) equals},
	* more specifically the following holds for arrays {@code a} and {@code b}:
	* <pre>{@code
	* Arrays.equals(a, b) == (Arrays.compare(a, b) == 0)
	* }</pre>
	*
	* @apiNote
	* <p>This method behaves as if (for non-{@code null} array references):
	* <pre>{@code
	* int i = Arrays.mismatch(a, b);
	* if (i >= 0 && i < Math.min(a.length, b.length))
	* return Boolean.compare(a[i], b[i]);
	* return a.length - b.length;
	* }</pre>
	*
	* @param a the first array to compare
	* @param b the second array to compare
	* @return the value {@code 0} if the first and second array are equal and
	* contain the same elements in the same order;
	* a value less than {@code 0} if the first array is
	* lexicographically less than the second array; and
	* a value greater than {@code 0} if the first array is
	* lexicographically greater than the second array
	* @since 9
	*/
	public static int compare(boolean[] a, boolean[] b) {
	if (a == b)
	return 0;
	if (a == null \|\| b == null)
	return a == null ? -1 : 1;

	int i = ArraysSupport.mismatch(a, b,
	Math.min(a.length, b.length));
	if (i >= 0) {
	return Boolean.compare(a[i], b[i]);
	}

	return a.length - b.length;
	}

	/**
	* Compares two {@code boolean} arrays lexicographically over the specified
	* ranges.
	*
	* <p>If the two arrays, over the specified ranges, share a common prefix
	* then the lexicographic comparison is the result of comparing two
	* elements, as if by {@link Boolean#compare(boolean, boolean)}, at a
	* relative index within the respective arrays that is the length of the
	* prefix.
	* Otherwise, one array is a proper prefix of the other and, lexicographic
	* comparison is the result of comparing the two range lengths.
	* (See {@link #mismatch(boolean[], int, int, boolean[], int, int)} for the
	* definition of a common and proper prefix.)
	*
	* <p>The comparison is consistent with
	* {@link #equals(boolean[], int, int, boolean[], int, int) equals}, more
	* specifically the following holds for arrays {@code a} and {@code b} with
	* specified ranges [{@code aFromIndex}, {@code atoIndex}) and
	* [{@code bFromIndex}, {@code btoIndex}) respectively:
	* <pre>{@code
	* Arrays.equals(a, aFromIndex, aToIndex, b, bFromIndex, bToIndex) ==
	* (Arrays.compare(a, aFromIndex, aToIndex, b, bFromIndex, bToIndex) == 0)
	* }</pre>
	*
	* @apiNote
	* <p>This method behaves as if:
	* <pre>{@code
	* int i = Arrays.mismatch(a, aFromIndex, aToIndex,
	* b, bFromIndex, bToIndex);
	* if (i >= 0 && i < Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex))
	* return Boolean.compare(a[aFromIndex + i], b[bFromIndex + i]);
	* return (aToIndex - aFromIndex) - (bToIndex - bFromIndex);
	* }</pre>
	*
	* @param a the first array to compare
	* @param aFromIndex the index (inclusive) of the first element in the
	* first array to be compared
	* @param aToIndex the index (exclusive) of the last element in the
	* first array to be compared
	* @param b the second array to compare
	* @param bFromIndex the index (inclusive) of the first element in the
	* second array to be compared
	* @param bToIndex the index (exclusive) of the last element in the
	* second array to be compared
	* @return the value {@code 0} if, over the specified ranges, the first and
	* second array are equal and contain the same elements in the same
	* order;
	* a value less than {@code 0} if, over the specified ranges, the
	* first array is lexicographically less than the second array; and
	* a value greater than {@code 0} if, over the specified ranges, the
	* first array is lexicographically greater than the second array
	* @throws IllegalArgumentException
	* if {@code aFromIndex > aToIndex} or
	* if {@code bFromIndex > bToIndex}
	* @throws ArrayIndexOutOfBoundsException
	* if {@code aFromIndex < 0 or aToIndex > a.length} or
	* if {@code bFromIndex < 0 or bToIndex > b.length}
	* @throws NullPointerException
	* if either array is {@code null}
	* @since 9
	*/
	public static int compare(boolean[] a, int aFromIndex, int aToIndex,
	boolean[] b, int bFromIndex, int bToIndex) {
	rangeCheck(a.length, aFromIndex, aToIndex);
	rangeCheck(b.length, bFromIndex, bToIndex);

	int aLength = aToIndex - aFromIndex;
	int bLength = bToIndex - bFromIndex;
	int i = ArraysSupport.mismatch(a, aFromIndex,
	b, bFromIndex,
	Math.min(aLength, bLength));
	if (i >= 0) {
	return Boolean.compare(a[aFromIndex + i], b[bFromIndex + i]);
	}

	return aLength - bLength;
	}

	// Compare byte

	/**
	* Compares two {@code byte} arrays lexicographically.
	*
	* <p>If the two arrays share a common prefix then the lexicographic
	* comparison is the result of comparing two elements, as if by
	* {@link Byte#compare(byte, byte)}, at an index within the respective
	* arrays that is the prefix length.
	* Otherwise, one array is a proper prefix of the other and, lexicographic
	* comparison is the result of comparing the two array lengths.
	* (See {@link #mismatch(byte[], byte[])} for the definition of a common and
	* proper prefix.)
	*
	* <p>A {@code null} array reference is considered lexicographically less
	* than a non-{@code null} array reference. Two {@code null} array
	* references are considered equal.
	*
	* <p>The comparison is consistent with {@link #equals(byte[], byte[]) equals},
	* more specifically the following holds for arrays {@code a} and {@code b}:
	* <pre>{@code
	* Arrays.equals(a, b) == (Arrays.compare(a, b) == 0)
	* }</pre>
	*
	* @apiNote
	* <p>This method behaves as if (for non-{@code null} array references):
	* <pre>{@code
	* int i = Arrays.mismatch(a, b);
	* if (i >= 0 && i < Math.min(a.length, b.length))
	* return Byte.compare(a[i], b[i]);
	* return a.length - b.length;
	* }</pre>
	*
	* @param a the first array to compare
	* @param b the second array to compare
	* @return the value {@code 0} if the first and second array are equal and
	* contain the same elements in the same order;
	* a value less than {@code 0} if the first array is
	* lexicographically less than the second array; and
	* a value greater than {@code 0} if the first array is
	* lexicographically greater than the second array
	* @since 9
	*/
	public static int compare(byte[] a, byte[] b) {
	if (a == b)
	return 0;
	if (a == null \|\| b == null)
	return a == null ? -1 : 1;

	int i = ArraysSupport.mismatch(a, b,
	Math.min(a.length, b.length));
	if (i >= 0) {
	return Byte.compare(a[i], b[i]);
	}

	return a.length - b.length;
	}

	/**
	* Compares two {@code byte} arrays lexicographically over the specified
	* ranges.
	*
	* <p>If the two arrays, over the specified ranges, share a common prefix
	* then the lexicographic comparison is the result of comparing two
	* elements, as if by {@link Byte#compare(byte, byte)}, at a relative index
	* within the respective arrays that is the length of the prefix.
	* Otherwise, one array is a proper prefix of the other and, lexicographic
	* comparison is the result of comparing the two range lengths.
	* (See {@link #mismatch(byte[], int, int, byte[], int, int)} for the
	* definition of a common and proper prefix.)
	*
	* <p>The comparison is consistent with
	* {@link #equals(byte[], int, int, byte[], int, int) equals}, more
	* specifically the following holds for arrays {@code a} and {@code b} with
	* specified ranges [{@code aFromIndex}, {@code atoIndex}) and
	* [{@code bFromIndex}, {@code btoIndex}) respectively:
	* <pre>{@code
	* Arrays.equals(a, aFromIndex, aToIndex, b, bFromIndex, bToIndex) ==
	* (Arrays.compare(a, aFromIndex, aToIndex, b, bFromIndex, bToIndex) == 0)
	* }</pre>
	*
	* @apiNote
	* <p>This method behaves as if:
	* <pre>{@code
	* int i = Arrays.mismatch(a, aFromIndex, aToIndex,
	* b, bFromIndex, bToIndex);
	* if (i >= 0 && i < Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex))
	* return Byte.compare(a[aFromIndex + i], b[bFromIndex + i]);
	* return (aToIndex - aFromIndex) - (bToIndex - bFromIndex);
	* }</pre>
	*
	* @param a the first array to compare
	* @param aFromIndex the index (inclusive) of the first element in the
	* first array to be compared
	* @param aToIndex the index (exclusive) of the last element in the
	* first array to be compared
	* @param b the second array to compare
	* @param bFromIndex the index (inclusive) of the first element in the
	* second array to be compared
	* @param bToIndex the index (exclusive) of the last element in the
	* second array to be compared
	* @return the value {@code 0} if, over the specified ranges, the first and
	* second array are equal and contain the same elements in the same
	* order;
	* a value less than {@code 0} if, over the specified ranges, the
	* first array is lexicographically less than the second array; and
	* a value greater than {@code 0} if, over the specified ranges, the
	* first array is lexicographically greater than the second array
	* @throws IllegalArgumentException
	* if {@code aFromIndex > aToIndex} or
	* if {@code bFromIndex > bToIndex}
	* @throws ArrayIndexOutOfBoundsException
	* if {@code aFromIndex < 0 or aToIndex > a.length} or
	* if {@code bFromIndex < 0 or bToIndex > b.length}
	* @throws NullPointerException
	* if either array is {@code null}
	* @since 9
	*/
	public static int compare(byte[] a, int aFromIndex, int aToIndex,
	byte[] b, int bFromIndex, int bToIndex) {
	rangeCheck(a.length, aFromIndex, aToIndex);
	rangeCheck(b.length, bFromIndex, bToIndex);

	int aLength = aToIndex - aFromIndex;
	int bLength = bToIndex - bFromIndex;
	int i = ArraysSupport.mismatch(a, aFromIndex,
	b, bFromIndex,
	Math.min(aLength, bLength));
	if (i >= 0) {
	return Byte.compare(a[aFromIndex + i], b[bFromIndex + i]);
	}

	return aLength - bLength;
	}

	/**
	* Compares two {@code byte} arrays lexicographically, numerically treating
	* elements as unsigned.
	*
	* <p>If the two arrays share a common prefix then the lexicographic
	* comparison is the result of comparing two elements, as if by
	* {@link Byte#compareUnsigned(byte, byte)}, at an index within the
	* respective arrays that is the prefix length.
	* Otherwise, one array is a proper prefix of the other and, lexicographic
	* comparison is the result of comparing the two array lengths.
	* (See {@link #mismatch(byte[], byte[])} for the definition of a common
	* and proper prefix.)
	*
	* <p>A {@code null} array reference is considered lexicographically less
	* than a non-{@code null} array reference. Two {@code null} array
	* references are considered equal.
	*
	* @apiNote
	* <p>This method behaves as if (for non-{@code null} array references):
	* <pre>{@code
	* int i = Arrays.mismatch(a, b);
	* if (i >= 0 && i < Math.min(a.length, b.length))
	* return Byte.compareUnsigned(a[i], b[i]);
	* return a.length - b.length;
	* }</pre>
	*
	* @param a the first array to compare
	* @param b the second array to compare
	* @return the value {@code 0} if the first and second array are
	* equal and contain the same elements in the same order;
	* a value less than {@code 0} if the first array is
	* lexicographically less than the second array; and
	* a value greater than {@code 0} if the first array is
	* lexicographically greater than the second array
	* @since 9
	*/
	public static int compareUnsigned(byte[] a, byte[] b) {
	if (a == b)
	return 0;
	if (a == null \|\| b == null)
	return a == null ? -1 : 1;

	int i = ArraysSupport.mismatch(a, b,
	Math.min(a.length, b.length));
	if (i >= 0) {
	return Byte.compareUnsigned(a[i], b[i]);
	}

	return a.length - b.length;
	}


	/**
	* Compares two {@code byte} arrays lexicographically over the specified
	* ranges, numerically treating elements as unsigned.
	*
	* <p>If the two arrays, over the specified ranges, share a common prefix
	* then the lexicographic comparison is the result of comparing two
	* elements, as if by {@link Byte#compareUnsigned(byte, byte)}, at a
	* relative index within the respective arrays that is the length of the
	* prefix.
	* Otherwise, one array is a proper prefix of the other and, lexicographic
	* comparison is the result of comparing the two range lengths.
	* (See {@link #mismatch(byte[], int, int, byte[], int, int)} for the
	* definition of a common and proper prefix.)
	*
	* @apiNote
	* <p>This method behaves as if:
	* <pre>{@code
	* int i = Arrays.mismatch(a, aFromIndex, aToIndex,
	* b, bFromIndex, bToIndex);
	* if (i >= 0 && i < Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex))
	* return Byte.compareUnsigned(a[aFromIndex + i], b[bFromIndex + i]);
	* return (aToIndex - aFromIndex) - (bToIndex - bFromIndex);
	* }</pre>
	*
	* @param a the first array to compare
	* @param aFromIndex the index (inclusive) of the first element in the
	* first array to be compared
	* @param aToIndex the index (exclusive) of the last element in the
	* first array to be compared
	* @param b the second array to compare
	* @param bFromIndex the index (inclusive) of the first element in the
	* second array to be compared
	* @param bToIndex the index (exclusive) of the last element in the
	* second array to be compared
	* @return the value {@code 0} if, over the specified ranges, the first and
	* second array are equal and contain the same elements in the same
	* order;
	* a value less than {@code 0} if, over the specified ranges, the
	* first array is lexicographically less than the second array; and
	* a value greater than {@code 0} if, over the specified ranges, the
	* first array is lexicographically greater than the second array
	* @throws IllegalArgumentException
	* if {@code aFromIndex > aToIndex} or
	* if {@code bFromIndex > bToIndex}
	* @throws ArrayIndexOutOfBoundsException
	* if {@code aFromIndex < 0 or aToIndex > a.length} or
	* if {@code bFromIndex < 0 or bToIndex > b.length}
	* @throws NullPointerException
	* if either array is null
	* @since 9
	*/
	public static int compareUnsigned(byte[] a, int aFromIndex, int aToIndex,
	byte[] b, int bFromIndex, int bToIndex) {
	rangeCheck(a.length, aFromIndex, aToIndex);
	rangeCheck(b.length, bFromIndex, bToIndex);

	int aLength = aToIndex - aFromIndex;
	int bLength = bToIndex - bFromIndex;
	int i = ArraysSupport.mismatch(a, aFromIndex,
	b, bFromIndex,
	Math.min(aLength, bLength));
	if (i >= 0) {
	return Byte.compareUnsigned(a[aFromIndex + i], b[bFromIndex + i]);
	}

	return aLength - bLength;
	}

	// Compare short

	/**
	* Compares two {@code short} arrays lexicographically.
	*
	* <p>If the two arrays share a common prefix then the lexicographic
	* comparison is the result of comparing two elements, as if by
	* {@link Short#compare(short, short)}, at an index within the respective
	* arrays that is the prefix length.
	* Otherwise, one array is a proper prefix of the other and, lexicographic
	* comparison is the result of comparing the two array lengths.
	* (See {@link #mismatch(short[], short[])} for the definition of a common
	* and proper prefix.)
	*
	* <p>A {@code null} array reference is considered lexicographically less
	* than a non-{@code null} array reference. Two {@code null} array
	* references are considered equal.
	*
	* <p>The comparison is consistent with {@link #equals(short[], short[]) equals},
	* more specifically the following holds for arrays {@code a} and {@code b}:
	* <pre>{@code
	* Arrays.equals(a, b) == (Arrays.compare(a, b) == 0)
	* }</pre>
	*
	* @apiNote
	* <p>This method behaves as if (for non-{@code null} array references):
	* <pre>{@code
	* int i = Arrays.mismatch(a, b);
	* if (i >= 0 && i < Math.min(a.length, b.length))
	* return Short.compare(a[i], b[i]);
	* return a.length - b.length;
	* }</pre>
	*
	* @param a the first array to compare
	* @param b the second array to compare
	* @return the value {@code 0} if the first and second array are equal and
	* contain the same elements in the same order;
	* a value less than {@code 0} if the first array is
	* lexicographically less than the second array; and
	* a value greater than {@code 0} if the first array is
	* lexicographically greater than the second array
	* @since 9
	*/
	public static int compare(short[] a, short[] b) {
	if (a == b)
	return 0;
	if (a == null \|\| b == null)
	return a == null ? -1 : 1;

	int i = ArraysSupport.mismatch(a, b,
	Math.min(a.length, b.length));
	if (i >= 0) {
	return Short.compare(a[i], b[i]);
	}

	return a.length - b.length;
	}

	/**
	* Compares two {@code short} arrays lexicographically over the specified
	* ranges.
	*
	* <p>If the two arrays, over the specified ranges, share a common prefix
	* then the lexicographic comparison is the result of comparing two
	* elements, as if by {@link Short#compare(short, short)}, at a relative
	* index within the respective arrays that is the length of the prefix.
	* Otherwise, one array is a proper prefix of the other and, lexicographic
	* comparison is the result of comparing the two range lengths.
	* (See {@link #mismatch(short[], int, int, short[], int, int)} for the
	* definition of a common and proper prefix.)
	*
	* <p>The comparison is consistent with
	* {@link #equals(short[], int, int, short[], int, int) equals}, more
	* specifically the following holds for arrays {@code a} and {@code b} with
	* specified ranges [{@code aFromIndex}, {@code atoIndex}) and
	* [{@code bFromIndex}, {@code btoIndex}) respectively:
	* <pre>{@code
	* Arrays.equals(a, aFromIndex, aToIndex, b, bFromIndex, bToIndex) ==
	* (Arrays.compare(a, aFromIndex, aToIndex, b, bFromIndex, bToIndex) == 0)
	* }</pre>
	*
	* @apiNote
	* <p>This method behaves as if:
	* <pre>{@code
	* int i = Arrays.mismatch(a, aFromIndex, aToIndex,
	* b, bFromIndex, bToIndex);
	* if (i >= 0 && i < Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex))
	* return Short.compare(a[aFromIndex + i], b[bFromIndex + i]);
	* return (aToIndex - aFromIndex) - (bToIndex - bFromIndex);
	* }</pre>
	*
	* @param a the first array to compare
	* @param aFromIndex the index (inclusive) of the first element in the
	* first array to be compared
	* @param aToIndex the index (exclusive) of the last element in the
	* first array to be compared
	* @param b the second array to compare
	* @param bFromIndex the index (inclusive) of the first element in the
	* second array to be compared
	* @param bToIndex the index (exclusive) of the last element in the
	* second array to be compared
	* @return the value {@code 0} if, over the specified ranges, the first and
	* second array are equal and contain the same elements in the same
	* order;
	* a value less than {@code 0} if, over the specified ranges, the
	* first array is lexicographically less than the second array; and
	* a value greater than {@code 0} if, over the specified ranges, the
	* first array is lexicographically greater than the second array
	* @throws IllegalArgumentException
	* if {@code aFromIndex > aToIndex} or
	* if {@code bFromIndex > bToIndex}
	* @throws ArrayIndexOutOfBoundsException
	* if {@code aFromIndex < 0 or aToIndex > a.length} or
	* if {@code bFromIndex < 0 or bToIndex > b.length}
	* @throws NullPointerException
	* if either array is {@code null}
	* @since 9
	*/
	public static int compare(short[] a, int aFromIndex, int aToIndex,
	short[] b, int bFromIndex, int bToIndex) {
	rangeCheck(a.length, aFromIndex, aToIndex);
	rangeCheck(b.length, bFromIndex, bToIndex);

	int aLength = aToIndex - aFromIndex;
	int bLength = bToIndex - bFromIndex;
	int i = ArraysSupport.mismatch(a, aFromIndex,
	b, bFromIndex,
	Math.min(aLength, bLength));
	if (i >= 0) {
	return Short.compare(a[aFromIndex + i], b[bFromIndex + i]);
	}

	return aLength - bLength;
	}

	/**
	* Compares two {@code short} arrays lexicographically, numerically treating
	* elements as unsigned.
	*
	* <p>If the two arrays share a common prefix then the lexicographic
	* comparison is the result of comparing two elements, as if by
	* {@link Short#compareUnsigned(short, short)}, at an index within the
	* respective arrays that is the prefix length.
	* Otherwise, one array is a proper prefix of the other and, lexicographic
	* comparison is the result of comparing the two array lengths.
	* (See {@link #mismatch(short[], short[])} for the definition of a common
	* and proper prefix.)
	*
	* <p>A {@code null} array reference is considered lexicographically less
	* than a non-{@code null} array reference. Two {@code null} array
	* references are considered equal.
	*
	* @apiNote
	* <p>This method behaves as if (for non-{@code null} array references):
	* <pre>{@code
	* int i = Arrays.mismatch(a, b);
	* if (i >= 0 && i < Math.min(a.length, b.length))
	* return Short.compareUnsigned(a[i], b[i]);
	* return a.length - b.length;
	* }</pre>
	*
	* @param a the first array to compare
	* @param b the second array to compare
	* @return the value {@code 0} if the first and second array are
	* equal and contain the same elements in the same order;
	* a value less than {@code 0} if the first array is
	* lexicographically less than the second array; and
	* a value greater than {@code 0} if the first array is
	* lexicographically greater than the second array
	* @since 9
	*/
	public static int compareUnsigned(short[] a, short[] b) {
	if (a == b)
	return 0;
	if (a == null \|\| b == null)
	return a == null ? -1 : 1;

	int i = ArraysSupport.mismatch(a, b,
	Math.min(a.length, b.length));
	if (i >= 0) {
	return Short.compareUnsigned(a[i], b[i]);
	}

	return a.length - b.length;
	}

	/**
	* Compares two {@code short} arrays lexicographically over the specified
	* ranges, numerically treating elements as unsigned.
	*
	* <p>If the two arrays, over the specified ranges, share a common prefix
	* then the lexicographic comparison is the result of comparing two
	* elements, as if by {@link Short#compareUnsigned(short, short)}, at a
	* relative index within the respective arrays that is the length of the
	* prefix.
	* Otherwise, one array is a proper prefix of the other and, lexicographic
	* comparison is the result of comparing the two range lengths.
	* (See {@link #mismatch(short[], int, int, short[], int, int)} for the
	* definition of a common and proper prefix.)
	*
	* @apiNote
	* <p>This method behaves as if:
	* <pre>{@code
	* int i = Arrays.mismatch(a, aFromIndex, aToIndex,
	* b, bFromIndex, bToIndex);
	* if (i >= 0 && i < Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex))
	* return Short.compareUnsigned(a[aFromIndex + i], b[bFromIndex + i]);
	* return (aToIndex - aFromIndex) - (bToIndex - bFromIndex);
	* }</pre>
	*
	* @param a the first array to compare
	* @param aFromIndex the index (inclusive) of the first element in the
	* first array to be compared
	* @param aToIndex the index (exclusive) of the last element in the
	* first array to be compared
	* @param b the second array to compare
	* @param bFromIndex the index (inclusive) of the first element in the
	* second array to be compared
	* @param bToIndex the index (exclusive) of the last element in the
	* second array to be compared
	* @return the value {@code 0} if, over the specified ranges, the first and
	* second array are equal and contain the same elements in the same
	* order;
	* a value less than {@code 0} if, over the specified ranges, the
	* first array is lexicographically less than the second array; and
	* a value greater than {@code 0} if, over the specified ranges, the
	* first array is lexicographically greater than the second array
	* @throws IllegalArgumentException
	* if {@code aFromIndex > aToIndex} or
	* if {@code bFromIndex > bToIndex}
	* @throws ArrayIndexOutOfBoundsException
	* if {@code aFromIndex < 0 or aToIndex > a.length} or
	* if {@code bFromIndex < 0 or bToIndex > b.length}
	* @throws NullPointerException
	* if either array is null
	* @since 9
	*/
	public static int compareUnsigned(short[] a, int aFromIndex, int aToIndex,
	short[] b, int bFromIndex, int bToIndex) {
	rangeCheck(a.length, aFromIndex, aToIndex);
	rangeCheck(b.length, bFromIndex, bToIndex);

	int aLength = aToIndex - aFromIndex;
	int bLength = bToIndex - bFromIndex;
	int i = ArraysSupport.mismatch(a, aFromIndex,
	b, bFromIndex,
	Math.min(aLength, bLength));
	if (i >= 0) {
	return Short.compareUnsigned(a[aFromIndex + i], b[bFromIndex + i]);
	}

	return aLength - bLength;
	}

	// Compare char

	/**
	* Compares two {@code char} arrays lexicographically.
	*
	* <p>If the two arrays share a common prefix then the lexicographic
	* comparison is the result of comparing two elements, as if by
	* {@link Character#compare(char, char)}, at an index within the respective
	* arrays that is the prefix length.
	* Otherwise, one array is a proper prefix of the other and, lexicographic
	* comparison is the result of comparing the two array lengths.
	* (See {@link #mismatch(char[], char[])} for the definition of a common and
	* proper prefix.)
	*
	* <p>A {@code null} array reference is considered lexicographically less
	* than a non-{@code null} array reference. Two {@code null} array
	* references are considered equal.
	*
	* <p>The comparison is consistent with {@link #equals(char[], char[]) equals},
	* more specifically the following holds for arrays {@code a} and {@code b}:
	* <pre>{@code
	* Arrays.equals(a, b) == (Arrays.compare(a, b) == 0)
	* }</pre>
	*
	* @apiNote
	* <p>This method behaves as if (for non-{@code null} array references):
	* <pre>{@code
	* int i = Arrays.mismatch(a, b);
	* if (i >= 0 && i < Math.min(a.length, b.length))
	* return Character.compare(a[i], b[i]);
	* return a.length - b.length;
	* }</pre>
	*
	* @param a the first array to compare
	* @param b the second array to compare
	* @return the value {@code 0} if the first and second array are equal and
	* contain the same elements in the same order;
	* a value less than {@code 0} if the first array is
	* lexicographically less than the second array; and
	* a value greater than {@code 0} if the first array is
	* lexicographically greater than the second array
	* @since 9
	*/
	public static int compare(char[] a, char[] b) {
	if (a == b)
	return 0;
	if (a == null \|\| b == null)
	return a == null ? -1 : 1;

	int i = ArraysSupport.mismatch(a, b,
	Math.min(a.length, b.length));
	if (i >= 0) {
	return Character.compare(a[i], b[i]);
	}

	return a.length - b.length;
	}

	/**
	* Compares two {@code char} arrays lexicographically over the specified
	* ranges.
	*
	* <p>If the two arrays, over the specified ranges, share a common prefix
	* then the lexicographic comparison is the result of comparing two
	* elements, as if by {@link Character#compare(char, char)}, at a relative
	* index within the respective arrays that is the length of the prefix.
	* Otherwise, one array is a proper prefix of the other and, lexicographic
	* comparison is the result of comparing the two range lengths.
	* (See {@link #mismatch(char[], int, int, char[], int, int)} for the
	* definition of a common and proper prefix.)
	*
	* <p>The comparison is consistent with
	* {@link #equals(char[], int, int, char[], int, int) equals}, more
	* specifically the following holds for arrays {@code a} and {@code b} with
	* specified ranges [{@code aFromIndex}, {@code atoIndex}) and
	* [{@code bFromIndex}, {@code btoIndex}) respectively:
	* <pre>{@code
	* Arrays.equals(a, aFromIndex, aToIndex, b, bFromIndex, bToIndex) ==
	* (Arrays.compare(a, aFromIndex, aToIndex, b, bFromIndex, bToIndex) == 0)
	* }</pre>
	*
	* @apiNote
	* <p>This method behaves as if:
	* <pre>{@code
	* int i = Arrays.mismatch(a, aFromIndex, aToIndex,
	* b, bFromIndex, bToIndex);
	* if (i >= 0 && i < Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex))
	* return Character.compare(a[aFromIndex + i], b[bFromIndex + i]);
	* return (aToIndex - aFromIndex) - (bToIndex - bFromIndex);
	* }</pre>
	*
	* @param a the first array to compare
	* @param aFromIndex the index (inclusive) of the first element in the
	* first array to be compared
	* @param aToIndex the index (exclusive) of the last element in the
	* first array to be compared
	* @param b the second array to compare
	* @param bFromIndex the index (inclusive) of the first element in the
	* second array to be compared
	* @param bToIndex the index (exclusive) of the last element in the
	* second array to be compared
	* @return the value {@code 0} if, over the specified ranges, the first and
	* second array are equal and contain the same elements in the same
	* order;
	* a value less than {@code 0} if, over the specified ranges, the
	* first array is lexicographically less than the second array; and
	* a value greater than {@code 0} if, over the specified ranges, the
	* first array is lexicographically greater than the second array
	* @throws IllegalArgumentException
	* if {@code aFromIndex > aToIndex} or
	* if {@code bFromIndex > bToIndex}
	* @throws ArrayIndexOutOfBoundsException
	* if {@code aFromIndex < 0 or aToIndex > a.length} or
	* if {@code bFromIndex < 0 or bToIndex > b.length}
	* @throws NullPointerException
	* if either array is {@code null}
	* @since 9
	*/
	public static int compare(char[] a, int aFromIndex, int aToIndex,
	char[] b, int bFromIndex, int bToIndex) {
	rangeCheck(a.length, aFromIndex, aToIndex);
	rangeCheck(b.length, bFromIndex, bToIndex);

	int aLength = aToIndex - aFromIndex;
	int bLength = bToIndex - bFromIndex;
	int i = ArraysSupport.mismatch(a, aFromIndex,
	b, bFromIndex,
	Math.min(aLength, bLength));
	if (i >= 0) {
	return Character.compare(a[aFromIndex + i], b[bFromIndex + i]);
	}

	return aLength - bLength;
	}

	// Compare int

	/**
	* Compares two {@code int} arrays lexicographically.
	*
	* <p>If the two arrays share a common prefix then the lexicographic
	* comparison is the result of comparing two elements, as if by
	* {@link Integer#compare(int, int)}, at an index within the respective
	* arrays that is the prefix length.
	* Otherwise, one array is a proper prefix of the other and, lexicographic
	* comparison is the result of comparing the two array lengths.
	* (See {@link #mismatch(int[], int[])} for the definition of a common and
	* proper prefix.)
	*
	* <p>A {@code null} array reference is considered lexicographically less
	* than a non-{@code null} array reference. Two {@code null} array
	* references are considered equal.
	*
	* <p>The comparison is consistent with {@link #equals(int[], int[]) equals},
	* more specifically the following holds for arrays {@code a} and {@code b}:
	* <pre>{@code
	* Arrays.equals(a, b) == (Arrays.compare(a, b) == 0)
	* }</pre>
	*
	* @apiNote
	* <p>This method behaves as if (for non-{@code null} array references):
	* <pre>{@code
	* int i = Arrays.mismatch(a, b);
	* if (i >= 0 && i < Math.min(a.length, b.length))
	* return Integer.compare(a[i], b[i]);
	* return a.length - b.length;
	* }</pre>
	*
	* @param a the first array to compare
	* @param b the second array to compare
	* @return the value {@code 0} if the first and second array are equal and
	* contain the same elements in the same order;
	* a value less than {@code 0} if the first array is
	* lexicographically less than the second array; and
	* a value greater than {@code 0} if the first array is
	* lexicographically greater than the second array
	* @since 9
	*/
	public static int compare(int[] a, int[] b) {
	if (a == b)
	return 0;
	if (a == null \|\| b == null)
	return a == null ? -1 : 1;

	int i = ArraysSupport.mismatch(a, b,
	Math.min(a.length, b.length));
	if (i >= 0) {
	return Integer.compare(a[i], b[i]);
	}

	return a.length - b.length;
	}

	/**
	* Compares two {@code int} arrays lexicographically over the specified
	* ranges.
	*
	* <p>If the two arrays, over the specified ranges, share a common prefix
	* then the lexicographic comparison is the result of comparing two
	* elements, as if by {@link Integer#compare(int, int)}, at a relative index
	* within the respective arrays that is the length of the prefix.
	* Otherwise, one array is a proper prefix of the other and, lexicographic
	* comparison is the result of comparing the two range lengths.
	* (See {@link #mismatch(int[], int, int, int[], int, int)} for the
	* definition of a common and proper prefix.)
	*
	* <p>The comparison is consistent with
	* {@link #equals(int[], int, int, int[], int, int) equals}, more
	* specifically the following holds for arrays {@code a} and {@code b} with
	* specified ranges [{@code aFromIndex}, {@code atoIndex}) and
	* [{@code bFromIndex}, {@code btoIndex}) respectively:
	* <pre>{@code
	* Arrays.equals(a, aFromIndex, aToIndex, b, bFromIndex, bToIndex) ==
	* (Arrays.compare(a, aFromIndex, aToIndex, b, bFromIndex, bToIndex) == 0)
	* }</pre>
	*
	* @apiNote
	* <p>This method behaves as if:
	* <pre>{@code
	* int i = Arrays.mismatch(a, aFromIndex, aToIndex,
	* b, bFromIndex, bToIndex);
	* if (i >= 0 && i < Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex))
	* return Integer.compare(a[aFromIndex + i], b[bFromIndex + i]);
	* return (aToIndex - aFromIndex) - (bToIndex - bFromIndex);
	* }</pre>
	*
	* @param a the first array to compare
	* @param aFromIndex the index (inclusive) of the first element in the
	* first array to be compared
	* @param aToIndex the index (exclusive) of the last element in the
	* first array to be compared
	* @param b the second array to compare
	* @param bFromIndex the index (inclusive) of the first element in the
	* second array to be compared
	* @param bToIndex the index (exclusive) of the last element in the
	* second array to be compared
	* @return the value {@code 0} if, over the specified ranges, the first and
	* second array are equal and contain the same elements in the same
	* order;
	* a value less than {@code 0} if, over the specified ranges, the
	* first array is lexicographically less than the second array; and
	* a value greater than {@code 0} if, over the specified ranges, the
	* first array is lexicographically greater than the second array
	* @throws IllegalArgumentException
	* if {@code aFromIndex > aToIndex} or
	* if {@code bFromIndex > bToIndex}
	* @throws ArrayIndexOutOfBoundsException
	* if {@code aFromIndex < 0 or aToIndex > a.length} or
	* if {@code bFromIndex < 0 or bToIndex > b.length}
	* @throws NullPointerException
	* if either array is {@code null}
	* @since 9
	*/
	public static int compare(int[] a, int aFromIndex, int aToIndex,
	int[] b, int bFromIndex, int bToIndex) {
	rangeCheck(a.length, aFromIndex, aToIndex);
	rangeCheck(b.length, bFromIndex, bToIndex);

	int aLength = aToIndex - aFromIndex;
	int bLength = bToIndex - bFromIndex;
	int i = ArraysSupport.mismatch(a, aFromIndex,
	b, bFromIndex,
	Math.min(aLength, bLength));
	if (i >= 0) {
	return Integer.compare(a[aFromIndex + i], b[bFromIndex + i]);
	}

	return aLength - bLength;
	}

	/**
	* Compares two {@code int} arrays lexicographically, numerically treating
	* elements as unsigned.
	*
	* <p>If the two arrays share a common prefix then the lexicographic
	* comparison is the result of comparing two elements, as if by
	* {@link Integer#compareUnsigned(int, int)}, at an index within the
	* respective arrays that is the prefix length.
	* Otherwise, one array is a proper prefix of the other and, lexicographic
	* comparison is the result of comparing the two array lengths.
	* (See {@link #mismatch(int[], int[])} for the definition of a common
	* and proper prefix.)
	*
	* <p>A {@code null} array reference is considered lexicographically less
	* than a non-{@code null} array reference. Two {@code null} array
	* references are considered equal.
	*
	* @apiNote
	* <p>This method behaves as if (for non-{@code null} array references):
	* <pre>{@code
	* int i = Arrays.mismatch(a, b);
	* if (i >= 0 && i < Math.min(a.length, b.length))
	* return Integer.compareUnsigned(a[i], b[i]);
	* return a.length - b.length;
	* }</pre>
	*
	* @param a the first array to compare
	* @param b the second array to compare
	* @return the value {@code 0} if the first and second array are
	* equal and contain the same elements in the same order;
	* a value less than {@code 0} if the first array is
	* lexicographically less than the second array; and
	* a value greater than {@code 0} if the first array is
	* lexicographically greater than the second array
	* @since 9
	*/
	public static int compareUnsigned(int[] a, int[] b) {
	if (a == b)
	return 0;
	if (a == null \|\| b == null)
	return a == null ? -1 : 1;

	int i = ArraysSupport.mismatch(a, b,
	Math.min(a.length, b.length));
	if (i >= 0) {
	return Integer.compareUnsigned(a[i], b[i]);
	}

	return a.length - b.length;
	}

	/**
	* Compares two {@code int} arrays lexicographically over the specified
	* ranges, numerically treating elements as unsigned.
	*
	* <p>If the two arrays, over the specified ranges, share a common prefix
	* then the lexicographic comparison is the result of comparing two
	* elements, as if by {@link Integer#compareUnsigned(int, int)}, at a
	* relative index within the respective arrays that is the length of the
	* prefix.
	* Otherwise, one array is a proper prefix of the other and, lexicographic
	* comparison is the result of comparing the two range lengths.
	* (See {@link #mismatch(int[], int, int, int[], int, int)} for the
	* definition of a common and proper prefix.)
	*
	* @apiNote
	* <p>This method behaves as if:
	* <pre>{@code
	* int i = Arrays.mismatch(a, aFromIndex, aToIndex,
	* b, bFromIndex, bToIndex);
	* if (i >= 0 && i < Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex))
	* return Integer.compareUnsigned(a[aFromIndex + i], b[bFromIndex + i]);
	* return (aToIndex - aFromIndex) - (bToIndex - bFromIndex);
	* }</pre>
	*
	* @param a the first array to compare
	* @param aFromIndex the index (inclusive) of the first element in the
	* first array to be compared
	* @param aToIndex the index (exclusive) of the last element in the
	* first array to be compared
	* @param b the second array to compare
	* @param bFromIndex the index (inclusive) of the first element in the
	* second array to be compared
	* @param bToIndex the index (exclusive) of the last element in the
	* second array to be compared
	* @return the value {@code 0} if, over the specified ranges, the first and
	* second array are equal and contain the same elements in the same
	* order;
	* a value less than {@code 0} if, over the specified ranges, the
	* first array is lexicographically less than the second array; and
	* a value greater than {@code 0} if, over the specified ranges, the
	* first array is lexicographically greater than the second array
	* @throws IllegalArgumentException
	* if {@code aFromIndex > aToIndex} or
	* if {@code bFromIndex > bToIndex}
	* @throws ArrayIndexOutOfBoundsException
	* if {@code aFromIndex < 0 or aToIndex > a.length} or
	* if {@code bFromIndex < 0 or bToIndex > b.length}
	* @throws NullPointerException
	* if either array is null
	* @since 9
	*/
	public static int compareUnsigned(int[] a, int aFromIndex, int aToIndex,
	int[] b, int bFromIndex, int bToIndex) {
	rangeCheck(a.length, aFromIndex, aToIndex);
	rangeCheck(b.length, bFromIndex, bToIndex);

	int aLength = aToIndex - aFromIndex;
	int bLength = bToIndex - bFromIndex;
	int i = ArraysSupport.mismatch(a, aFromIndex,
	b, bFromIndex,
	Math.min(aLength, bLength));
	if (i >= 0) {
	return Integer.compareUnsigned(a[aFromIndex + i], b[bFromIndex + i]);
	}

	return aLength - bLength;
	}

	// Compare long

	/**
	* Compares two {@code long} arrays lexicographically.
	*
	* <p>If the two arrays share a common prefix then the lexicographic
	* comparison is the result of comparing two elements, as if by
	* {@link Long#compare(long, long)}, at an index within the respective
	* arrays that is the prefix length.
	* Otherwise, one array is a proper prefix of the other and, lexicographic
	* comparison is the result of comparing the two array lengths.
	* (See {@link #mismatch(long[], long[])} for the definition of a common and
	* proper prefix.)
	*
	* <p>A {@code null} array reference is considered lexicographically less
	* than a non-{@code null} array reference. Two {@code null} array
	* references are considered equal.
	*
	* <p>The comparison is consistent with {@link #equals(long[], long[]) equals},
	* more specifically the following holds for arrays {@code a} and {@code b}:
	* <pre>{@code
	* Arrays.equals(a, b) == (Arrays.compare(a, b) == 0)
	* }</pre>
	*
	* @apiNote
	* <p>This method behaves as if (for non-{@code null} array references):
	* <pre>{@code
	* int i = Arrays.mismatch(a, b);
	* if (i >= 0 && i < Math.min(a.length, b.length))
	* return Long.compare(a[i], b[i]);
	* return a.length - b.length;
	* }</pre>
	*
	* @param a the first array to compare
	* @param b the second array to compare
	* @return the value {@code 0} if the first and second array are equal and
	* contain the same elements in the same order;
	* a value less than {@code 0} if the first array is
	* lexicographically less than the second array; and
	* a value greater than {@code 0} if the first array is
	* lexicographically greater than the second array
	* @since 9
	*/
	public static int compare(long[] a, long[] b) {
	if (a == b)
	return 0;
	if (a == null \|\| b == null)
	return a == null ? -1 : 1;

	int i = ArraysSupport.mismatch(a, b,
	Math.min(a.length, b.length));
	if (i >= 0) {
	return Long.compare(a[i], b[i]);
	}

	return a.length - b.length;
	}

	/**
	* Compares two {@code long} arrays lexicographically over the specified
	* ranges.
	*
	* <p>If the two arrays, over the specified ranges, share a common prefix
	* then the lexicographic comparison is the result of comparing two
	* elements, as if by {@link Long#compare(long, long)}, at a relative index
	* within the respective arrays that is the length of the prefix.
	* Otherwise, one array is a proper prefix of the other and, lexicographic
	* comparison is the result of comparing the two range lengths.
	* (See {@link #mismatch(long[], int, int, long[], int, int)} for the
	* definition of a common and proper prefix.)
	*
	* <p>The comparison is consistent with
	* {@link #equals(long[], int, int, long[], int, int) equals}, more
	* specifically the following holds for arrays {@code a} and {@code b} with
	* specified ranges [{@code aFromIndex}, {@code atoIndex}) and
	* [{@code bFromIndex}, {@code btoIndex}) respectively:
	* <pre>{@code
	* Arrays.equals(a, aFromIndex, aToIndex, b, bFromIndex, bToIndex) ==
	* (Arrays.compare(a, aFromIndex, aToIndex, b, bFromIndex, bToIndex) == 0)
	* }</pre>
	*
	* @apiNote
	* <p>This method behaves as if:
	* <pre>{@code
	* int i = Arrays.mismatch(a, aFromIndex, aToIndex,
	* b, bFromIndex, bToIndex);
	* if (i >= 0 && i < Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex))
	* return Long.compare(a[aFromIndex + i], b[bFromIndex + i]);
	* return (aToIndex - aFromIndex) - (bToIndex - bFromIndex);
	* }</pre>
	*
	* @param a the first array to compare
	* @param aFromIndex the index (inclusive) of the first element in the
	* first array to be compared
	* @param aToIndex the index (exclusive) of the last element in the
	* first array to be compared
	* @param b the second array to compare
	* @param bFromIndex the index (inclusive) of the first element in the
	* second array to be compared
	* @param bToIndex the index (exclusive) of the last element in the
	* second array to be compared
	* @return the value {@code 0} if, over the specified ranges, the first and
	* second array are equal and contain the same elements in the same
	* order;
	* a value less than {@code 0} if, over the specified ranges, the
	* first array is lexicographically less than the second array; and
	* a value greater than {@code 0} if, over the specified ranges, the
	* first array is lexicographically greater than the second array
	* @throws IllegalArgumentException
	* if {@code aFromIndex > aToIndex} or
	* if {@code bFromIndex > bToIndex}
	* @throws ArrayIndexOutOfBoundsException
	* if {@code aFromIndex < 0 or aToIndex > a.length} or
	* if {@code bFromIndex < 0 or bToIndex > b.length}
	* @throws NullPointerException
	* if either array is {@code null}
	* @since 9
	*/
	public static int compare(long[] a, int aFromIndex, int aToIndex,
	long[] b, int bFromIndex, int bToIndex) {
	rangeCheck(a.length, aFromIndex, aToIndex);
	rangeCheck(b.length, bFromIndex, bToIndex);

	int aLength = aToIndex - aFromIndex;
	int bLength = bToIndex - bFromIndex;
	int i = ArraysSupport.mismatch(a, aFromIndex,
	b, bFromIndex,
	Math.min(aLength, bLength));
	if (i >= 0) {
	return Long.compare(a[aFromIndex + i], b[bFromIndex + i]);
	}

	return aLength - bLength;
	}

	/**
	* Compares two {@code long} arrays lexicographically, numerically treating
	* elements as unsigned.
	*
	* <p>If the two arrays share a common prefix then the lexicographic
	* comparison is the result of comparing two elements, as if by
	* {@link Long#compareUnsigned(long, long)}, at an index within the
	* respective arrays that is the prefix length.
	* Otherwise, one array is a proper prefix of the other and, lexicographic
	* comparison is the result of comparing the two array lengths.
	* (See {@link #mismatch(long[], long[])} for the definition of a common
	* and proper prefix.)
	*
	* <p>A {@code null} array reference is considered lexicographically less
	* than a non-{@code null} array reference. Two {@code null} array
	* references are considered equal.
	*
	* @apiNote
	* <p>This method behaves as if (for non-{@code null} array references):
	* <pre>{@code
	* int i = Arrays.mismatch(a, b);
	* if (i >= 0 && i < Math.min(a.length, b.length))
	* return Long.compareUnsigned(a[i], b[i]);
	* return a.length - b.length;
	* }</pre>
	*
	* @param a the first array to compare
	* @param b the second array to compare
	* @return the value {@code 0} if the first and second array are
	* equal and contain the same elements in the same order;
	* a value less than {@code 0} if the first array is
	* lexicographically less than the second array; and
	* a value greater than {@code 0} if the first array is
	* lexicographically greater than the second array
	* @since 9
	*/
	public static int compareUnsigned(long[] a, long[] b) {
	if (a == b)
	return 0;
	if (a == null \|\| b == null)
	return a == null ? -1 : 1;

	int i = ArraysSupport.mismatch(a, b,
	Math.min(a.length, b.length));
	if (i >= 0) {
	return Long.compareUnsigned(a[i], b[i]);
	}

	return a.length - b.length;
	}

	/**
	* Compares two {@code long} arrays lexicographically over the specified
	* ranges, numerically treating elements as unsigned.
	*
	* <p>If the two arrays, over the specified ranges, share a common prefix
	* then the lexicographic comparison is the result of comparing two
	* elements, as if by {@link Long#compareUnsigned(long, long)}, at a
	* relative index within the respective arrays that is the length of the
	* prefix.
	* Otherwise, one array is a proper prefix of the other and, lexicographic
	* comparison is the result of comparing the two range lengths.
	* (See {@link #mismatch(long[], int, int, long[], int, int)} for the
	* definition of a common and proper prefix.)
	*
	* @apiNote
	* <p>This method behaves as if:
	* <pre>{@code
	* int i = Arrays.mismatch(a, aFromIndex, aToIndex,
	* b, bFromIndex, bToIndex);
	* if (i >= 0 && i < Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex))
	* return Long.compareUnsigned(a[aFromIndex + i], b[bFromIndex + i]);
	* return (aToIndex - aFromIndex) - (bToIndex - bFromIndex);
	* }</pre>
	*
	* @param a the first array to compare
	* @param aFromIndex the index (inclusive) of the first element in the
	* first array to be compared
	* @param aToIndex the index (exclusive) of the last element in the
	* first array to be compared
	* @param b the second array to compare
	* @param bFromIndex the index (inclusive) of the first element in the
	* second array to be compared
	* @param bToIndex the index (exclusive) of the last element in the
	* second array to be compared
	* @return the value {@code 0} if, over the specified ranges, the first and
	* second array are equal and contain the same elements in the same
	* order;
	* a value less than {@code 0} if, over the specified ranges, the
	* first array is lexicographically less than the second array; and
	* a value greater than {@code 0} if, over the specified ranges, the
	* first array is lexicographically greater than the second array
	* @throws IllegalArgumentException
	* if {@code aFromIndex > aToIndex} or
	* if {@code bFromIndex > bToIndex}
	* @throws ArrayIndexOutOfBoundsException
	* if {@code aFromIndex < 0 or aToIndex > a.length} or
	* if {@code bFromIndex < 0 or bToIndex > b.length}
	* @throws NullPointerException
	* if either array is null
	* @since 9
	*/
	public static int compareUnsigned(long[] a, int aFromIndex, int aToIndex,
	long[] b, int bFromIndex, int bToIndex) {
	rangeCheck(a.length, aFromIndex, aToIndex);
	rangeCheck(b.length, bFromIndex, bToIndex);

	int aLength = aToIndex - aFromIndex;
	int bLength = bToIndex - bFromIndex;
	int i = ArraysSupport.mismatch(a, aFromIndex,
	b, bFromIndex,
	Math.min(aLength, bLength));
	if (i >= 0) {
	return Long.compareUnsigned(a[aFromIndex + i], b[bFromIndex + i]);
	}

	return aLength - bLength;
	}

	// Compare float

	/**
	* Compares two {@code float} arrays lexicographically.
	*
	* <p>If the two arrays share a common prefix then the lexicographic
	* comparison is the result of comparing two elements, as if by
	* {@link Float#compare(float, float)}, at an index within the respective
	* arrays that is the prefix length.
	* Otherwise, one array is a proper prefix of the other and, lexicographic
	* comparison is the result of comparing the two array lengths.
	* (See {@link #mismatch(float[], float[])} for the definition of a common
	* and proper prefix.)
	*
	* <p>A {@code null} array reference is considered lexicographically less
	* than a non-{@code null} array reference. Two {@code null} array
	* references are considered equal.
	*
	* <p>The comparison is consistent with {@link #equals(float[], float[]) equals},
	* more specifically the following holds for arrays {@code a} and {@code b}:
	* <pre>{@code
	* Arrays.equals(a, b) == (Arrays.compare(a, b) == 0)
	* }</pre>
	*
	* @apiNote
	* <p>This method behaves as if (for non-{@code null} array references):
	* <pre>{@code
	* int i = Arrays.mismatch(a, b);
	* if (i >= 0 && i < Math.min(a.length, b.length))
	* return Float.compare(a[i], b[i]);
	* return a.length - b.length;
	* }</pre>
	*
	* @param a the first array to compare
	* @param b the second array to compare
	* @return the value {@code 0} if the first and second array are equal and
	* contain the same elements in the same order;
	* a value less than {@code 0} if the first array is
	* lexicographically less than the second array; and
	* a value greater than {@code 0} if the first array is
	* lexicographically greater than the second array
	* @since 9
	*/
	public static int compare(float[] a, float[] b) {
	if (a == b)
	return 0;
	if (a == null \|\| b == null)
	return a == null ? -1 : 1;

	int i = ArraysSupport.mismatch(a, b,
	Math.min(a.length, b.length));
	if (i >= 0) {
	return Float.compare(a[i], b[i]);
	}

	return a.length - b.length;
	}

	/**
	* Compares two {@code float} arrays lexicographically over the specified
	* ranges.
	*
	* <p>If the two arrays, over the specified ranges, share a common prefix
	* then the lexicographic comparison is the result of comparing two
	* elements, as if by {@link Float#compare(float, float)}, at a relative
	* index within the respective arrays that is the length of the prefix.
	* Otherwise, one array is a proper prefix of the other and, lexicographic
	* comparison is the result of comparing the two range lengths.
	* (See {@link #mismatch(float[], int, int, float[], int, int)} for the
	* definition of a common and proper prefix.)
	*
	* <p>The comparison is consistent with
	* {@link #equals(float[], int, int, float[], int, int) equals}, more
	* specifically the following holds for arrays {@code a} and {@code b} with
	* specified ranges [{@code aFromIndex}, {@code atoIndex}) and
	* [{@code bFromIndex}, {@code btoIndex}) respectively:
	* <pre>{@code
	* Arrays.equals(a, aFromIndex, aToIndex, b, bFromIndex, bToIndex) ==
	* (Arrays.compare(a, aFromIndex, aToIndex, b, bFromIndex, bToIndex) == 0)
	* }</pre>
	*
	* @apiNote
	* <p>This method behaves as if:
	* <pre>{@code
	* int i = Arrays.mismatch(a, aFromIndex, aToIndex,
	* b, bFromIndex, bToIndex);
	* if (i >= 0 && i < Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex))
	* return Float.compare(a[aFromIndex + i], b[bFromIndex + i]);
	* return (aToIndex - aFromIndex) - (bToIndex - bFromIndex);
	* }</pre>
	*
	* @param a the first array to compare
	* @param aFromIndex the index (inclusive) of the first element in the
	* first array to be compared
	* @param aToIndex the index (exclusive) of the last element in the
	* first array to be compared
	* @param b the second array to compare
	* @param bFromIndex the index (inclusive) of the first element in the
	* second array to be compared
	* @param bToIndex the index (exclusive) of the last element in the
	* second array to be compared
	* @return the value {@code 0} if, over the specified ranges, the first and
	* second array are equal and contain the same elements in the same
	* order;
	* a value less than {@code 0} if, over the specified ranges, the
	* first array is lexicographically less than the second array; and
	* a value greater than {@code 0} if, over the specified ranges, the
	* first array is lexicographically greater than the second array
	* @throws IllegalArgumentException
	* if {@code aFromIndex > aToIndex} or
	* if {@code bFromIndex > bToIndex}
	* @throws ArrayIndexOutOfBoundsException
	* if {@code aFromIndex < 0 or aToIndex > a.length} or
	* if {@code bFromIndex < 0 or bToIndex > b.length}
	* @throws NullPointerException
	* if either array is {@code null}
	* @since 9
	*/
	public static int compare(float[] a, int aFromIndex, int aToIndex,
	float[] b, int bFromIndex, int bToIndex) {
	rangeCheck(a.length, aFromIndex, aToIndex);
	rangeCheck(b.length, bFromIndex, bToIndex);

	int aLength = aToIndex - aFromIndex;
	int bLength = bToIndex - bFromIndex;
	int i = ArraysSupport.mismatch(a, aFromIndex,
	b, bFromIndex,
	Math.min(aLength, bLength));
	if (i >= 0) {
	return Float.compare(a[aFromIndex + i], b[bFromIndex + i]);
	}

	return aLength - bLength;
	}

	// Compare double

	/**
	* Compares two {@code double} arrays lexicographically.
	*
	* <p>If the two arrays share a common prefix then the lexicographic
	* comparison is the result of comparing two elements, as if by
	* {@link Double#compare(double, double)}, at an index within the respective
	* arrays that is the prefix length.
	* Otherwise, one array is a proper prefix of the other and, lexicographic
	* comparison is the result of comparing the two array lengths.
	* (See {@link #mismatch(double[], double[])} for the definition of a common
	* and proper prefix.)
	*
	* <p>A {@code null} array reference is considered lexicographically less
	* than a non-{@code null} array reference. Two {@code null} array
	* references are considered equal.
	*
	* <p>The comparison is consistent with {@link #equals(double[], double[]) equals},
	* more specifically the following holds for arrays {@code a} and {@code b}:
	* <pre>{@code
	* Arrays.equals(a, b) == (Arrays.compare(a, b) == 0)
	* }</pre>
	*
	* @apiNote
	* <p>This method behaves as if (for non-{@code null} array references):
	* <pre>{@code
	* int i = Arrays.mismatch(a, b);
	* if (i >= 0 && i < Math.min(a.length, b.length))
	* return Double.compare(a[i], b[i]);
	* return a.length - b.length;
	* }</pre>
	*
	* @param a the first array to compare
	* @param b the second array to compare
	* @return the value {@code 0} if the first and second array are equal and
	* contain the same elements in the same order;
	* a value less than {@code 0} if the first array is
	* lexicographically less than the second array; and
	* a value greater than {@code 0} if the first array is
	* lexicographically greater than the second array
	* @since 9
	*/
	public static int compare(double[] a, double[] b) {
	if (a == b)
	return 0;
	if (a == null \|\| b == null)
	return a == null ? -1 : 1;

	int i = ArraysSupport.mismatch(a, b,
	Math.min(a.length, b.length));
	if (i >= 0) {
	return Double.compare(a[i], b[i]);
	}

	return a.length - b.length;
	}

	/**
	* Compares two {@code double} arrays lexicographically over the specified
	* ranges.
	*
	* <p>If the two arrays, over the specified ranges, share a common prefix
	* then the lexicographic comparison is the result of comparing two
	* elements, as if by {@link Double#compare(double, double)}, at a relative
	* index within the respective arrays that is the length of the prefix.
	* Otherwise, one array is a proper prefix of the other and, lexicographic
	* comparison is the result of comparing the two range lengths.
	* (See {@link #mismatch(double[], int, int, double[], int, int)} for the
	* definition of a common and proper prefix.)
	*
	* <p>The comparison is consistent with
	* {@link #equals(double[], int, int, double[], int, int) equals}, more
	* specifically the following holds for arrays {@code a} and {@code b} with
	* specified ranges [{@code aFromIndex}, {@code atoIndex}) and
	* [{@code bFromIndex}, {@code btoIndex}) respectively:
	* <pre>{@code
	* Arrays.equals(a, aFromIndex, aToIndex, b, bFromIndex, bToIndex) ==
	* (Arrays.compare(a, aFromIndex, aToIndex, b, bFromIndex, bToIndex) == 0)
	* }</pre>
	*
	* @apiNote
	* <p>This method behaves as if:
	* <pre>{@code
	* int i = Arrays.mismatch(a, aFromIndex, aToIndex,
	* b, bFromIndex, bToIndex);
	* if (i >= 0 && i < Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex))
	* return Double.compare(a[aFromIndex + i], b[bFromIndex + i]);
	* return (aToIndex - aFromIndex) - (bToIndex - bFromIndex);
	* }</pre>
	*
	* @param a the first array to compare
	* @param aFromIndex the index (inclusive) of the first element in the
	* first array to be compared
	* @param aToIndex the index (exclusive) of the last element in the
	* first array to be compared
	* @param b the second array to compare
	* @param bFromIndex the index (inclusive) of the first element in the
	* second array to be compared
	* @param bToIndex the index (exclusive) of the last element in the
	* second array to be compared
	* @return the value {@code 0} if, over the specified ranges, the first and
	* second array are equal and contain the same elements in the same
	* order;
	* a value less than {@code 0} if, over the specified ranges, the
	* first array is lexicographically less than the second array; and
	* a value greater than {@code 0} if, over the specified ranges, the
	* first array is lexicographically greater than the second array
	* @throws IllegalArgumentException
	* if {@code aFromIndex > aToIndex} or
	* if {@code bFromIndex > bToIndex}
	* @throws ArrayIndexOutOfBoundsException
	* if {@code aFromIndex < 0 or aToIndex > a.length} or
	* if {@code bFromIndex < 0 or bToIndex > b.length}
	* @throws NullPointerException
	* if either array is {@code null}
	* @since 9
	*/
	public static int compare(double[] a, int aFromIndex, int aToIndex,
	double[] b, int bFromIndex, int bToIndex) {
	rangeCheck(a.length, aFromIndex, aToIndex);
	rangeCheck(b.length, bFromIndex, bToIndex);

	int aLength = aToIndex - aFromIndex;
	int bLength = bToIndex - bFromIndex;
	int i = ArraysSupport.mismatch(a, aFromIndex,
	b, bFromIndex,
	Math.min(aLength, bLength));
	if (i >= 0) {
	return Double.compare(a[aFromIndex + i], b[bFromIndex + i]);
	}

	return aLength - bLength;
	}

	// Compare objects

	/**
	* Compares two {@code Object} arrays, within comparable elements,
	* lexicographically.
	*
	* <p>If the two arrays share a common prefix then the lexicographic
	* comparison is the result of comparing two elements of type {@code T} at
	* an index {@code i} within the respective arrays that is the prefix
	* length, as if by:
	* <pre>{@code
	* Comparator.nullsFirst(Comparator.<T>naturalOrder()).
	* compare(a[i], b[i])
	* }</pre>
	* Otherwise, one array is a proper prefix of the other and, lexicographic
	* comparison is the result of comparing the two array lengths.
	* (See {@link #mismatch(Object[], Object[])} for the definition of a common
	* and proper prefix.)
	*
	* <p>A {@code null} array reference is considered lexicographically less
	* than a non-{@code null} array reference. Two {@code null} array
	* references are considered equal.
	* A {@code null} array element is considered lexicographically less than a
	* non-{@code null} array element. Two {@code null} array elements are
	* considered equal.
	*
	* <p>The comparison is consistent with {@link #equals(Object[], Object[]) equals},
	* more specifically the following holds for arrays {@code a} and {@code b}:
	* <pre>{@code
	* Arrays.equals(a, b) == (Arrays.compare(a, b) == 0)
	* }</pre>
	*
	* @apiNote
	* <p>This method behaves as if (for non-{@code null} array references
	* and elements):
	* <pre>{@code
	* int i = Arrays.mismatch(a, b);
	* if (i >= 0 && i < Math.min(a.length, b.length))
	* return a[i].compareTo(b[i]);
	* return a.length - b.length;
	* }</pre>
	*
	* @param a the first array to compare
	* @param b the second array to compare
	* @param <T> the type of comparable array elements
	* @return the value {@code 0} if the first and second array are equal and
	* contain the same elements in the same order;
	* a value less than {@code 0} if the first array is
	* lexicographically less than the second array; and
	* a value greater than {@code 0} if the first array is
	* lexicographically greater than the second array
	* @since 9
	*/
	public static <T extends Comparable<? super T>> int compare(T[] a, T[] b) {
	if (a == b)
	return 0;
	// A null array is less than a non-null array
	if (a == null \|\| b == null)
	return a == null ? -1 : 1;

	int length = Math.min(a.length, b.length);
	for (int i = 0; i < length; i++) {
	T oa = a[i];
	T ob = b[i];
	if (oa != ob) {
	// A null element is less than a non-null element
	if (oa == null \|\| ob == null)
	return oa == null ? -1 : 1;
	int v = oa.compareTo(ob);
	if (v != 0) {
	return v;
	}
	}
	}

	return a.length - b.length;
	}

	/**
	* Compares two {@code Object} arrays lexicographically over the specified
	* ranges.
	*
	* <p>If the two arrays, over the specified ranges, share a common prefix
	* then the lexicographic comparison is the result of comparing two
	* elements of type {@code T} at a relative index {@code i} within the
	* respective arrays that is the prefix length, as if by:
	* <pre>{@code
	* Comparator.nullsFirst(Comparator.<T>naturalOrder()).
	* compare(a[aFromIndex + i, b[bFromIndex + i])
	* }</pre>
	* Otherwise, one array is a proper prefix of the other and, lexicographic
	* comparison is the result of comparing the two range lengths.
	* (See {@link #mismatch(Object[], int, int, Object[], int, int)} for the
	* definition of a common and proper prefix.)
	*
	* <p>The comparison is consistent with
	* {@link #equals(Object[], int, int, Object[], int, int) equals}, more
	* specifically the following holds for arrays {@code a} and {@code b} with
	* specified ranges [{@code aFromIndex}, {@code atoIndex}) and
	* [{@code bFromIndex}, {@code btoIndex}) respectively:
	* <pre>{@code
	* Arrays.equals(a, aFromIndex, aToIndex, b, bFromIndex, bToIndex) ==
	* (Arrays.compare(a, aFromIndex, aToIndex, b, bFromIndex, bToIndex) == 0)
	* }</pre>
	*
	* @apiNote
	* <p>This method behaves as if (for non-{@code null} array elements):
	* <pre>{@code
	* int i = Arrays.mismatch(a, aFromIndex, aToIndex,
	* b, bFromIndex, bToIndex);
	* if (i >= 0 && i < Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex))
	* return a[aFromIndex + i].compareTo(b[bFromIndex + i]);
	* return (aToIndex - aFromIndex) - (bToIndex - bFromIndex);
	* }</pre>
	*
	* @param a the first array to compare
	* @param aFromIndex the index (inclusive) of the first element in the
	* first array to be compared
	* @param aToIndex the index (exclusive) of the last element in the
	* first array to be compared
	* @param b the second array to compare
	* @param bFromIndex the index (inclusive) of the first element in the
	* second array to be compared
	* @param bToIndex the index (exclusive) of the last element in the
	* second array to be compared
	* @param <T> the type of comparable array elements
	* @return the value {@code 0} if, over the specified ranges, the first and
	* second array are equal and contain the same elements in the same
	* order;
	* a value less than {@code 0} if, over the specified ranges, the
	* first array is lexicographically less than the second array; and
	* a value greater than {@code 0} if, over the specified ranges, the
	* first array is lexicographically greater than the second array
	* @throws IllegalArgumentException
	* if {@code aFromIndex > aToIndex} or
	* if {@code bFromIndex > bToIndex}
	* @throws ArrayIndexOutOfBoundsException
	* if {@code aFromIndex < 0 or aToIndex > a.length} or
	* if {@code bFromIndex < 0 or bToIndex > b.length}
	* @throws NullPointerException
	* if either array is {@code null}
	* @since 9
	*/
	public static <T extends Comparable<? super T>> int compare(
	T[] a, int aFromIndex, int aToIndex,
	T[] b, int bFromIndex, int bToIndex) {
	rangeCheck(a.length, aFromIndex, aToIndex);
	rangeCheck(b.length, bFromIndex, bToIndex);

	int aLength = aToIndex - aFromIndex;
	int bLength = bToIndex - bFromIndex;
	int length = Math.min(aLength, bLength);
	for (int i = 0; i < length; i++) {
	T oa = a[aFromIndex++];
	T ob = b[bFromIndex++];
	if (oa != ob) {
	if (oa == null \|\| ob == null)
	return oa == null ? -1 : 1;
	int v = oa.compareTo(ob);
	if (v != 0) {
	return v;
	}
	}
	}

	return aLength - bLength;
	}

	/**
	* Compares two {@code Object} arrays lexicographically using a specified
	* comparator.
	*
	* <p>If the two arrays share a common prefix then the lexicographic
	* comparison is the result of comparing with the specified comparator two
	* elements at an index within the respective arrays that is the prefix
	* length.
	* Otherwise, one array is a proper prefix of the other and, lexicographic
	* comparison is the result of comparing the two array lengths.
	* (See {@link #mismatch(Object[], Object[])} for the definition of a common
	* and proper prefix.)
	*
	* <p>A {@code null} array reference is considered lexicographically less
	* than a non-{@code null} array reference. Two {@code null} array
	* references are considered equal.
	*
	* @apiNote
	* <p>This method behaves as if (for non-{@code null} array references):
	* <pre>{@code
	* int i = Arrays.mismatch(a, b, cmp);
	* if (i >= 0 && i < Math.min(a.length, b.length))
	* return cmp.compare(a[i], b[i]);
	* return a.length - b.length;
	* }</pre>
	*
	* @param a the first array to compare
	* @param b the second array to compare
	* @param cmp the comparator to compare array elements
	* @param <T> the type of array elements
	* @return the value {@code 0} if the first and second array are equal and
	* contain the same elements in the same order;
	* a value less than {@code 0} if the first array is
	* lexicographically less than the second array; and
	* a value greater than {@code 0} if the first array is
	* lexicographically greater than the second array
	* @throws NullPointerException if the comparator is {@code null}
	* @since 9
	*/
	public static <T> int compare(T[] a, T[] b,
	Comparator<? super T> cmp) {
	Objects.requireNonNull(cmp);
	if (a == b)
	return 0;
	if (a == null \|\| b == null)
	return a == null ? -1 : 1;

	int length = Math.min(a.length, b.length);
	for (int i = 0; i < length; i++) {
	T oa = a[i];
	T ob = b[i];
	if (oa != ob) {
	// Null-value comparison is deferred to the comparator
	int v = cmp.compare(oa, ob);
	if (v != 0) {
	return v;
	}
	}
	}

	return a.length - b.length;
	}

	/**
	* Compares two {@code Object} arrays lexicographically over the specified
	* ranges.
	*
	* <p>If the two arrays, over the specified ranges, share a common prefix
	* then the lexicographic comparison is the result of comparing with the
	* specified comparator two elements at a relative index within the
	* respective arrays that is the prefix length.
	* Otherwise, one array is a proper prefix of the other and, lexicographic
	* comparison is the result of comparing the two range lengths.
	* (See {@link #mismatch(Object[], int, int, Object[], int, int)} for the
	* definition of a common and proper prefix.)
	*
	* @apiNote
	* <p>This method behaves as if (for non-{@code null} array elements):
	* <pre>{@code
	* int i = Arrays.mismatch(a, aFromIndex, aToIndex,
	* b, bFromIndex, bToIndex, cmp);
	* if (i >= 0 && i < Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex))
	* return cmp.compare(a[aFromIndex + i], b[bFromIndex + i]);
	* return (aToIndex - aFromIndex) - (bToIndex - bFromIndex);
	* }</pre>
	*
	* @param a the first array to compare
	* @param aFromIndex the index (inclusive) of the first element in the
	* first array to be compared
	* @param aToIndex the index (exclusive) of the last element in the
	* first array to be compared
	* @param b the second array to compare
	* @param bFromIndex the index (inclusive) of the first element in the
	* second array to be compared
	* @param bToIndex the index (exclusive) of the last element in the
	* second array to be compared
	* @param cmp the comparator to compare array elements
	* @param <T> the type of array elements
	* @return the value {@code 0} if, over the specified ranges, the first and
	* second array are equal and contain the same elements in the same
	* order;
	* a value less than {@code 0} if, over the specified ranges, the
	* first array is lexicographically less than the second array; and
	* a value greater than {@code 0} if, over the specified ranges, the
	* first array is lexicographically greater than the second array
	* @throws IllegalArgumentException
	* if {@code aFromIndex > aToIndex} or
	* if {@code bFromIndex > bToIndex}
	* @throws ArrayIndexOutOfBoundsException
	* if {@code aFromIndex < 0 or aToIndex > a.length} or
	* if {@code bFromIndex < 0 or bToIndex > b.length}
	* @throws NullPointerException
	* if either array or the comparator is {@code null}
	* @since 9
	*/
	public static <T> int compare(
	T[] a, int aFromIndex, int aToIndex,
	T[] b, int bFromIndex, int bToIndex,
	Comparator<? super T> cmp) {
	Objects.requireNonNull(cmp);
	rangeCheck(a.length, aFromIndex, aToIndex);
	rangeCheck(b.length, bFromIndex, bToIndex);

	int aLength = aToIndex - aFromIndex;
	int bLength = bToIndex - bFromIndex;
	int length = Math.min(aLength, bLength);
	for (int i = 0; i < length; i++) {
	T oa = a[aFromIndex++];
	T ob = b[bFromIndex++];
	if (oa != ob) {
	// Null-value comparison is deferred to the comparator
	int v = cmp.compare(oa, ob);
	if (v != 0) {
	return v;
	}
	}
	}

	return aLength - bLength;
	}


	// Mismatch methods

	// Mismatch boolean

	/**
	* Finds and returns the index of the first mismatch between two
	* {@code boolean} arrays, otherwise return -1 if no mismatch is found. The
	* index will be in the range of 0 (inclusive) up to the length (inclusive)
	* of the smaller array.
	*
	* <p>If the two arrays share a common prefix then the returned index is the
	* length of the common prefix and it follows that there is a mismatch
	* between the two elements at that index within the respective arrays.
	* If one array is a proper prefix of the other then the returned index is
	* the length of the smaller array and it follows that the index is only
	* valid for the larger array.
	* Otherwise, there is no mismatch.
	*
	* <p>Two non-{@code null} arrays, {@code a} and {@code b}, share a common
	* prefix of length {@code pl} if the following expression is true:
	* <pre>{@code
	* pl >= 0 &&
	* pl < Math.min(a.length, b.length) &&
	* Arrays.equals(a, 0, pl, b, 0, pl) &&
	* a[pl] != b[pl]
	* }</pre>
	* Note that a common prefix length of {@code 0} indicates that the first
	* elements from each array mismatch.
	*
	* <p>Two non-{@code null} arrays, {@code a} and {@code b}, share a proper
	* prefix if the following expression is true:
	* <pre>{@code
	* a.length != b.length &&
	* Arrays.equals(a, 0, Math.min(a.length, b.length),
	* b, 0, Math.min(a.length, b.length))
	* }</pre>
	*
	* @param a the first array to be tested for a mismatch
	* @param b the second array to be tested for a mismatch
	* @return the index of the first mismatch between the two arrays,
	* otherwise {@code -1}.
	* @throws NullPointerException
	* if either array is {@code null}
	* @since 9
	*/
	public static int mismatch(boolean[] a, boolean[] b) {
	int length = Math.min(a.length, b.length); // Check null array refs
	if (a == b)
	return -1;

	int i = ArraysSupport.mismatch(a, b, length);
	return (i < 0 && a.length != b.length) ? length : i;
	}

	/**
	* Finds and returns the relative index of the first mismatch between two
	* {@code boolean} arrays over the specified ranges, otherwise return -1 if
	* no mismatch is found. The index will be in the range of 0 (inclusive) up
	* to the length (inclusive) of the smaller range.
	*
	* <p>If the two arrays, over the specified ranges, share a common prefix
	* then the returned relative index is the length of the common prefix and
	* it follows that there is a mismatch between the two elements at that
	* relative index within the respective arrays.
	* If one array is a proper prefix of the other, over the specified ranges,
	* then the returned relative index is the length of the smaller range and
	* it follows that the relative index is only valid for the array with the
	* larger range.
	* Otherwise, there is no mismatch.
	*
	* <p>Two non-{@code null} arrays, {@code a} and {@code b} with specified
	* ranges [{@code aFromIndex}, {@code atoIndex}) and
	* [{@code bFromIndex}, {@code btoIndex}) respectively, share a common
	* prefix of length {@code pl} if the following expression is true:
	* <pre>{@code
	* pl >= 0 &&
	* pl < Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex) &&
	* Arrays.equals(a, aFromIndex, aFromIndex + pl, b, bFromIndex, bFromIndex + pl) &&
	* a[aFromIndex + pl] != b[bFromIndex + pl]
	* }</pre>
	* Note that a common prefix length of {@code 0} indicates that the first
	* elements from each array mismatch.
	*
	* <p>Two non-{@code null} arrays, {@code a} and {@code b} with specified
	* ranges [{@code aFromIndex}, {@code atoIndex}) and
	* [{@code bFromIndex}, {@code btoIndex}) respectively, share a proper
	* prefix if the following expression is true:
	* <pre>{@code
	* (aToIndex - aFromIndex) != (bToIndex - bFromIndex) &&
	* Arrays.equals(a, 0, Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex),
	* b, 0, Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex))
	* }</pre>
	*
	* @param a the first array to be tested for a mismatch
	* @param aFromIndex the index (inclusive) of the first element in the
	* first array to be tested
	* @param aToIndex the index (exclusive) of the last element in the
	* first array to be tested
	* @param b the second array to be tested for a mismatch
	* @param bFromIndex the index (inclusive) of the first element in the
	* second array to be tested
	* @param bToIndex the index (exclusive) of the last element in the
	* second array to be tested
	* @return the relative index of the first mismatch between the two arrays
	* over the specified ranges, otherwise {@code -1}.
	* @throws IllegalArgumentException
	* if {@code aFromIndex > aToIndex} or
	* if {@code bFromIndex > bToIndex}
	* @throws ArrayIndexOutOfBoundsException
	* if {@code aFromIndex < 0 or aToIndex > a.length} or
	* if {@code bFromIndex < 0 or bToIndex > b.length}
	* @throws NullPointerException
	* if either array is {@code null}
	* @since 9
	*/
	public static int mismatch(boolean[] a, int aFromIndex, int aToIndex,
	boolean[] b, int bFromIndex, int bToIndex) {
	rangeCheck(a.length, aFromIndex, aToIndex);
	rangeCheck(b.length, bFromIndex, bToIndex);

	int aLength = aToIndex - aFromIndex;
	int bLength = bToIndex - bFromIndex;
	int length = Math.min(aLength, bLength);
	int i = ArraysSupport.mismatch(a, aFromIndex,
	b, bFromIndex,
	length);
	return (i < 0 && aLength != bLength) ? length : i;
	}

	// Mismatch byte

	/**
	* Finds and returns the index of the first mismatch between two {@code byte}
	* arrays, otherwise return -1 if no mismatch is found. The index will be
	* in the range of 0 (inclusive) up to the length (inclusive) of the smaller
	* array.
	*
	* <p>If the two arrays share a common prefix then the returned index is the
	* length of the common prefix and it follows that there is a mismatch
	* between the two elements at that index within the respective arrays.
	* If one array is a proper prefix of the other then the returned index is
	* the length of the smaller array and it follows that the index is only
	* valid for the larger array.
	* Otherwise, there is no mismatch.
	*
	* <p>Two non-{@code null} arrays, {@code a} and {@code b}, share a common
	* prefix of length {@code pl} if the following expression is true:
	* <pre>{@code
	* pl >= 0 &&
	* pl < Math.min(a.length, b.length) &&
	* Arrays.equals(a, 0, pl, b, 0, pl) &&
	* a[pl] != b[pl]
	* }</pre>
	* Note that a common prefix length of {@code 0} indicates that the first
	* elements from each array mismatch.
	*
	* <p>Two non-{@code null} arrays, {@code a} and {@code b}, share a proper
	* prefix if the following expression is true:
	* <pre>{@code
	* a.length != b.length &&
	* Arrays.equals(a, 0, Math.min(a.length, b.length),
	* b, 0, Math.min(a.length, b.length))
	* }</pre>
	*
	* @param a the first array to be tested for a mismatch
	* @param b the second array to be tested for a mismatch
	* @return the index of the first mismatch between the two arrays,
	* otherwise {@code -1}.
	* @throws NullPointerException
	* if either array is {@code null}
	* @since 9
	*/
	public static int mismatch(byte[] a, byte[] b) {
	int length = Math.min(a.length, b.length); // Check null array refs
	if (a == b)
	return -1;

	int i = ArraysSupport.mismatch(a, b, length);
	return (i < 0 && a.length != b.length) ? length : i;
	}

	/**
	* Finds and returns the relative index of the first mismatch between two
	* {@code byte} arrays over the specified ranges, otherwise return -1 if no
	* mismatch is found. The index will be in the range of 0 (inclusive) up to
	* the length (inclusive) of the smaller range.
	*
	* <p>If the two arrays, over the specified ranges, share a common prefix
	* then the returned relative index is the length of the common prefix and
	* it follows that there is a mismatch between the two elements at that
	* relative index within the respective arrays.
	* If one array is a proper prefix of the other, over the specified ranges,
	* then the returned relative index is the length of the smaller range and
	* it follows that the relative index is only valid for the array with the
	* larger range.
	* Otherwise, there is no mismatch.
	*
	* <p>Two non-{@code null} arrays, {@code a} and {@code b} with specified
	* ranges [{@code aFromIndex}, {@code atoIndex}) and
	* [{@code bFromIndex}, {@code btoIndex}) respectively, share a common
	* prefix of length {@code pl} if the following expression is true:
	* <pre>{@code
	* pl >= 0 &&
	* pl < Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex) &&
	* Arrays.equals(a, aFromIndex, aFromIndex + pl, b, bFromIndex, bFromIndex + pl) &&
	* a[aFromIndex + pl] != b[bFromIndex + pl]
	* }</pre>
	* Note that a common prefix length of {@code 0} indicates that the first
	* elements from each array mismatch.
	*
	* <p>Two non-{@code null} arrays, {@code a} and {@code b} with specified
	* ranges [{@code aFromIndex}, {@code atoIndex}) and
	* [{@code bFromIndex}, {@code btoIndex}) respectively, share a proper
	* prefix if the following expression is true:
	* <pre>{@code
	* (aToIndex - aFromIndex) != (bToIndex - bFromIndex) &&
	* Arrays.equals(a, 0, Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex),
	* b, 0, Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex))
	* }</pre>
	*
	* @param a the first array to be tested for a mismatch
	* @param aFromIndex the index (inclusive) of the first element in the
	* first array to be tested
	* @param aToIndex the index (exclusive) of the last element in the
	* first array to be tested
	* @param b the second array to be tested for a mismatch
	* @param bFromIndex the index (inclusive) of the first element in the
	* second array to be tested
	* @param bToIndex the index (exclusive) of the last element in the
	* second array to be tested
	* @return the relative index of the first mismatch between the two arrays
	* over the specified ranges, otherwise {@code -1}.
	* @throws IllegalArgumentException
	* if {@code aFromIndex > aToIndex} or
	* if {@code bFromIndex > bToIndex}
	* @throws ArrayIndexOutOfBoundsException
	* if {@code aFromIndex < 0 or aToIndex > a.length} or
	* if {@code bFromIndex < 0 or bToIndex > b.length}
	* @throws NullPointerException
	* if either array is {@code null}
	* @since 9
	*/
	public static int mismatch(byte[] a, int aFromIndex, int aToIndex,
	byte[] b, int bFromIndex, int bToIndex) {
	rangeCheck(a.length, aFromIndex, aToIndex);
	rangeCheck(b.length, bFromIndex, bToIndex);

	int aLength = aToIndex - aFromIndex;
	int bLength = bToIndex - bFromIndex;
	int length = Math.min(aLength, bLength);
	int i = ArraysSupport.mismatch(a, aFromIndex,
	b, bFromIndex,
	length);
	return (i < 0 && aLength != bLength) ? length : i;
	}

	// Mismatch char

	/**
	* Finds and returns the index of the first mismatch between two {@code char}
	* arrays, otherwise return -1 if no mismatch is found. The index will be
	* in the range of 0 (inclusive) up to the length (inclusive) of the smaller
	* array.
	*
	* <p>If the two arrays share a common prefix then the returned index is the
	* length of the common prefix and it follows that there is a mismatch
	* between the two elements at that index within the respective arrays.
	* If one array is a proper prefix of the other then the returned index is
	* the length of the smaller array and it follows that the index is only
	* valid for the larger array.
	* Otherwise, there is no mismatch.
	*
	* <p>Two non-{@code null} arrays, {@code a} and {@code b}, share a common
	* prefix of length {@code pl} if the following expression is true:
	* <pre>{@code
	* pl >= 0 &&
	* pl < Math.min(a.length, b.length) &&
	* Arrays.equals(a, 0, pl, b, 0, pl) &&
	* a[pl] != b[pl]
	* }</pre>
	* Note that a common prefix length of {@code 0} indicates that the first
	* elements from each array mismatch.
	*
	* <p>Two non-{@code null} arrays, {@code a} and {@code b}, share a proper
	* prefix if the following expression is true:
	* <pre>{@code
	* a.length != b.length &&
	* Arrays.equals(a, 0, Math.min(a.length, b.length),
	* b, 0, Math.min(a.length, b.length))
	* }</pre>
	*
	* @param a the first array to be tested for a mismatch
	* @param b the second array to be tested for a mismatch
	* @return the index of the first mismatch between the two arrays,
	* otherwise {@code -1}.
	* @throws NullPointerException
	* if either array is {@code null}
	* @since 9
	*/
	public static int mismatch(char[] a, char[] b) {
	int length = Math.min(a.length, b.length); // Check null array refs
	if (a == b)
	return -1;

	int i = ArraysSupport.mismatch(a, b, length);
	return (i < 0 && a.length != b.length) ? length : i;
	}

	/**
	* Finds and returns the relative index of the first mismatch between two
	* {@code char} arrays over the specified ranges, otherwise return -1 if no
	* mismatch is found. The index will be in the range of 0 (inclusive) up to
	* the length (inclusive) of the smaller range.
	*
	* <p>If the two arrays, over the specified ranges, share a common prefix
	* then the returned relative index is the length of the common prefix and
	* it follows that there is a mismatch between the two elements at that
	* relative index within the respective arrays.
	* If one array is a proper prefix of the other, over the specified ranges,
	* then the returned relative index is the length of the smaller range and
	* it follows that the relative index is only valid for the array with the
	* larger range.
	* Otherwise, there is no mismatch.
	*
	* <p>Two non-{@code null} arrays, {@code a} and {@code b} with specified
	* ranges [{@code aFromIndex}, {@code atoIndex}) and
	* [{@code bFromIndex}, {@code btoIndex}) respectively, share a common
	* prefix of length {@code pl} if the following expression is true:
	* <pre>{@code
	* pl >= 0 &&
	* pl < Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex) &&
	* Arrays.equals(a, aFromIndex, aFromIndex + pl, b, bFromIndex, bFromIndex + pl) &&
	* a[aFromIndex + pl] != b[bFromIndex + pl]
	* }</pre>
	* Note that a common prefix length of {@code 0} indicates that the first
	* elements from each array mismatch.
	*
	* <p>Two non-{@code null} arrays, {@code a} and {@code b} with specified
	* ranges [{@code aFromIndex}, {@code atoIndex}) and
	* [{@code bFromIndex}, {@code btoIndex}) respectively, share a proper
	* prefix if the following expression is true:
	* <pre>{@code
	* (aToIndex - aFromIndex) != (bToIndex - bFromIndex) &&
	* Arrays.equals(a, 0, Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex),
	* b, 0, Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex))
	* }</pre>
	*
	* @param a the first array to be tested for a mismatch
	* @param aFromIndex the index (inclusive) of the first element in the
	* first array to be tested
	* @param aToIndex the index (exclusive) of the last element in the
	* first array to be tested
	* @param b the second array to be tested for a mismatch
	* @param bFromIndex the index (inclusive) of the first element in the
	* second array to be tested
	* @param bToIndex the index (exclusive) of the last element in the
	* second array to be tested
	* @return the relative index of the first mismatch between the two arrays
	* over the specified ranges, otherwise {@code -1}.
	* @throws IllegalArgumentException
	* if {@code aFromIndex > aToIndex} or
	* if {@code bFromIndex > bToIndex}
	* @throws ArrayIndexOutOfBoundsException
	* if {@code aFromIndex < 0 or aToIndex > a.length} or
	* if {@code bFromIndex < 0 or bToIndex > b.length}
	* @throws NullPointerException
	* if either array is {@code null}
	* @since 9
	*/
	public static int mismatch(char[] a, int aFromIndex, int aToIndex,
	char[] b, int bFromIndex, int bToIndex) {
	rangeCheck(a.length, aFromIndex, aToIndex);
	rangeCheck(b.length, bFromIndex, bToIndex);

	int aLength = aToIndex - aFromIndex;
	int bLength = bToIndex - bFromIndex;
	int length = Math.min(aLength, bLength);
	int i = ArraysSupport.mismatch(a, aFromIndex,
	b, bFromIndex,
	length);
	return (i < 0 && aLength != bLength) ? length : i;
	}

	// Mismatch short

	/**
	* Finds and returns the index of the first mismatch between two {@code short}
	* arrays, otherwise return -1 if no mismatch is found. The index will be
	* in the range of 0 (inclusive) up to the length (inclusive) of the smaller
	* array.
	*
	* <p>If the two arrays share a common prefix then the returned index is the
	* length of the common prefix and it follows that there is a mismatch
	* between the two elements at that index within the respective arrays.
	* If one array is a proper prefix of the other then the returned index is
	* the length of the smaller array and it follows that the index is only
	* valid for the larger array.
	* Otherwise, there is no mismatch.
	*
	* <p>Two non-{@code null} arrays, {@code a} and {@code b}, share a common
	* prefix of length {@code pl} if the following expression is true:
	* <pre>{@code
	* pl >= 0 &&
	* pl < Math.min(a.length, b.length) &&
	* Arrays.equals(a, 0, pl, b, 0, pl) &&
	* a[pl] != b[pl]
	* }</pre>
	* Note that a common prefix length of {@code 0} indicates that the first
	* elements from each array mismatch.
	*
	* <p>Two non-{@code null} arrays, {@code a} and {@code b}, share a proper
	* prefix if the following expression is true:
	* <pre>{@code
	* a.length != b.length &&
	* Arrays.equals(a, 0, Math.min(a.length, b.length),
	* b, 0, Math.min(a.length, b.length))
	* }</pre>
	*
	* @param a the first array to be tested for a mismatch
	* @param b the second array to be tested for a mismatch
	* @return the index of the first mismatch between the two arrays,
	* otherwise {@code -1}.
	* @throws NullPointerException
	* if either array is {@code null}
	* @since 9
	*/
	public static int mismatch(short[] a, short[] b) {
	int length = Math.min(a.length, b.length); // Check null array refs
	if (a == b)
	return -1;

	int i = ArraysSupport.mismatch(a, b, length);
	return (i < 0 && a.length != b.length) ? length : i;
	}

	/**
	* Finds and returns the relative index of the first mismatch between two
	* {@code short} arrays over the specified ranges, otherwise return -1 if no
	* mismatch is found. The index will be in the range of 0 (inclusive) up to
	* the length (inclusive) of the smaller range.
	*
	* <p>If the two arrays, over the specified ranges, share a common prefix
	* then the returned relative index is the length of the common prefix and
	* it follows that there is a mismatch between the two elements at that
	* relative index within the respective arrays.
	* If one array is a proper prefix of the other, over the specified ranges,
	* then the returned relative index is the length of the smaller range and
	* it follows that the relative index is only valid for the array with the
	* larger range.
	* Otherwise, there is no mismatch.
	*
	* <p>Two non-{@code null} arrays, {@code a} and {@code b} with specified
	* ranges [{@code aFromIndex}, {@code atoIndex}) and
	* [{@code bFromIndex}, {@code btoIndex}) respectively, share a common
	* prefix of length {@code pl} if the following expression is true:
	* <pre>{@code
	* pl >= 0 &&
	* pl < Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex) &&
	* Arrays.equals(a, aFromIndex, aFromIndex + pl, b, bFromIndex, bFromIndex + pl) &&
	* a[aFromIndex + pl] != b[bFromIndex + pl]
	* }</pre>
	* Note that a common prefix length of {@code 0} indicates that the first
	* elements from each array mismatch.
	*
	* <p>Two non-{@code null} arrays, {@code a} and {@code b} with specified
	* ranges [{@code aFromIndex}, {@code atoIndex}) and
	* [{@code bFromIndex}, {@code btoIndex}) respectively, share a proper
	* prefix if the following expression is true:
	* <pre>{@code
	* (aToIndex - aFromIndex) != (bToIndex - bFromIndex) &&
	* Arrays.equals(a, 0, Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex),
	* b, 0, Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex))
	* }</pre>
	*
	* @param a the first array to be tested for a mismatch
	* @param aFromIndex the index (inclusive) of the first element in the
	* first array to be tested
	* @param aToIndex the index (exclusive) of the last element in the
	* first array to be tested
	* @param b the second array to be tested for a mismatch
	* @param bFromIndex the index (inclusive) of the first element in the
	* second array to be tested
	* @param bToIndex the index (exclusive) of the last element in the
	* second array to be tested
	* @return the relative index of the first mismatch between the two arrays
	* over the specified ranges, otherwise {@code -1}.
	* @throws IllegalArgumentException
	* if {@code aFromIndex > aToIndex} or
	* if {@code bFromIndex > bToIndex}
	* @throws ArrayIndexOutOfBoundsException
	* if {@code aFromIndex < 0 or aToIndex > a.length} or
	* if {@code bFromIndex < 0 or bToIndex > b.length}
	* @throws NullPointerException
	* if either array is {@code null}
	* @since 9
	*/
	public static int mismatch(short[] a, int aFromIndex, int aToIndex,
	short[] b, int bFromIndex, int bToIndex) {
	rangeCheck(a.length, aFromIndex, aToIndex);
	rangeCheck(b.length, bFromIndex, bToIndex);

	int aLength = aToIndex - aFromIndex;
	int bLength = bToIndex - bFromIndex;
	int length = Math.min(aLength, bLength);
	int i = ArraysSupport.mismatch(a, aFromIndex,
	b, bFromIndex,
	length);
	return (i < 0 && aLength != bLength) ? length : i;
	}

	// Mismatch int

	/**
	* Finds and returns the index of the first mismatch between two {@code int}
	* arrays, otherwise return -1 if no mismatch is found. The index will be
	* in the range of 0 (inclusive) up to the length (inclusive) of the smaller
	* array.
	*
	* <p>If the two arrays share a common prefix then the returned index is the
	* length of the common prefix and it follows that there is a mismatch
	* between the two elements at that index within the respective arrays.
	* If one array is a proper prefix of the other then the returned index is
	* the length of the smaller array and it follows that the index is only
	* valid for the larger array.
	* Otherwise, there is no mismatch.
	*
	* <p>Two non-{@code null} arrays, {@code a} and {@code b}, share a common
	* prefix of length {@code pl} if the following expression is true:
	* <pre>{@code
	* pl >= 0 &&
	* pl < Math.min(a.length, b.length) &&
	* Arrays.equals(a, 0, pl, b, 0, pl) &&
	* a[pl] != b[pl]
	* }</pre>
	* Note that a common prefix length of {@code 0} indicates that the first
	* elements from each array mismatch.
	*
	* <p>Two non-{@code null} arrays, {@code a} and {@code b}, share a proper
	* prefix if the following expression is true:
	* <pre>{@code
	* a.length != b.length &&
	* Arrays.equals(a, 0, Math.min(a.length, b.length),
	* b, 0, Math.min(a.length, b.length))
	* }</pre>
	*
	* @param a the first array to be tested for a mismatch
	* @param b the second array to be tested for a mismatch
	* @return the index of the first mismatch between the two arrays,
	* otherwise {@code -1}.
	* @throws NullPointerException
	* if either array is {@code null}
	* @since 9
	*/
	public static int mismatch(int[] a, int[] b) {
	int length = Math.min(a.length, b.length); // Check null array refs
	if (a == b)
	return -1;

	int i = ArraysSupport.mismatch(a, b, length);
	return (i < 0 && a.length != b.length) ? length : i;
	}

	/**
	* Finds and returns the relative index of the first mismatch between two
	* {@code int} arrays over the specified ranges, otherwise return -1 if no
	* mismatch is found. The index will be in the range of 0 (inclusive) up to
	* the length (inclusive) of the smaller range.
	*
	* <p>If the two arrays, over the specified ranges, share a common prefix
	* then the returned relative index is the length of the common prefix and
	* it follows that there is a mismatch between the two elements at that
	* relative index within the respective arrays.
	* If one array is a proper prefix of the other, over the specified ranges,
	* then the returned relative index is the length of the smaller range and
	* it follows that the relative index is only valid for the array with the
	* larger range.
	* Otherwise, there is no mismatch.
	*
	* <p>Two non-{@code null} arrays, {@code a} and {@code b} with specified
	* ranges [{@code aFromIndex}, {@code atoIndex}) and
	* [{@code bFromIndex}, {@code btoIndex}) respectively, share a common
	* prefix of length {@code pl} if the following expression is true:
	* <pre>{@code
	* pl >= 0 &&
	* pl < Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex) &&
	* Arrays.equals(a, aFromIndex, aFromIndex + pl, b, bFromIndex, bFromIndex + pl) &&
	* a[aFromIndex + pl] != b[bFromIndex + pl]
	* }</pre>
	* Note that a common prefix length of {@code 0} indicates that the first
	* elements from each array mismatch.
	*
	* <p>Two non-{@code null} arrays, {@code a} and {@code b} with specified
	* ranges [{@code aFromIndex}, {@code atoIndex}) and
	* [{@code bFromIndex}, {@code btoIndex}) respectively, share a proper
	* prefix if the following expression is true:
	* <pre>{@code
	* (aToIndex - aFromIndex) != (bToIndex - bFromIndex) &&
	* Arrays.equals(a, 0, Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex),
	* b, 0, Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex))
	* }</pre>
	*
	* @param a the first array to be tested for a mismatch
	* @param aFromIndex the index (inclusive) of the first element in the
	* first array to be tested
	* @param aToIndex the index (exclusive) of the last element in the
	* first array to be tested
	* @param b the second array to be tested for a mismatch
	* @param bFromIndex the index (inclusive) of the first element in the
	* second array to be tested
	* @param bToIndex the index (exclusive) of the last element in the
	* second array to be tested
	* @return the relative index of the first mismatch between the two arrays
	* over the specified ranges, otherwise {@code -1}.
	* @throws IllegalArgumentException
	* if {@code aFromIndex > aToIndex} or
	* if {@code bFromIndex > bToIndex}
	* @throws ArrayIndexOutOfBoundsException
	* if {@code aFromIndex < 0 or aToIndex > a.length} or
	* if {@code bFromIndex < 0 or bToIndex > b.length}
	* @throws NullPointerException
	* if either array is {@code null}
	* @since 9
	*/
	public static int mismatch(int[] a, int aFromIndex, int aToIndex,
	int[] b, int bFromIndex, int bToIndex) {
	rangeCheck(a.length, aFromIndex, aToIndex);
	rangeCheck(b.length, bFromIndex, bToIndex);

	int aLength = aToIndex - aFromIndex;
	int bLength = bToIndex - bFromIndex;
	int length = Math.min(aLength, bLength);
	int i = ArraysSupport.mismatch(a, aFromIndex,
	b, bFromIndex,
	length);
	return (i < 0 && aLength != bLength) ? length : i;
	}

	// Mismatch long

	/**
	* Finds and returns the index of the first mismatch between two {@code long}
	* arrays, otherwise return -1 if no mismatch is found. The index will be
	* in the range of 0 (inclusive) up to the length (inclusive) of the smaller
	* array.
	*
	* <p>If the two arrays share a common prefix then the returned index is the
	* length of the common prefix and it follows that there is a mismatch
	* between the two elements at that index within the respective arrays.
	* If one array is a proper prefix of the other then the returned index is
	* the length of the smaller array and it follows that the index is only
	* valid for the larger array.
	* Otherwise, there is no mismatch.
	*
	* <p>Two non-{@code null} arrays, {@code a} and {@code b}, share a common
	* prefix of length {@code pl} if the following expression is true:
	* <pre>{@code
	* pl >= 0 &&
	* pl < Math.min(a.length, b.length) &&
	* Arrays.equals(a, 0, pl, b, 0, pl) &&
	* a[pl] != b[pl]
	* }</pre>
	* Note that a common prefix length of {@code 0} indicates that the first
	* elements from each array mismatch.
	*
	* <p>Two non-{@code null} arrays, {@code a} and {@code b}, share a proper
	* prefix if the following expression is true:
	* <pre>{@code
	* a.length != b.length &&
	* Arrays.equals(a, 0, Math.min(a.length, b.length),
	* b, 0, Math.min(a.length, b.length))
	* }</pre>
	*
	* @param a the first array to be tested for a mismatch
	* @param b the second array to be tested for a mismatch
	* @return the index of the first mismatch between the two arrays,
	* otherwise {@code -1}.
	* @throws NullPointerException
	* if either array is {@code null}
	* @since 9
	*/
	public static int mismatch(long[] a, long[] b) {
	int length = Math.min(a.length, b.length); // Check null array refs
	if (a == b)
	return -1;

	int i = ArraysSupport.mismatch(a, b, length);
	return (i < 0 && a.length != b.length) ? length : i;
	}

	/**
	* Finds and returns the relative index of the first mismatch between two
	* {@code long} arrays over the specified ranges, otherwise return -1 if no
	* mismatch is found. The index will be in the range of 0 (inclusive) up to
	* the length (inclusive) of the smaller range.
	*
	* <p>If the two arrays, over the specified ranges, share a common prefix
	* then the returned relative index is the length of the common prefix and
	* it follows that there is a mismatch between the two elements at that
	* relative index within the respective arrays.
	* If one array is a proper prefix of the other, over the specified ranges,
	* then the returned relative index is the length of the smaller range and
	* it follows that the relative index is only valid for the array with the
	* larger range.
	* Otherwise, there is no mismatch.
	*
	* <p>Two non-{@code null} arrays, {@code a} and {@code b} with specified
	* ranges [{@code aFromIndex}, {@code atoIndex}) and
	* [{@code bFromIndex}, {@code btoIndex}) respectively, share a common
	* prefix of length {@code pl} if the following expression is true:
	* <pre>{@code
	* pl >= 0 &&
	* pl < Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex) &&
	* Arrays.equals(a, aFromIndex, aFromIndex + pl, b, bFromIndex, bFromIndex + pl) &&
	* a[aFromIndex + pl] != b[bFromIndex + pl]
	* }</pre>
	* Note that a common prefix length of {@code 0} indicates that the first
	* elements from each array mismatch.
	*
	* <p>Two non-{@code null} arrays, {@code a} and {@code b} with specified
	* ranges [{@code aFromIndex}, {@code atoIndex}) and
	* [{@code bFromIndex}, {@code btoIndex}) respectively, share a proper
	* prefix if the following expression is true:
	* <pre>{@code
	* (aToIndex - aFromIndex) != (bToIndex - bFromIndex) &&
	* Arrays.equals(a, 0, Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex),
	* b, 0, Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex))
	* }</pre>
	*
	* @param a the first array to be tested for a mismatch
	* @param aFromIndex the index (inclusive) of the first element in the
	* first array to be tested
	* @param aToIndex the index (exclusive) of the last element in the
	* first array to be tested
	* @param b the second array to be tested for a mismatch
	* @param bFromIndex the index (inclusive) of the first element in the
	* second array to be tested
	* @param bToIndex the index (exclusive) of the last element in the
	* second array to be tested
	* @return the relative index of the first mismatch between the two arrays
	* over the specified ranges, otherwise {@code -1}.
	* @throws IllegalArgumentException
	* if {@code aFromIndex > aToIndex} or
	* if {@code bFromIndex > bToIndex}
	* @throws ArrayIndexOutOfBoundsException
	* if {@code aFromIndex < 0 or aToIndex > a.length} or
	* if {@code bFromIndex < 0 or bToIndex > b.length}
	* @throws NullPointerException
	* if either array is {@code null}
	* @since 9
	*/
	public static int mismatch(long[] a, int aFromIndex, int aToIndex,
	long[] b, int bFromIndex, int bToIndex) {
	rangeCheck(a.length, aFromIndex, aToIndex);
	rangeCheck(b.length, bFromIndex, bToIndex);

	int aLength = aToIndex - aFromIndex;
	int bLength = bToIndex - bFromIndex;
	int length = Math.min(aLength, bLength);
	int i = ArraysSupport.mismatch(a, aFromIndex,
	b, bFromIndex,
	length);
	return (i < 0 && aLength != bLength) ? length : i;
	}

	// Mismatch float

	/**
	* Finds and returns the index of the first mismatch between two {@code float}
	* arrays, otherwise return -1 if no mismatch is found. The index will be
	* in the range of 0 (inclusive) up to the length (inclusive) of the smaller
	* array.
	*
	* <p>If the two arrays share a common prefix then the returned index is the
	* length of the common prefix and it follows that there is a mismatch
	* between the two elements at that index within the respective arrays.
	* If one array is a proper prefix of the other then the returned index is
	* the length of the smaller array and it follows that the index is only
	* valid for the larger array.
	* Otherwise, there is no mismatch.
	*
	* <p>Two non-{@code null} arrays, {@code a} and {@code b}, share a common
	* prefix of length {@code pl} if the following expression is true:
	* <pre>{@code
	* pl >= 0 &&
	* pl < Math.min(a.length, b.length) &&
	* Arrays.equals(a, 0, pl, b, 0, pl) &&
	* Float.compare(a[pl], b[pl]) != 0
	* }</pre>
	* Note that a common prefix length of {@code 0} indicates that the first
	* elements from each array mismatch.
	*
	* <p>Two non-{@code null} arrays, {@code a} and {@code b}, share a proper
	* prefix if the following expression is true:
	* <pre>{@code
	* a.length != b.length &&
	* Arrays.equals(a, 0, Math.min(a.length, b.length),
	* b, 0, Math.min(a.length, b.length))
	* }</pre>
	*
	* @param a the first array to be tested for a mismatch
	* @param b the second array to be tested for a mismatch
	* @return the index of the first mismatch between the two arrays,
	* otherwise {@code -1}.
	* @throws NullPointerException
	* if either array is {@code null}
	* @since 9
	*/
	public static int mismatch(float[] a, float[] b) {
	int length = Math.min(a.length, b.length); // Check null array refs
	if (a == b)
	return -1;

	int i = ArraysSupport.mismatch(a, b, length);
	return (i < 0 && a.length != b.length) ? length : i;
	}

	/**
	* Finds and returns the relative index of the first mismatch between two
	* {@code float} arrays over the specified ranges, otherwise return -1 if no
	* mismatch is found. The index will be in the range of 0 (inclusive) up to
	* the length (inclusive) of the smaller range.
	*
	* <p>If the two arrays, over the specified ranges, share a common prefix
	* then the returned relative index is the length of the common prefix and
	* it follows that there is a mismatch between the two elements at that
	* relative index within the respective arrays.
	* If one array is a proper prefix of the other, over the specified ranges,
	* then the returned relative index is the length of the smaller range and
	* it follows that the relative index is only valid for the array with the
	* larger range.
	* Otherwise, there is no mismatch.
	*
	* <p>Two non-{@code null} arrays, {@code a} and {@code b} with specified
	* ranges [{@code aFromIndex}, {@code atoIndex}) and
	* [{@code bFromIndex}, {@code btoIndex}) respectively, share a common
	* prefix of length {@code pl} if the following expression is true:
	* <pre>{@code
	* pl >= 0 &&
	* pl < Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex) &&
	* Arrays.equals(a, aFromIndex, aFromIndex + pl, b, bFromIndex, bFromIndex + pl) &&
	* Float.compare(a[aFromIndex + pl], b[bFromIndex + pl]) != 0
	* }</pre>
	* Note that a common prefix length of {@code 0} indicates that the first
	* elements from each array mismatch.
	*
	* <p>Two non-{@code null} arrays, {@code a} and {@code b} with specified
	* ranges [{@code aFromIndex}, {@code atoIndex}) and
	* [{@code bFromIndex}, {@code btoIndex}) respectively, share a proper
	* prefix if the following expression is true:
	* <pre>{@code
	* (aToIndex - aFromIndex) != (bToIndex - bFromIndex) &&
	* Arrays.equals(a, 0, Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex),
	* b, 0, Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex))
	* }</pre>
	*
	* @param a the first array to be tested for a mismatch
	* @param aFromIndex the index (inclusive) of the first element in the
	* first array to be tested
	* @param aToIndex the index (exclusive) of the last element in the
	* first array to be tested
	* @param b the second array to be tested for a mismatch
	* @param bFromIndex the index (inclusive) of the first element in the
	* second array to be tested
	* @param bToIndex the index (exclusive) of the last element in the
	* second array to be tested
	* @return the relative index of the first mismatch between the two arrays
	* over the specified ranges, otherwise {@code -1}.
	* @throws IllegalArgumentException
	* if {@code aFromIndex > aToIndex} or
	* if {@code bFromIndex > bToIndex}
	* @throws ArrayIndexOutOfBoundsException
	* if {@code aFromIndex < 0 or aToIndex > a.length} or
	* if {@code bFromIndex < 0 or bToIndex > b.length}
	* @throws NullPointerException
	* if either array is {@code null}
	* @since 9
	*/
	public static int mismatch(float[] a, int aFromIndex, int aToIndex,
	float[] b, int bFromIndex, int bToIndex) {
	rangeCheck(a.length, aFromIndex, aToIndex);
	rangeCheck(b.length, bFromIndex, bToIndex);

	int aLength = aToIndex - aFromIndex;
	int bLength = bToIndex - bFromIndex;
	int length = Math.min(aLength, bLength);
	int i = ArraysSupport.mismatch(a, aFromIndex,
	b, bFromIndex,
	length);
	return (i < 0 && aLength != bLength) ? length : i;
	}

	// Mismatch double

	/**
	* Finds and returns the index of the first mismatch between two
	* {@code double} arrays, otherwise return -1 if no mismatch is found. The
	* index will be in the range of 0 (inclusive) up to the length (inclusive)
	* of the smaller array.
	*
	* <p>If the two arrays share a common prefix then the returned index is the
	* length of the common prefix and it follows that there is a mismatch
	* between the two elements at that index within the respective arrays.
	* If one array is a proper prefix of the other then the returned index is
	* the length of the smaller array and it follows that the index is only
	* valid for the larger array.
	* Otherwise, there is no mismatch.
	*
	* <p>Two non-{@code null} arrays, {@code a} and {@code b}, share a common
	* prefix of length {@code pl} if the following expression is true:
	* <pre>{@code
	* pl >= 0 &&
	* pl < Math.min(a.length, b.length) &&
	* Arrays.equals(a, 0, pl, b, 0, pl) &&
	* Double.compare(a[pl], b[pl]) != 0
	* }</pre>
	* Note that a common prefix length of {@code 0} indicates that the first
	* elements from each array mismatch.
	*
	* <p>Two non-{@code null} arrays, {@code a} and {@code b}, share a proper
	* prefix if the following expression is true:
	* <pre>{@code
	* a.length != b.length &&
	* Arrays.equals(a, 0, Math.min(a.length, b.length),
	* b, 0, Math.min(a.length, b.length))
	* }</pre>
	*
	* @param a the first array to be tested for a mismatch
	* @param b the second array to be tested for a mismatch
	* @return the index of the first mismatch between the two arrays,
	* otherwise {@code -1}.
	* @throws NullPointerException
	* if either array is {@code null}
	* @since 9
	*/
	public static int mismatch(double[] a, double[] b) {
	int length = Math.min(a.length, b.length); // Check null array refs
	if (a == b)
	return -1;

	int i = ArraysSupport.mismatch(a, b, length);
	return (i < 0 && a.length != b.length) ? length : i;
	}

	/**
	* Finds and returns the relative index of the first mismatch between two
	* {@code double} arrays over the specified ranges, otherwise return -1 if
	* no mismatch is found. The index will be in the range of 0 (inclusive) up
	* to the length (inclusive) of the smaller range.
	*
	* <p>If the two arrays, over the specified ranges, share a common prefix
	* then the returned relative index is the length of the common prefix and
	* it follows that there is a mismatch between the two elements at that
	* relative index within the respective arrays.
	* If one array is a proper prefix of the other, over the specified ranges,
	* then the returned relative index is the length of the smaller range and
	* it follows that the relative index is only valid for the array with the
	* larger range.
	* Otherwise, there is no mismatch.
	*
	* <p>Two non-{@code null} arrays, {@code a} and {@code b} with specified
	* ranges [{@code aFromIndex}, {@code atoIndex}) and
	* [{@code bFromIndex}, {@code btoIndex}) respectively, share a common
	* prefix of length {@code pl} if the following expression is true:
	* <pre>{@code
	* pl >= 0 &&
	* pl < Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex) &&
	* Arrays.equals(a, aFromIndex, aFromIndex + pl, b, bFromIndex, bFromIndex + pl) &&
	* Double.compare(a[aFromIndex + pl], b[bFromIndex + pl]) != 0
	* }</pre>
	* Note that a common prefix length of {@code 0} indicates that the first
	* elements from each array mismatch.
	*
	* <p>Two non-{@code null} arrays, {@code a} and {@code b} with specified
	* ranges [{@code aFromIndex}, {@code atoIndex}) and
	* [{@code bFromIndex}, {@code btoIndex}) respectively, share a proper
	* prefix if the following expression is true:
	* <pre>{@code
	* (aToIndex - aFromIndex) != (bToIndex - bFromIndex) &&
	* Arrays.equals(a, 0, Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex),
	* b, 0, Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex))
	* }</pre>
	*
	* @param a the first array to be tested for a mismatch
	* @param aFromIndex the index (inclusive) of the first element in the
	* first array to be tested
	* @param aToIndex the index (exclusive) of the last element in the
	* first array to be tested
	* @param b the second array to be tested for a mismatch
	* @param bFromIndex the index (inclusive) of the first element in the
	* second array to be tested
	* @param bToIndex the index (exclusive) of the last element in the
	* second array to be tested
	* @return the relative index of the first mismatch between the two arrays
	* over the specified ranges, otherwise {@code -1}.
	* @throws IllegalArgumentException
	* if {@code aFromIndex > aToIndex} or
	* if {@code bFromIndex > bToIndex}
	* @throws ArrayIndexOutOfBoundsException
	* if {@code aFromIndex < 0 or aToIndex > a.length} or
	* if {@code bFromIndex < 0 or bToIndex > b.length}
	* @throws NullPointerException
	* if either array is {@code null}
	* @since 9
	*/
	public static int mismatch(double[] a, int aFromIndex, int aToIndex,
	double[] b, int bFromIndex, int bToIndex) {
	rangeCheck(a.length, aFromIndex, aToIndex);
	rangeCheck(b.length, bFromIndex, bToIndex);

	int aLength = aToIndex - aFromIndex;
	int bLength = bToIndex - bFromIndex;
	int length = Math.min(aLength, bLength);
	int i = ArraysSupport.mismatch(a, aFromIndex,
	b, bFromIndex,
	length);
	return (i < 0 && aLength != bLength) ? length : i;
	}

	// Mismatch objects

	/**
	* Finds and returns the index of the first mismatch between two
	* {@code Object} arrays, otherwise return -1 if no mismatch is found. The
	* index will be in the range of 0 (inclusive) up to the length (inclusive)
	* of the smaller array.
	*
	* <p>If the two arrays share a common prefix then the returned index is the
	* length of the common prefix and it follows that there is a mismatch
	* between the two elements at that index within the respective arrays.
	* If one array is a proper prefix of the other then the returned index is
	* the length of the smaller array and it follows that the index is only
	* valid for the larger array.
	* Otherwise, there is no mismatch.
	*
	* <p>Two non-{@code null} arrays, {@code a} and {@code b}, share a common
	* prefix of length {@code pl} if the following expression is true:
	* <pre>{@code
	* pl >= 0 &&
	* pl < Math.min(a.length, b.length) &&
	* Arrays.equals(a, 0, pl, b, 0, pl) &&
	* !Objects.equals(a[pl], b[pl])
	* }</pre>
	* Note that a common prefix length of {@code 0} indicates that the first
	* elements from each array mismatch.
	*
	* <p>Two non-{@code null} arrays, {@code a} and {@code b}, share a proper
	* prefix if the following expression is true:
	* <pre>{@code
	* a.length != b.length &&
	* Arrays.equals(a, 0, Math.min(a.length, b.length),
	* b, 0, Math.min(a.length, b.length))
	* }</pre>
	*
	* @param a the first array to be tested for a mismatch
	* @param b the second array to be tested for a mismatch
	* @return the index of the first mismatch between the two arrays,
	* otherwise {@code -1}.
	* @throws NullPointerException
	* if either array is {@code null}
	* @since 9
	*/
	public static int mismatch(Object[] a, Object[] b) {
	int length = Math.min(a.length, b.length); // Check null array refs
	if (a == b)
	return -1;

	for (int i = 0; i < length; i++) {
	if (!Objects.equals(a[i], b[i]))
	return i;
	}

	return a.length != b.length ? length : -1;
	}

	/**
	* Finds and returns the relative index of the first mismatch between two
	* {@code Object} arrays over the specified ranges, otherwise return -1 if
	* no mismatch is found. The index will be in the range of 0 (inclusive) up
	* to the length (inclusive) of the smaller range.
	*
	* <p>If the two arrays, over the specified ranges, share a common prefix
	* then the returned relative index is the length of the common prefix and
	* it follows that there is a mismatch between the two elements at that
	* relative index within the respective arrays.
	* If one array is a proper prefix of the other, over the specified ranges,
	* then the returned relative index is the length of the smaller range and
	* it follows that the relative index is only valid for the array with the
	* larger range.
	* Otherwise, there is no mismatch.
	*
	* <p>Two non-{@code null} arrays, {@code a} and {@code b} with specified
	* ranges [{@code aFromIndex}, {@code atoIndex}) and
	* [{@code bFromIndex}, {@code btoIndex}) respectively, share a common
	* prefix of length {@code pl} if the following expression is true:
	* <pre>{@code
	* pl >= 0 &&
	* pl < Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex) &&
	* Arrays.equals(a, aFromIndex, aFromIndex + pl, b, bFromIndex, bFromIndex + pl) &&
	* !Objects.equals(a[aFromIndex + pl], b[bFromIndex + pl])
	* }</pre>
	* Note that a common prefix length of {@code 0} indicates that the first
	* elements from each array mismatch.
	*
	* <p>Two non-{@code null} arrays, {@code a} and {@code b} with specified
	* ranges [{@code aFromIndex}, {@code atoIndex}) and
	* [{@code bFromIndex}, {@code btoIndex}) respectively, share a proper
	* prefix if the following expression is true:
	* <pre>{@code
	* (aToIndex - aFromIndex) != (bToIndex - bFromIndex) &&
	* Arrays.equals(a, 0, Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex),
	* b, 0, Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex))
	* }</pre>
	*
	* @param a the first array to be tested for a mismatch
	* @param aFromIndex the index (inclusive) of the first element in the
	* first array to be tested
	* @param aToIndex the index (exclusive) of the last element in the
	* first array to be tested
	* @param b the second array to be tested for a mismatch
	* @param bFromIndex the index (inclusive) of the first element in the
	* second array to be tested
	* @param bToIndex the index (exclusive) of the last element in the
	* second array to be tested
	* @return the relative index of the first mismatch between the two arrays
	* over the specified ranges, otherwise {@code -1}.
	* @throws IllegalArgumentException
	* if {@code aFromIndex > aToIndex} or
	* if {@code bFromIndex > bToIndex}
	* @throws ArrayIndexOutOfBoundsException
	* if {@code aFromIndex < 0 or aToIndex > a.length} or
	* if {@code bFromIndex < 0 or bToIndex > b.length}
	* @throws NullPointerException
	* if either array is {@code null}
	* @since 9
	*/
	public static int mismatch(
	Object[] a, int aFromIndex, int aToIndex,
	Object[] b, int bFromIndex, int bToIndex) {
	rangeCheck(a.length, aFromIndex, aToIndex);
	rangeCheck(b.length, bFromIndex, bToIndex);

	int aLength = aToIndex - aFromIndex;
	int bLength = bToIndex - bFromIndex;
	int length = Math.min(aLength, bLength);
	for (int i = 0; i < length; i++) {
	if (!Objects.equals(a[aFromIndex++], b[bFromIndex++]))
	return i;
	}

	return aLength != bLength ? length : -1;
	}

	/**
	* Finds and returns the index of the first mismatch between two
	* {@code Object} arrays, otherwise return -1 if no mismatch is found.
	* The index will be in the range of 0 (inclusive) up to the length
	* (inclusive) of the smaller array.
	*
	* <p>The specified comparator is used to determine if two array elements
	* from the each array are not equal.
	*
	* <p>If the two arrays share a common prefix then the returned index is the
	* length of the common prefix and it follows that there is a mismatch
	* between the two elements at that index within the respective arrays.
	* If one array is a proper prefix of the other then the returned index is
	* the length of the smaller array and it follows that the index is only
	* valid for the larger array.
	* Otherwise, there is no mismatch.
	*
	* <p>Two non-{@code null} arrays, {@code a} and {@code b}, share a common
	* prefix of length {@code pl} if the following expression is true:
	* <pre>{@code
	* pl >= 0 &&
	* pl < Math.min(a.length, b.length) &&
	* Arrays.equals(a, 0, pl, b, 0, pl, cmp)
	* cmp.compare(a[pl], b[pl]) != 0
	* }</pre>
	* Note that a common prefix length of {@code 0} indicates that the first
	* elements from each array mismatch.
	*
	* <p>Two non-{@code null} arrays, {@code a} and {@code b}, share a proper
	* prefix if the following expression is true:
	* <pre>{@code
	* a.length != b.length &&
	* Arrays.equals(a, 0, Math.min(a.length, b.length),
	* b, 0, Math.min(a.length, b.length),
	* cmp)
	* }</pre>
	*
	* @param a the first array to be tested for a mismatch
	* @param b the second array to be tested for a mismatch
	* @param cmp the comparator to compare array elements
	* @param <T> the type of array elements
	* @return the index of the first mismatch between the two arrays,
	* otherwise {@code -1}.
	* @throws NullPointerException
	* if either array or the comparator is {@code null}
	* @since 9
	*/
	public static <T> int mismatch(T[] a, T[] b, Comparator<? super T> cmp) {
	Objects.requireNonNull(cmp);
	int length = Math.min(a.length, b.length); // Check null array refs
	if (a == b)
	return -1;

	for (int i = 0; i < length; i++) {
	T oa = a[i];
	T ob = b[i];
	if (oa != ob) {
	// Null-value comparison is deferred to the comparator
	int v = cmp.compare(oa, ob);
	if (v != 0) {
	return i;
	}
	}
	}

	return a.length != b.length ? length : -1;
	}

	/**
	* Finds and returns the relative index of the first mismatch between two
	* {@code Object} arrays over the specified ranges, otherwise return -1 if
	* no mismatch is found. The index will be in the range of 0 (inclusive) up
	* to the length (inclusive) of the smaller range.
	*
	* <p>If the two arrays, over the specified ranges, share a common prefix
	* then the returned relative index is the length of the common prefix and
	* it follows that there is a mismatch between the two elements at that
	* relative index within the respective arrays.
	* If one array is a proper prefix of the other, over the specified ranges,
	* then the returned relative index is the length of the smaller range and
	* it follows that the relative index is only valid for the array with the
	* larger range.
	* Otherwise, there is no mismatch.
	*
	* <p>Two non-{@code null} arrays, {@code a} and {@code b} with specified
	* ranges [{@code aFromIndex}, {@code atoIndex}) and
	* [{@code bFromIndex}, {@code btoIndex}) respectively, share a common
	* prefix of length {@code pl} if the following expression is true:
	* <pre>{@code
	* pl >= 0 &&
	* pl < Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex) &&
	* Arrays.equals(a, aFromIndex, aFromIndex + pl, b, bFromIndex, bFromIndex + pl, cmp) &&
	* cmp.compare(a[aFromIndex + pl], b[bFromIndex + pl]) != 0
	* }</pre>
	* Note that a common prefix length of {@code 0} indicates that the first
	* elements from each array mismatch.
	*
	* <p>Two non-{@code null} arrays, {@code a} and {@code b} with specified
	* ranges [{@code aFromIndex}, {@code atoIndex}) and
	* [{@code bFromIndex}, {@code btoIndex}) respectively, share a proper
	* prefix if the following expression is true:
	* <pre>{@code
	* (aToIndex - aFromIndex) != (bToIndex - bFromIndex) &&
	* Arrays.equals(a, 0, Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex),
	* b, 0, Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex),
	* cmp)
	* }</pre>
	*
	* @param a the first array to be tested for a mismatch
	* @param aFromIndex the index (inclusive) of the first element in the
	* first array to be tested
	* @param aToIndex the index (exclusive) of the last element in the
	* first array to be tested
	* @param b the second array to be tested for a mismatch
	* @param bFromIndex the index (inclusive) of the first element in the
	* second array to be tested
	* @param bToIndex the index (exclusive) of the last element in the
	* second array to be tested
	* @param cmp the comparator to compare array elements
	* @param <T> the type of array elements
	* @return the relative index of the first mismatch between the two arrays
	* over the specified ranges, otherwise {@code -1}.
	* @throws IllegalArgumentException
	* if {@code aFromIndex > aToIndex} or
	* if {@code bFromIndex > bToIndex}
	* @throws ArrayIndexOutOfBoundsException
	* if {@code aFromIndex < 0 or aToIndex > a.length} or
	* if {@code bFromIndex < 0 or bToIndex > b.length}
	* @throws NullPointerException
	* if either array or the comparator is {@code null}
	* @since 9
	*/
	public static <T> int mismatch(
	T[] a, int aFromIndex, int aToIndex,
	T[] b, int bFromIndex, int bToIndex,
	Comparator<? super T> cmp) {
	Objects.requireNonNull(cmp);
	rangeCheck(a.length, aFromIndex, aToIndex);
	rangeCheck(b.length, bFromIndex, bToIndex);

	int aLength = aToIndex - aFromIndex;
	int bLength = bToIndex - bFromIndex;
	int length = Math.min(aLength, bLength);
	for (int i = 0; i < length; i++) {
	T oa = a[aFromIndex++];
	T ob = b[bFromIndex++];
	if (oa != ob) {
	// Null-value comparison is deferred to the comparator
	int v = cmp.compare(oa, ob);
	if (v != 0) {
	return i;
	}
	}
	}

	return aLength != bLength ? length : -1;
	}
	}

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